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Magazine Chapter 27: Q15P (page 1198)
a. Draw three segments of the polymer that is formed from 1,4-polymerization of 1,3-butadiene in which all the double bonds are trans.
b. Draw three segments of the polymer that is formed from 1,2-polymerization of 1,3-butadiene.
Short Answer
a. The three segments of polymer created by 1,4-polymerization of 1,3-butadiene are given below.
b. The three segments of polymer created from 1,2-polymerization of 1,3-butadiene is given below.
Step by step solution
Polymerization of dienes
The treatment of diene with strong acids leads to the creation of polymers. The polymerization of 1,3-butadiene at the C1 and C2 positions create polyethylene.
The polymerization at the C1 and C4 positions generate cis-polybutadiene, trans-polybutadiene, or a mixed polymer.
Drawing the three segments of the polymer formed from 1,4-polymerization of 1,3-butadiene and three segments of the polymer formed from 1,2-polymerization of 1,3-butadiene
a. In 1,4-polymerization of 1,3-butadiene, one C-1 of 1,3-butadiene connects to the fourth carbon of the other 1,3-butadiene. Hence, all the double bonds are trans.
The three segments of polymer created by 1,4-polymerization of 1,3-butadiene are given below.
Segments of polymer created by 1,4-polymerization of 1,3-butadiene
b. In 1,2-polymerization of 1,3-butadiene, the first carbon of 1,3-butadiene links to the second carbon of the other 1,3-butadiene.
The three segments of polymer created from 1,2-polymerization of 1,3-butadiene are given below.
Segments of polymer created from 1,2-polymerization of 1,3-butadiene
The three segments of the polymer formed from 1,4-polymerization of 1,3-butadiene and three segments formed from 1,2-polymerization of 1,3-butadiene are drawn.
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