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Macrolide antibiotics all have large rings (macrocycle) in which an ester makes the ring; a cyclic ester is termed a lactone. One example is erythromycin A, first isolated from soil bacteria in the 1950鈥檚. Over time, some pathogenic bacteria have developed resistance to erythromycin by evolving an enzymatic mechanism to cleave the macrocycle at the ketone. To counter this resistance, chemists modified the erythromycin structure to replace the ketone with an amine that the bacteria could not detoxify. This modified antibiotic, azithromycin, trade name Zithromax庐, is one of the most prescribed drugs in the world for respiratory infections.

(a) Identify the lactone group in each structure that merits the classification as macrolides.

(b) Two groups are circled. What type of functional group are they? Explain

(c) Identify the ketone in erythromycin targeted by bacteria as the site for detoxification.

(d) Identify the amine in azithromycin. What type of amine is it?

(e) From what you know about the reactivity of ketones and amines, why was an amine a good choice to be the 鈥渃hemical opposite of a ketone鈥?

Short Answer

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(b)

(e) A ketone is an electrophile, meaning that it will be attacked by a nucleophile. Presumably, bacteria used an enzyme with a nucleophile at its active site to detoxify erythromycin. In contrast, the amine in azithromycin is nucleophile and will be unaffected by another nucleophile, rendering the detoxifying enzyme useless.

Step by step solution

01

Step-1. Explanation of part (a): 

A lactone is an ester in which the functional group of the ester has become part of a ring structure with carbon atoms. Examples of lactones are macrolides, kavalactones etc. Lactones are often used as flavors and fragrances.

02

Step-2. Explanation of part (b):

An acetal is a functional group in which carbon is attached by single bonds to ether oxygen and two carbons or hydrogens. Formation of acetal occurs when hydroxyl group of a hemiacetal becomes protonated and is lost as water. Both circled groups shown are acetals. One carbon bonded to two groups, one carbon and one hydrogen.

Acetal groups are squared out as shown

03

Step-3. Explanation of part (c) and (d):

Ketones are organic compounds which incorporate carbonyl functional group and the carbon atom of this group has remaining bonds that may be occupied by alkyl or aryl substituents. Tertiary amine is an amine in which the nitrogen atom is directly bonded to three carbons of any hybridization which cannot be carbonyl group carbons.

Depiction of ketonic and tertiary amine functional group in erythromycin and azithromycin respectively

04

Step-4. Explanation of part (e):

A ketone is an electrophile, meaning that it will be attacked by a nucleophile. Presumably, bacteria used an enzyme with a nucleophile at its active site to detoxify erythromycin. In contrast, the amine in azithromycin is nucleophile and will be unaffected by another nucleophile, rendering the detoxifying enzyme useless.

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Most popular questions from this chapter

Reductive amination of aldehydes and ketones is a versatile method for attaching alkyl groups to amines, but the alkyl group is restricted to a 1 0or 20carbon by this method. Prof. Phil Baran of Scripps Research Institute has reported (Science, 2015, 348(6237), 886-891) a novel way to reduce an aromatic nitro group and add the resulting amine to an alkene so that the aromatic amine is bonded to a carbon- all in a continuous sequence of reactions. For example:

Predict the products using these starting materials, all of which are reported in this paper.

Propose a mechanism for nitration of pyridine at the 4-position, and show why this orientation is not observed.

A compound of formula C11H16N2gives the IR, 1HNMR, and 13CNMR spectra shown. The proton NMR peak at未 2.0disappears on shaking with D2O. Propose a structure for this compound, and show how your structure accounts for the observed absorptions.

Question. The carbon NMR chemical shifts of diethylmethylamine, piperidine, propan-1-ol, and propanal follow. Determine which spectrum corresponds to each structure, and show which carbon atom(s) are responsible for each absorption.

(a) 25.9, 27.8, 47.9

(b) 12.4, 41.0, 51.1

(c) 7.9, 44.7, 201.9

(d) 10.0, 25.8, 63.6

Question. (a) Show how fragmentation occurs to give the base peak at m/z 58 in the mass spectrum of ethyl propyl amine (N-ethylpropan-1-amine), shown below.

(b) Show how a similar cleavage in the ethyl group gives an ion of m/z72.

(c) Explain why the peak at m/z 72 is much weaker than the one at m/z 58.

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