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Chapter 7: Q3P. (page 332)

Question: Draw five more compounds of formulaC4H6NOCl.

Short Answer

Expert verified

Answer:

The five compounds with the given formula are as follows:

Step by step solution

01

Figure out the total number of atoms

In the given formula there are 4 carbon atoms, 6 hydrogen atoms, 1 nitrogen atom, 1 oxygen atom and 1 chlorine atom.

02

Draw the compounds with the given formula

The following are the compounds that can be drawn with the given formula.

Five compounds of formula C4H6NOCl.

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Most popular questions from this chapter

Predict the products of E1 elimination of the following compounds. Label the major products

When the following stereoisomer of 2-bromo-1,3-dimethylcyclohexane is treated with sodium methoxide, no E2 reaction is observed. Explain why this compound cannot undergo the E2 reaction in the chair conformation.

Predict the elimination products of the following reactions and label the major products.

  1. Cis-1-bromo-2-methylcyclohexane +in
  2. Trans-1-bromo-2-methylcyclohexane +in

Propose mechanisms for the following reactions. Additional products may be formed, but your mechanism only needs to explain the products shown.

When 2-bromo-3-phenylbutane is treated with sodium methoxide, two alkenes result (by E2 elimination). The Zaitsev product predominates.

  1. Draw the reaction, showing the major and minor products.
  2. When one pure stereoisomer of 2-bromo-3-phenylbutane reacts, one pure stereoisomer of the major product results. For example, when (2R,3R)-2-bromo-3-phenylbutane reacts, the product is the stereoisomer with the methyl group cis. Use your models to draw a Newmanprojection of the transition state to show why this stereospecificity is observed.
  3. Use a Newman projection of the transition state to predict the major product of elimination of (2S,3R)-2-bromo-3-phenylbutane.
  4. Predict the major product from elimination of (2S,3S)-2-bromo-3-phenylbutane. This prediction can be made without drawing any structures, by considering the results in part (b).
See all solutions

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