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Question: Rank the following isomers in order of increasing boiling point, and explain the reasons for your order of ranking.

Short Answer

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Answer

The order of increasing boiling point is,

Step by step solution

01

Boiling point

The boiling point of compounds is dependent on the molecular weight, intermolecular attractive forces and family of a compound from which it belongs.With an increase in molar mass, the boiling point increases and the more the hydrogen bonding, the higher the boiling point.

02

The rank of isomers in order of increasing boiling point 

  • The given isomers are n-pentanol, ethyl acetate and valeric acid. These have different functional groups.
  • The carboxylic acid group (-COOH) is present in valeric acid.
  • In n-pentanol, the alcohol group (-OH) is present.
  • In ethyl acetate, the ester group (-COO) is present.

The boiling point for ethyl acetate (ester-containing compound) is the lowest (770C) because ester does not form hydrogen bonds. Then comes n-pentanol (alcohol-containing compound), which forms hydrogen bonds, so it has a higher boiling point (1380C) than ethyl acetate. At last, valeric acid (carboxylic acid-containing compound) forms two hydrogen bonds and boils in the form of a dimer. So, it has the highest boiling point among all (1860C)). Thus, the order of increasing boiling point is,

Order of increasing boiling point

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Most popular questions from this chapter

Substituent effects: resonance and induction.

(a)When the methoxy group is in the meta position inB, is the acid stronger or weaker than inA? Is the methoxy group in the meta position electron-donating or withdrawing?

(b)When the methoxy group is in the para position inC, is the acid stronger or weaker than inA? Is the methoxy group in the para position electron-donating or withdrawing?

(c)How can this apparent contradiction be explained? Which effect is stronger for methoxy?

(d)When the fluoro group is in the meta position inE, is the acid stronger or weaker than inD? Is the fluoro group in the meta position electron-donating or withdrawing?

(e)When the fluoro group is in the para position inF, is the acid stronger or weaker than inD? Is the fluoro group in the para position electron-donating or withdrawing?

(f)Compare the results of the fluoro group with those of the above methoxy group. What must be different about the relative strength of the resonance and inductive effects for fluoro compared with methoxy?

(a)Hydrogen peroxide (HOOH) has a pKa of 11.6, making it roughly 10,000 times as strong an acid as water (pKa = 15.7). Explain why H2O2is a stronger acid than H2O.

(b) In contrast to part (a), peroxyacetic acid (pKa = 8.2) is a much weakeracid than acetic acid (pka = 4.74) . Explain why peroxyacetic acid is a weaker acid than acetic acid.

(c) Peroxyacetic acid (bp = 105° C) has a lower boiling point than acetic acid (bp = 118° C) , even though peroxyacetic acid has a higher molecular weight. Explain why peroxyacetic acid is more volatile than acetic acid.

Consider the following reaction-energy diagram.

(a) Label the reactants and the products. Label the activation energy for the first step and the second step.

(b) Is the overall reaction endothermic or exothermic? What is the sign of ?

(c) Which points in the curve correspond to intermediates? Which correspond to transition states?

(d) Label the transition state of the rate-limiting step. Does its structure resemble the reactants, the products, or an intermediate?

Show how you would accomplish the following multistep syntheses using the indicated starting material and any necessary reagents.

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Question. A student adds NBS to a solution of 1-methylcyclohexene and irradiates the mixture with a sunlamp until all the NBS has reacted. After a careful distillation, the product mixture contains two major products of formula.

  1. Draw the resonance forms of the three possible allylic free radical intermediates.
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  3. Draw the products obtained from each free-radical intermediate.
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