Chapter 18: Q53P (page 915)
If anisole is allowed to sit in that contains a small amount of, what products are formed?
Short Answer
The product formed when anisole is placed in is,

/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 18: Q53P (page 915)
If anisole is allowed to sit in that contains a small amount of, what products are formed?
The product formed when anisole is placed in is,

All the tools & learning materials you need for study success - in one app.
Get started for free
Show the mechanism for the generation of the acylium ion if an acid anhydride is used instead of an acyl chloride for the source of the acylium ion.
Question: The pKa values of a few ortho-, meta-, and para-substituted benzoic acids are shown below:

The relative pKa values depend on the substituent. For chloro-substituted benzoic acids, the ortho isomer is the most acidic and the para isomer is the least
acidic; for nitro-substituted benzoic acids, the ortho isomer is the most acidic and the meta isomer is the least acidic; and for amino-substituted benzoic acids, the meta isomer is the most acidic and the ortho isomer is the least acidic. Explain these relative acidities.
a. Cl: ortho > meta > para
b. NO2: ortho > para > meta
c. NH2: meta > para > ortho
Show how the following compounds can be synthesized from benzene:
a. p-nitrobenzoic acid
b. m-bromophenol
c. o-chlorophenol
d. m-methylnitrobenzene
e. p-methylbenzonitrile
f. m-chlorobenzaldehyde
Draw resonance contributors for the carbanion that would be formed if meta-chloronitrobenzene were to react with hydroxide ion. Why doesn’t the reaction occur?
Explain why fluorobenzene is more reactive than chlorobenzene toward electrophilic aromatic substitution but chloromethyl benzene is more reactive than fluoromethylbenzene.
What do you think about this solution?
We value your feedback to improve our textbook solutions.