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(a) Draw the structure of the transition state for the second propagation step in the chlorination of methane.

Show whether the transition state is product-like or reactant-like and which of the two partial bonds is stronger.

(b) Repeat for the second propagation step in the bromination of methane.

Short Answer

Expert verified

a)

second propagation step in the chlorination of methane

transition state

The transition state is more reactant-like.

(b)

Step by step solution

01

Free radicals

An atom or group of atoms containing odd or unpaired electron is known as the free radical. The unpaired electron is represented by a single unpaired dot in the formula. Free radicals are electrically neutral. They are highly reactive species formed by homolytic fission of a covalent bond.

02

Propagation

The formation of products with regeneration of reactive species takes place in the propagation step.

03

Transition state or activated complex

The highest energy state in a molecular collision that leads to reaction is the transition state. Transition state is most unstable. The transition state or activated complex gets converted into product molecules. During the formation of this complex, old bonds start breaking and the new bonds start making.

04

Hammond’s postulate

According to Hammond’s postulate, related species which are closer in energy are also closer in structure and the structure of the transition state resembles the structure of the closest stable species.

05

Explanation

(a)

second propagation step in the chlorination of methane

transition state

From Hammond’s postulate, it is known that the transition state in the exothermic chlorination must resemble the reactants more than the products. Hence, the transition state is more reactant-like.

(b)

second propagation step in the bromination of methane

transition state

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Most popular questions from this chapter

In the presence of a small amount of bromine, cyclohexene undergoes the following light-promoted reaction:

(a) Propose a mechanism for this reaction.

(b) Draw the structure of the rate-limiting transition state.

(c) Use Hammond’s postulate to predict which intermediate most closely resembles this transition state.

(d) Explain why cyclohexene reacts with bromine much faster than cyclohexane, which must be heated to react.

Question: Each of the following proposed mechanisms for the free-radical chlorination of methane is wrong. Explain how the experimental evidence disproves each mechanism.

(a)

CI2+³ó±¹â†’C±õ2(anactivatedformofCI2)CI2+CH4→H°ä±ô+°ä±á3Cl(b)CH4+hv→CH3+HCH3+Cl2→CH3Cl+ClCl+H→HCl

When a small piece of platinum is added to a mixture of ethene and hydrogen, the following reaction occurs:

Doubling the concentration of hydrogen has no effect on the reaction rate. Doubling the concentration of ethene also has no effect.

(a) What is the kinetic order of this reaction with respect to ethene? With respect to hydrogen? What is the overall order?

(b) Write the unusual rate equation for this reaction.

(c)Explain this strange rate equation, and suggest what one might do to accelerate the reaction.

Question: (a) Write the propagation steps leading to the formation of dichloromethane (CH2Cl2).

(b) Explain why free-radical halogenation usually gives mixture of products.

(c) How could an industrial plant control the proportions of methane and chlorine to favor production of CCl4? To favor production of CH3Cl?

Label each hydrogen atom in the following compound as primary (1o), secondary (2o), or tertiary (3o)

(a)

(b)

(c)

(d)

e)

(f)

See all solutions

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