/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q-24-45P There are many methods for activ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

There are many methods for activating a carboxylic acid in preparation for coupling with an amine. The following method converts the acid to an N-hydroxysuccinimide (NHS) ester.

(a) Explain why an NHS ester is much more reactive than a simple alkyl ester.

(b) Propose a mechanism for the reaction shown.

(c) Propose a mechanism for the reaction of the NHS ester with an amine, R-NH2

Short Answer

Expert verified

(a) An NHS ester is much more reactive than an alkyl ester because the anion of NHS ester R2NO-has an electron withdrawing group on oxygen anion, thereby distributing the negative charge over two atoms instead of one and we know that delocalisation of charge brings stability.

Anion of NHS ester

(Stable)

(b)

(c)

Step by step solution

01

Step-1. Explanation of part (a):

Anion of NHS ester acts as a leaving group and stabilisation of anion is the major factor in determining the ability of leaving group. The anion of NHS is stable and hence NHS ester is more reactive than alkyl ester. R2NO-, anion of NHS ester, is stable due to presence of electron withdrawing group which is attached with oxygen anion and stabilises the negative charge. Also, the negative charge is distributed over two atoms instead of just one atom as in alkyl ester anion.

Anion of NHS ester

(Stable)

02

Step-2. Explanation of part (b):

The anion of NHS ester is abbreviated as O-succ. In the mechanism, the carboxylate ion acts as a nucleophile and attacks at the carbonyl carbon of the given reactant which leads to formation of an intermediate and anion of NHS ester is stable and acts as a good leaving group in next step. NHS trifluoroacetate activates the carboxylic acid through a mixed anhydride to form an ester under mild conditions. Also, anion of NHS ester acts as a nucleophile and attacks at carbonyl carbon of the anhydride which leads to formation of another intermediate and after that, when leaving group leaves, we get our required product.

Mechanism of the given reaction

03

Step-3. Explanation of part (c):

Amine acts as a nucleophile and attacks at the carbonyl carbon of the NHS ester which leads to the formation of an intermediate and NHS anion acts as a good leaving group in next step. Nitrogen stabilises the positive charge on itself by losing proton attached to it and we get our required product.

Mechanism of NHS ester with amine

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Peptides often have functional groups other than free amino groups at the N terminus and other than carboxyl groups at the C terminus.

(a) A tetrapeptide is hydrolyzed by heating with 6 M, and the hydrolysate is found to contain Ala, Phe, Val, and Glu. When the hydrolysate is neutralized, the odor of ammonia is detected. Explain where this ammonia might have been incorporated in the original peptide.

(b) The tripeptide thyrotropic hormone releasing factor(TRF) has the full name pyroglutamylhistidylprolinamide. The structure appears here. Explain the functional groups at the N terminus and at the C terminus.

(c)On acidic hydrolysis, an unknown pentapeptide gives glycine, alanine, valine, leucine and isoleucine. No odor of ammonia is detected when the hydrolysate is neutralized. Reaction with phenyl isothiocyanate followed by mild hydrolysis gives nophenylthiohydantoin derivative. Incubation with carboxypeptidase has no effect. Explain these findings.

The herbicide glyphosate(Roundup) kills plants by inhibiting an enzyme needed for synthesis of phenylalanine. Deprived of phenylalanine, the plant cannot make the proteins it needs, and it gradually weakens and dies. Although a small amount of glyphosate is deadly to a plant, its human toxicity is quite low. Suggest why this powerful herbicide has little effect on humans.

Most naturally occurring amino acids have chiral centers (the asymmetric α carbon atoms) that are named (S) by the Cahn-Ingold-Prelog convention (Section 5-3). The common naturally occurring form of cysteine has a chiral center that is named (R), however.

(a) What is the relationship between (R)-Cysteine and (S)-alanine? Do they have the opposite three-dimensional configuration (as the names might suggest) or the same configuration?

(b) (S)-Alanine is an L-amino acid (Figure 24-2). Is (R)-cysteine a D-amino acid or an L-amino acid?

Show how solid-phase peptide synthesis would be used to make Ile-Gly-Asn.

Complete hydrolysis of an unknown basic decapeptide gives Gly, Ala, Leu, Ile, Phe, Tyr, Glu, Arg, Lys, and Ser. Terminal residue analysis shows that the N terminus is Ala, and the C terminus is Ile. Incubation of the decapeptide with chymotrypsin gives two tripeptides, A and B, and a tetrapeptide, C. Amino acid analysis shows that peptide A contains Gly, Glu, Tyr, and; peptide B contains Ala, Phe, and Lys; and peptide C contains Leu, Ile, Ser, and Arg.Terminal residue analysis gives the following results.

Incubation of the decapeptide with trypsin gives a dipeptide D, a pentapeptide E, and a tripeptide F. Terminal residue analysis of F shows that the N terminus is Ser and the C terminus is Ile. Propose a structure for the decapeptide and for fragments A through F.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.