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Chapter 9: Q82P (page 452)

Fill in the squares in the following chemical equations:

Short Answer

Expert verified

1. It is a two step reaction.

2. In this carbocation is formed.

3. In this negative ion will attack from the side where there is less number of bulkier groups.

4. As the carbocation intermediate is formed so the stability order 3掳 carbocation>2掳 carbocation>1掳 carbocation

Step by step solution

01

How SN1 reaction proceed

1. It is a two step reaction.

2. In this carbocation is formed.

3. In this negative ion will attack from the side where there is less number of bulkier groups.

4. As the carbocation intermediate is formed so the stability order 3掳 carbocation>2掳 carbocation>1掳 carbocation

02

Final answer

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Most popular questions from this chapter

Propose a mechanism for the following reaction:

Which of the following hexachlorocyclohexanes is the least reactive in an E2 reaction?

Rank the following alkyl halides from most reactive to least reactive in an SN1 reaction:

2-bromo-2-methylpentane, 2-chloro-2-methylpentane, 3-chloropentane, and 2-iodo-2-methylpentane.

a. Draw the structures of the products obtained from the reaction of each enantiomer of cis-1-chloro-2-isopropylcyclopentane with sodium methoxide in methanol.

b. Are all the products optically active?

c. How would the products differ if the starting material were the trans isomer? Are these products optically active?

d. Will the cis enantiomers or the trans enantiomers form substitution products more rapidly?

e. Will the cis enantiomers or the trans enantiomers form elimination products more rapidly?

Four alkenes are formed from the E1 reaction of 3-bromo-2,3-dimethylpentane and methoxide ion. Draw the structures of the alkenes and rank them according to the amount that would be formed.
See all solutions

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