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Air at \(300^{\circ} \mathrm{C}\) and \(130 \mathrm{kPa}\) flows through a horizontal \(7-\mathrm{cm}\) ID pipe at a velocity of \(42.0 \mathrm{m} / \mathrm{s}\). (a) Calculate \(\dot{E}_{\mathrm{k}}(\mathrm{W}),\) assuming ideal-gas behavior. (b) If the air is heated to \(400^{\circ} \mathrm{C}\) at constant pressure, what is \(\Delta \dot{E}_{\mathrm{k}}=\dot{E}_{\mathrm{k}}\left(400^{\circ} \mathrm{C}\right)-\dot{E}_{\mathrm{k}}\left(300^{\circ} \mathrm{C}\right) ?\) (c) Why would it be incorrect to say that the rate of transfer of heat to the gas in Part (b) must equal the rate of change of kinetic energy?

Short Answer

Expert verified
Part (a): To get the rate of kinetic energy \(\dot{E}_{k}\), the mass flow rate needs to be calculated first, which can be done using the ideal gas law to find the density and then applying the continuity equation. Once we have the rate of mass flow, we can use the formula for kinetic energy to get the rate of kinetic energy. Part (b): The difference \(\Delta \dot{E}_{k}\) can be obtained by repeating the same steps for the heated air and subtracting the \(\dot{E}_{k}\) values for the two temperatures. The change in temperature doesn’t directly result in a change in velocity, but rather in a change in density and hence the mass flow rate. Part (c): The statement is incorrect as it doesn't take into account that the rate of heat transfer can convert into other forms of energy, such as internal energy of the air, not just kinetic energy.

Step by step solution

01

Calculate Mass Flow Rate

Firstly, calculate the mass flow rate of air. The air is assumed to behave as an ideal gas, thus its density can be calculated by \(\rho = \frac{p}{RT}\), where \(p = 130kPa\) is the pressure, \(R = 0.287 kJ/kg·K\) is the specific gas constant for air, and \(T = 300^{\circ}C = 573.15 K\) is the temperature. Once the density is obtained, the mass flow rate can be found by \(\dot{m} = \rho AV\), where \(A = \pi d^2 / 4\) is the cross-sectional area of the pipe and \(V = 42.0 m/s\) is the velocity
02

Calculate the Kinetic Energy Rate for 300°C

Next, use the mass flow rate from the previous step and the provided velocity to calculate the kinetic energy rate for temperature \(300^{\circ}C\) using the formula \(\dot{E}_{k}=1/2 \ \dot{m} {V}^{2}\)
03

Compute the Change in Kinetic Energy Rate

Now, we need to compute the change in kinetic energy when the temperature changes to \(400^{\circ}C\). The same steps need to be repeated for the new temperature scenario to obtain the new kinetic energy rate. Firstly, repeat step 1 but use \(T = 400^{\circ}C = 673.15 K\) to calculate the new mass flow rate. After this, use the new mass flow rate to compute \(\dot{E}_{k}(400^{\circ}C)\). The difference in kinetic energy for the two different temperatures is the subtraction \(\Delta \dot{E}_{k}=\dot{E}_{k}(400^{\circ}C)-\dot{E}_{k}(300^{\circ}C)\)
04

Discuss the Incorrectness of the Statement in Part (c)

Finally, explain why it would be incorrect to say that the rate of transfer of heat to the gas is equal to the rate of change of kinetic energy. The statement is incorrect because it disregards the fact that changes in temperature and state of the gas can result in changes in internal energy, not just kinetic energy. Therefore, the heat transfer can be utilized for changing the internal energy of the gas and not just its kinetic energy

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ideal Gas Law
The Ideal Gas Law is a key equation in understanding the behavior of gases under various conditions. It relates the pressure, volume, and temperature of a gas to the number of moles and the ideal gas constant. The equation is stated as:
  • \( PV = nRT \)
where \( P \) is the pressure, \( V \) is the volume, \( n \) is the number of moles, \( R \) is the ideal gas constant, and \( T \) is the absolute temperature.
To connect this to mass, we can use a rearranged form to find the density \( \rho \) through the equation \( \rho = \frac{P}{RT} \) when working with the specific gas constant \( R \) and absolute temperature \( T \).
In the context of calculating the mass flow rate of air in a pipe, we assumed ideal gas behavior. This allowed us to use pressure, temperature, and gas constant values to determine density and continue with further calculations.
Kinetic Energy Calculation
Kinetic energy in the context of fluid flow is vital for understanding how energy changes affect systems. The kinetic energy rate, particularly in exercises like these, indicates how much energy is carried due to motion. The formula to find the kinetic energy rate is:
  • \( \dot{E}_{k} = \frac{1}{2} \dot{m} V^2 \)
where \( \dot{E}_{k} \) is the kinetic energy rate, \( \dot{m} \) is the mass flow rate, and \( V \) is the velocity.
In this exercise, the air's velocity and the mass flow rate—calculated based on the ideal gas law—are used to determine \( \dot{E}_{k} \). By knowing \( \dot{m} \), the crucial component here, we can solve for kinetic energy at different temperatures. This provides insights into how energy distribution changes with varying temperature conditions, a critical analysis in thermodynamics and engineering scenarios.
Mass Flow Rate
Mass Flow Rate is the quantity of gas passing through a section of a pipe over a period of time. It is a critical value in determining the kinetic energy rate and other thermodynamic properties.
To calculate the mass flow rate \( \dot{m} \), we first determine the density \( \rho \) using the ideal gas law rearranged as mentioned earlier. Then, we use the formula:
  • \( \dot{m} = \rho AV \)
where \( \rho \) is the density, \( A \) is the cross-sectional area of the pipe (calculated as \( \pi d^2 / 4 \) for a circular pipe), and \( V \) is the velocity.
The determination of mass flow rate is foundational, as it is used further in calculating kinetic energy and impacts how other properties, like heat transfer, are understood in the system. During the exercise, by understanding and computing this value under different temperature scenarios, analysts can predict how the system's energy balance shifts.
Heat Transfer
Heat transfer plays a crucial role in thermodynamics, affecting how energy moves and transforms within a system. When a substance such as air is heated, as in the scenario moving from \(300^{\circ}C\) to \(400^{\circ}C\), energy is added to the system.
However, it's essential to distinguish between heat transfer and changes purely in kinetic energy. Heat not only affects kinetic energy but also internal energy, which includes molecular motions and bonding energies. This is why the statement that 'heat transfer equals the rate of change of kinetic energy' is incorrect; not all heat input results in kinetic energy changes.
Understanding heat transfer involves looking at the complete energy picture and its interaction with physical properties, such as temperature and pressure, to fully grasp how energy is allocated within the system.

