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Question. (a) Show how fragmentation occurs to give the base peak at m/z 58 in the mass spectrum of ethyl propyl amine (N-ethylpropan-1-amine), shown below.

(b) Show how a similar cleavage in the ethyl group gives an ion of m/z72.

(c) Explain why the peak at m/z 72 is much weaker than the one at m/z 58.

Short Answer

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(A)

(B)

(c) The fragmentation in part (a) occurs more often than the one in part (b) because of the stability of radicals produced along with the iminium ion. Ethyl radical is much more stable than methyl radical so pathway (a) is preferred.

Step by step solution

01

Explanation of part (a)

In mass spectrum, the vertical axis denotes the relative abundance of ions. The most intensive peak in a spectrum is called as base peak. In the mass spectrum, the relative intensity of each ion is normally found using the peak with the highest intensity as standard or base peak. The heaviest ion or the one with greatest m/z value is the molecular ion.

N-ethylpropan-1-amine of m/z value 87, undergoes fragmentation in the form of alpha-cleavage to produce two fragments which have m/z values 58 and 29. The fragment with m/z value 58 is formed due to stabilisation of carbocation by +M-effect of nitrogen atom. Fragment with m/z 29 is the ethyl radical.

02

Explanation of part (b)

In mass spectrum, the vertical axis denotes the relative abundance of ions. The most intensive peak in a spectrum is called as base peak. In the mass spectrum, the relative intensity of each ion is normally found using the peak with the highest intensity as standard or base peak. The heaviest ion or the one with greatest m/z value is the molecular ion.

N-ethylpropan-1-amine undergoes alpha cleavage to produce the fragment which has m/z value of 72. This fragment is stable as nitrogen though having positive charge is stable as it has complete octet. Methyl radical is also produced as a fragment which has m/z value of 15.

03

Explanation of part (c)

The fragmentation in part (a) occurs more often than the one in part (b) because of the stability of radicals produced along with the iminium ion. Ethyl radical is much more stable than methyl radical as radicals are electron deficient species, thus, CH3in CH3CH2 stabilises the radical by inductive effect, so pathway (a) is preferred.

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Predict the products of the following reactions:

(a) 别虫肠别蝉蝉鈥夆赌塏贬3鈥夆赌+鈥夆赌塒hCH2CH2CH2Br

(b)1bromopentane(2)LiAlH4(3)H3O+(1)NaN3

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(d) product鈥夆赌塮rom鈥夆赌塸art鈥夆赌塩heat

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(f) product鈥夆赌塮rom鈥夆赌塸art鈥夆赌塭(3)heat(1)excessCH3I(2)Ag2O

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(k)

(l)

Macrolide antibiotics all have large rings (macrocycle) in which an ester makes the ring; a cyclic ester is termed a lactone. One example is erythromycin A, first isolated from soil bacteria in the 1950鈥檚. Over time, some pathogenic bacteria have developed resistance to erythromycin by evolving an enzymatic mechanism to cleave the macrocycle at the ketone. To counter this resistance, chemists modified the erythromycin structure to replace the ketone with an amine that the bacteria could not detoxify. This modified antibiotic, azithromycin, trade name Zithromax庐, is one of the most prescribed drugs in the world for respiratory infections.

(a) Identify the lactone group in each structure that merits the classification as macrolides.

(b) Two groups are circled. What type of functional group are they? Explain

(c) Identify the ketone in erythromycin targeted by bacteria as the site for detoxification.

(d) Identify the amine in azithromycin. What type of amine is it?

(e) From what you know about the reactivity of ketones and amines, why was an amine a good choice to be the 鈥渃hemical opposite of a ketone鈥?

Basicity depends on availability of an electron pair to bond a proton. Correlate structural effects in these amines with their basicities.

(a) Explain this order:

Show how to prepare the following aromatic amines by aromatic nitration, followed by reduction. You may use benzene and toluene as your aromatic starting materials.

  1. Aniline
  2. p-bromoaniline
  3. m-bromoaniline
  4. m-aminobenzoic acid

Propose a mechanism for nitration of pyridine at the 4-position, and show why this orientation is not observed.

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