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Chapter 8: Q 65P (page 375)

Draw all the products of the following reaction:

Short Answer

Expert verified

Double bond shifts towards positive charge and the carbon having positive charge will form double bond and the adjacent carbon will get double bond likewise then next adjacent double bond attack and positive charge will go on that carbon like this way positive charge will spread on that ring. Where the ring will get positive charge there the OH group will attach.

Step by step solution

01

How will reaction proceed

Double bond shifts towards positive charge and the carbon having positive charge will form double bond and the adjacent carbon will get double bond likewise then next adjacent double bond attack and positive charge will go on that carbon like this way positive charge will spread on that ring. Where the ring will get positive charge there the OH group will attach.

02

Final answer

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Most popular questions from this chapter

Draw the resonance contributors for the following carbocation

Draw resonance contributors for the following ions:

a. When HBr adds to a conjugated diene, what is the rate-determining step?

b. When HBr adds to a conjugated diene, what is the product-determining step?

a) What are the products of the following reaction?

b) How many stereoisomers of each product could be obtained?

Which of the double bonds in zingiberene, the compound responsible for the aroma of ginger, is most reactive in an electrophilic addition reaction with HBr?
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