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Most popular questions from this chapter

One thousand liters of a 95 wt\% glycerol- \(5 \%\) water solution is to be diluted to \(60 \%\) glycerol by adding a \(35 \%\) solution pumped from a large storage tank through a \(5-\mathrm{cm}\) ID pipe at a steady rate. The pipe discharges at a point 23 m higher than the liquid surface in the storage tank. The operation is carried out isothermally and takes 13 min to complete. The friction loss ( \(\hat{F}\) of Equation \(7.7-2\) ) is \(50 \mathrm{J} / \mathrm{kg}\). Calculate the final solution volume and the shaft work in \(\mathrm{kW}\) that the pump must deliver, assuming that the surface of the stored solution and the pipe outlet are both at 1 atm. Data: \(\quad \rho_{\mathrm{H}_{2} \mathrm{O}}=1.00 \mathrm{kg} / \mathrm{L}, \rho_{\mathrm{gly}}=1.26 \mathrm{kg} / \mathrm{L} .\) (Use to estimate solution densities.)

Water from a reservoir passes over a dam through a turbine and discharges from a \(70-\mathrm{cm}\) ID pipe at a point 55 m below the reservoir surface. The turbine delivers 0.80 MW. Calculate the required flow rate of water in \(\left.\mathrm{m}^{3} / \mathrm{min} \text { if friction is neglected. (See Example } 7.7-3 .\right)\) If friction were included, would a higher or lower flow rate be required? (Note: The equation you will solve in this problem has multiple roots. Find a solution less than \(2 \mathrm{m}^{3} / \mathrm{s}\).)

Steam produced in a boiler is frequently "wet"-that is, it is a mist composed of saturated water vapor and entrained liquid droplets. The quality of a wet steam is defined as the fraction of the mixture by mass that is vapor. A wet steam at a pressure of 5.0 bar with a quality of 0.85 is isothermally "dried" by evaporating the entrained liquid. The flow rate of the dried steam is \(52.5 \mathrm{m}^{3} / \mathrm{h}\). (a) Use the steam tables to determine the temperature at which this operation occurs, the specific enthalpies of the wet and dry steams, and the total mass flow rate of the process stream. (b) Calculate the heat input (kW) required for the evaporation process. (c) Suppose leaks developed in the feed pipe to the dryer and in the dryer exit pipe. Speculate on what you would see at each location.

Liquid water at 60 bar and \(250^{\circ} \mathrm{C}\) passes through an adiabatic expansion valve, emerging at a pressure \(P_{\mathrm{f}}\) and temperature \(T_{\mathrm{f}} .\) If \(P_{\mathrm{f}}\) is low enough, some of the liquid evaporates. (a) If \(P_{\mathrm{f}}=1.0\) bar, determine the temperature of the final mixture \(\left(T_{\mathrm{f}}\right)\) and the fraction of the liquid feed that evaporates \(\left(y_{\mathrm{v}}\right)\) by writing an energy balance about the valve and neglecting \(\Delta \dot{E}_{\mathrm{k}}\) (b) If you took \(\Delta \dot{E}_{\mathrm{k}}\) into account in Part (a), how would the calculated outlet temperature compare with the value you determined? What about the calculated value of \(y_{\mathrm{v}} ?\) Explain. (c) What is the value of \(P_{\mathrm{f}}\) above which no evaporation would occur? (d) Sketch the shapes of plots of \(T_{\mathrm{f}}\) versus \(P_{\mathrm{f}}\) and \(y_{\mathrm{v}}\) versus \(P_{\mathrm{f}}\) for 1 bar \(\leq P_{\mathrm{f}} \leq 60\) bar. Briefly explain your reasoning.

Eight fluid ounces \((1 \mathrm{qt}=32 \mathrm{oz})\) of a beverage in a glass at \(18.0^{\circ} \mathrm{C}\) is to be cooled by adding ice and stirring. The properties of the beverage may be taken to be those of liquid water. The enthalpy of the ice relative to liquid water at the triple point is \(-348 \mathrm{kJ} / \mathrm{kg} .\) Estimate the mass of ice (g) that must melt bring the liquid temperature to \(4^{\circ} \mathrm{C},\) neglecting energy losses to the surroundings.

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