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Question: Each of the following proposed mechanisms for the free-radical chlorination of methane is wrong. Explain how the experimental evidence disproves each mechanism.

(a)

CI2+³ó±¹â†’C±õ2(anactivatedformofCI2)CI2+CH4→H°ä±ô+°ä±á3Cl(b)CH4+hv→CH3+HCH3+Cl2→CH3Cl+ClCl+H→HCl

Short Answer

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Answer

(a)The mechanism of the reaction requires that one photon of light (hv) must be added for each CH3Cl . The high quantum suggests it to be a chain reaction, but due to the absence of propagation steps, it cannot be a chain reaction.

(b)The energy of light required to break a H-CH3 bond is 435KJ/mol . Again, the energy needed to start the reaction is 242KJ/mol , which is much less than the energy needed to break the bond.

Step by step solution

01

Free radicals

An atom or group of atoms containing odd or unpaired electrons is known as the free radical. The unpaired electron is represented by a single unpaired dot in the formula. Free radicals are electrically neutral. They are highly reactive species formed by homolytic fission of a covalent bond.

02

Steps involved in a free radical chain reaction

In a free-radical chain reaction, free radicals are generally created in the initiation steps. A free radical and a reactant is combined to yield a product and another free radical in the propagation steps. Lastly, the number of free radicals generally decreasesin the termination steps.

03

Explanation

(a) The mechanism of the reaction requires that one photon of light (hv) must be added for each CH3Cl . The high quantum suggests it to be a chain reaction, but due to the absence of propagation steps, it cannot be a chain reaction.

(b) The energy of light required to break H-CH3 a bond is .435KJ/mol Again, the energy needed to start the reaction is242KJ/mol , which is much less than the energy needed to break the bond.

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Most popular questions from this chapter

Question: The bromination of methane proceeds through the following steps:

(a) Draw a complete reaction-energy diagram for this reaction.

(b) Label the rate-limiting step.

(c) Draw the structure of each transition state

(d) Compute the overall value of∆H0for the bromination.

Under certain conditions, the bromination of cyclohexene follows an unusual rate law:

(a) What is the kinetic order with respect to cyclohexene?

(b) What is the kinetic order with respect to bromine?

(c) What is the kinetic order overall?

When a small piece of platinum is added to a mixture of ethene and hydrogen, the following reaction occurs:

Doubling the concentration of hydrogen has no effect on the reaction rate. Doubling the concentration of ethene also has no effect.

(a) What is the kinetic order of this reaction with respect to ethene? With respect to hydrogen? What is the overall order?

(b) Write the unusual rate equation for this reaction.

(c)Explain this strange rate equation, and suggest what one might do to accelerate the reaction.

Question: When ethene is mixed with hydrogen in the presence of a platinum catalyst, hydrogen adds across the double bond to form ethane. At room temperature, the reaction goes to completion. Predict the signs ∆H0and∆S0for this reaction. Explain these signs in terms of bonding and freedom of motion.

The following reaction is a common synthesis used in the organic chemistry laboratory course.

When we double the concentration of methoxide ion (CH3O-) , we find that the reaction rate doubles. When we triple the concentration of 1-bromopropane , we find the reaction rate triples.

(a) What is the order of this reaction with respect to 1-bromopropane? What is the order with respect to methoxide ion? Write the rate equation for this reaction. What is the overall order?

(b) One lab textbook recommends forming the sodium methoxide in methanol solvent, but before adding 1-bromopropane ,it first distills off enough methanol to reduce the mixture to half of its original volume. What difference in rate will we see when we run the reaction (using the same amounts of reagents) in half the volume of solvent?

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