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Question: (a) Write the propagation steps leading to the formation of dichloromethane (CH2Cl2).

(b) Explain why free-radical halogenation usually gives mixture of products.

(c) How could an industrial plant control the proportions of methane and chlorine to favor production of CCl4? To favor production of CH3Cl?

Short Answer

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Answer

a

(b) A halogen atom is substituted for a hydrogen atom in free-radical halogenation. A different compound is produced from the first substitution of a hydrogen atom. The hydrogen atoms left unreacted can compete for halogen atoms that are available. For example, in the chlorination of methane, different substitution products are formed such as CH4,CH3Cl,CH2CI2, CHCI3, and CCI4. Hence, free-radical halogenation usually gives a mixture of products.

(c)The amount ofCI2 (chlorine) reacted with CH4 (methane) should be in excess for favoring the production ofCCI4 . This is to make certain that the reaction progresses so that all the C-H bonds are replaced with C-l bonds.

The amount ofCI2 (chlorine) reacted withCH4 (methane) should be less to favor the production of . This is to make certain that the reaction progresses so that all the chlorine atoms would more likely react with methane to formCH3Cl and not with CH3Cl to form CH2CI2 .

Step by step solution

01

Free radicals

An atom or group of atoms containing odd or unpaired electrons is known as the free radical. The unpaired electron is represented by a single unpaired dot in the formula. Free radicals are electrically neutral. They are highly reactive species formed by homolytic fission of a covalent bond.

02

Propagation

The formation of products with the regeneration of reactive species takes place in the propagation step.

03

Explanation

(a) Formation of reactive intermediates takes place first in the initiation step.

Initiation

In the first step of propagation, a radical reacts to generate another radical.

Propagation

In the second step, chloromethyl radical reacts with CI2 to generate the product and chlorine radical.

Chloromethyl radical reacts withCI2

(b) A halogen atom is substituted for a hydrogen atom in free-radical halogenation. A different compound is produced from the first substitution of a hydrogen atom. The hydrogen atoms left unreacted can compete for halogen atoms that are available. For example, in the chlorination of methane, different substitution products are formed such as CH4,CH3Cl,CH2CI2, CHCI3, and CCI4. Hence, free-radical halogenation usually gives a mixture of products.

(c)The amount ofCI2 (chlorine) reacted with CH4 (methane) should be in excess for favoring the production ofCCI4 . This is to make certain that the reaction progresses so that all the C-H bonds are replaced with C-l bonds.

The amount ofCI2 (chlorine) reacted with CH4 (methane) should be less to favor the production of . This is to make certain that the reaction progresses so that all the chlorine atoms would more likely react with methane to formCH3Cl and not with CH3Cl to form CH2CI2 .

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Most popular questions from this chapter

The following reaction is a common synthesis used in the organic chemistry laboratory course.

When we double the concentration of methoxide ion (CH3O-) , we find that the reaction rate doubles. When we triple the concentration of 1-bromopropane , we find the reaction rate triples.

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