Q32 P Predict which member of each pai... [FREE SOLUTION]

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Chapter 2: Q32 P (page 138)

Predict which member of each pair is more soluble in water. Explain your prediction.
(a)
(b)
(c)
(d)
(e)
(f)

Short Answer

Expert verified

(a)

(b)

(c)

(d)

(e)

(f)

Step by step solution

Hydrogen bonding

molecules containing a hydrogen atom linked by a covalent bond to a highly electronegative atom (like N,O of F). It is of two types namely, intermolecular hydrogen bonding (formed between two molecules of the same or different compounds) and intramolecular hydrogen bonding (formed between hydrogen atom and N,O of F atom of the same molecule).

Identification of compounds more soluble in water

The presence of hydrogen bonding between molecules of a substance tells us that the molecules are polar. This implies that the molecules will be soluble in a polar solvent like water. But if the hydrophobic part of the molecule is big, then that molecule would not be soluble in water. Again, if some compounds have extremely polar bonds, then they will be soluble in water.

Predicting the more soluble compound

The second compound will be more soluble in water because it can form hydrogen bonds with water.
The second compound will be more soluble in water because it can form more hydrogen bonds with water. The second compound has two oxygen atoms while the first compound has only one oxygen atom.
The first compound is more soluble in water since it has a shorter carbon chain which is hydrophobic.
The second compound will be more soluble in water because it can form hydrogen bonds with water.
The second compound will be more soluble in water because it can form more hydrogen bonds with water. The second compound has two bromine atoms while the first compound has only one oxygen atom.
The second compound is more soluble in water since it has a shorter carbon chain which is hydrophobic.