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Chapter 21: 15P (page 817)

Draw the products of each reaction.

a.

b.

Short Answer

Expert verified

a.

b.

Step by step solution

01

Reaction of an aldehyde with NaCN

The treatment of aldehyde with NaCN in the presence of HCl results in the formation of a secondary alcohol.

02

Product formation in a and b

a.

The reaction of benzaldehyde with NaCN followed by HCl results in the formation of 2-hydroxy-2-phenylacetonitrile as shown below:

Products formed in a

b.

The reaction of 1-hydroxycyclopentanecarbonitrile with H3O+ followed by heat results in the formation of 1-hydroxycyclopentanecarboxylic acid as shown below:

Products formed in B

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Most popular questions from this chapter

What 1掳 amine and carbonyl compound are needed to prepare each imine?

a.

b.

A solution of acetone (CH3)2C=O in ethanol CH3CH2OH in the presence of a trace of acid was allowed to stand for several days, and a new compound of molecular formula C7H16O2 was formed. The IR spectrum showed only one major peak in the functional group region around 3000 cm-1 , and the 1H-NMR spectrum is given here. What is the structure of the product?

What carbonyl compound and amine are formed by the hydrolysis of each compound?

a.

b.

c.

What starting materials are needed to prepare each alkene by a Wittig reaction? When there are two possible routes, indicate which route, if any, is preferred.

a.

b

c.

Draw the products of the following Wittig reactions

a.

b.
See all solutions

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