/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 36 Steam produced in a boiler is fr... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Steam produced in a boiler is frequently "wet"-that is, it is a mist composed of saturated water vapor and entrained liquid droplets. The quality of a wet steam is defined as the fraction of the mixture by mass that is vapor. A wet steam at a pressure of 5.0 bar with a quality of 0.85 is isothermally "dried" by evaporating the entrained liquid. The flow rate of the dried steam is \(52.5 \mathrm{m}^{3} / \mathrm{h}\). (a) Use the steam tables to determine the temperature at which this operation occurs, the specific enthalpies of the wet and dry steams, and the total mass flow rate of the process stream. (b) Calculate the heat input (kW) required for the evaporation process. (c) Suppose leaks developed in the feed pipe to the dryer and in the dryer exit pipe. Speculate on what you would see at each location.

Short Answer

Expert verified
The saturation temperature, 151.83°C. The specific enthalpy of the wet steam is 317.07 kJ/kg and of the dry steam is 2,113.8 kJ/kg. The heat input (kW) required for evaporation is calculated using the energy balance equation. As for leaks, there would be wet steam at the feed pipe and dry steam at the dryer exit pipe.\n

Step by step solution

01

Determine the temperature

Consult the steam tables for properties of saturated steam at 5 bar pressure. The saturation temperature is 151.83°C.
02

Calculate Specific Enthalpies

Using steam tables, the specific enthalpy of saturated vapor, \(h_{fg}\), and specific enthalpies of wet steam \(h_w\) and dry steam \(h_d\) can be computed. \(h_{fg}(5\, \text{bar}) = 2,113.8 \, \text{kJ/kg}\), \(h_w = (1-0.85) \times h_{fg} = 0.15 \times 2,113.8 = 317.07 \, \text{kJ/kg}\), and \(h_d = h_{fg} = 2,113.8 \, \text{kJ/kg}\)
03

Compute the Mass Flow Rate and Energy Input

The mass flow rate of steam can be obtained from the volume flow rate and the specific volume of steam (from steam tables). After calculating the mass flow rate, the energy required is calculated using the energy balance equation: \(Q = \dot{m}(h_d - h_w)\), where \(Q\) represents the heat input, and \(\dot{m}\) is the mass flow rate.
04

Analyze the Impact of Leaks

If leaks developed in the feed pipe to the dryer and in the dryer exit pipe, at the feed pipe, wet steam (containing water droplets) would be observed while at the dryer exit pipe, one may observe dry steam. The leak at the dryer would also reduce the efficiency of the drying process.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Steam Quality
The quality of steam is an important aspect in thermodynamics, especially in applications involving heat engines and HVAC systems.
It refers to the proportion of steam in a wet steam mixture, given as a ratio between 0 and 1. A quality of 0 indicates pure saturated liquid, while a quality of 1 suggests pure saturated vapor.
For a wet steam with a quality of 0.85, this means 85% of the mixture is in the form of vapor, and the remaining 15% is liquid. Understanding steam quality helps in correctly analyzing energy requirements and efficiency of heat transfer processes.
This is crucial in systems where precise control of thermal energy is needed, such as power generation and food processing.
Enthalpy Calculation
Enthalpy is a measure of total energy within a system, including internal energy and pressure-volume work. When dealing with steam, specific enthalpy is a key factor to consider.
In calculations, specific enthalpy is often derived from steam tables, which list values for both the liquid and vapor phases.
For wet steam, the specific enthalpy can be calculated using a combination of the enthalpies of the liquid and vapor states depending on its quality. The formula often used combines the saturated liquid enthalpy and the enthalpy of vaporization, defined as:
  • h_w = (1-x) imes h_{f} + x imes h_{fg}
  • h_d = h_{fg}
where:
  • x is the steam quality
  • h_{f} is the enthalpy of the liquid state
  • h_{fg} is the enthalpy change from liquid to vapor
Proper enthalpy calculation is essential for determining the energy input/output in thermal systems.
Heat Transfer
Heat transfer is a fundamental concept in thermodynamics and engineering.
It involves the transfer of thermal energy from one system or material to another. In our example, it specifically refers to the energy required to convert entrained liquid into vapor.
The heat input needed for this process is calculated using an energy balance equation:
  • Q = \(\dot{m}(h_d - h_w)\)
where:
  • Q is the heat input,
  • \(\dot{m}\) is the mass flow rate,
  • h_d is the enthalpy of dry steam,
  • h_w is the enthalpy of wet steam.
Understanding and calculating the heat required for phase changes helps maintain system efficiency and predict operational costs.
Saturated Steam
Saturated steam is a term used to describe steam that is in equilibrium with water at a certain pressure and temperature.
In the steam tables, saturated steam denotes the
  • temperature,
  • specific enthalpy,
  • and specific volume
for water boiling at a particular pressure.
Understanding saturated steam is vital in thermodynamic processes because it represents the conditions under which phase change occurs.
This is essential for accurately determining the operating conditions needed for different applications, like turbines and heat exchangers.
Mass Flow Rate Calculation
Mass flow rate is an essential component in thermodynamic and fluid mechanics calculations. It represents the amount of mass passing through a point per unit of time.
In thermal systems, mass flow rate is crucial for understanding how much energy is being transferred in the form of thermal energy or work.
It is calculated from the specific volume of steam and its flow rate as given by:
  • \( \dot{m} = \dfrac{V}{v} \)
where:
  • V is the volumetric flow rate
  • v is the specific volume of steam.
These calculations are crucial for designing and analyzing the efficiency and capacity of systems that utilize steam as a working fluid, such as power plants and steam engines.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Arsenic contamination of aquifers is a major health problem in much of the world and is particularly severe in Bangladesh. One method of removing the arsenic is to pump water from an aquifer to the surface and through a bed packed with granular material containing iron oxide, which binds the arsenic. The purified water is then either used or allowed to seep back through the ground into the aquifer. In an installation of the type just described, a pump draws 69.1 gallons per minute of contaminated water from an aquifer through a 3 -inch ID pipe and then discharges the water through a 2-inch ID pipe to an open overhead tank filled with granular material. The water leaves the end of the discharge line 80 feet above the water in the aquifer. The friction losses in the piping system are \(10 \mathrm{ft} \cdot \mathrm{lb}_{\mathrm{f}} / \mathrm{lb}_{\mathrm{m}}\) (a) If the pump is \(70 \%\) efficient (i.e., \(30 \%\) of the electrical energy delivered to the pump is not used in pumping the water), what is the required pump horsepower? (b) Even if we assume that the iron oxide binds \(100 \%\) of the arsenic, what other factors limit the effectiveness of this operation?

Saturated steam at \(100^{\circ} \mathrm{C}\) is heated to \(350^{\circ} \mathrm{C}\). Use the steam tables to determine (a) the required heat input (J/s) if a continuous stream flowing at \(100 \mathrm{kg} / \mathrm{s}\) undergoes the process at constant pressure and (b) the required heat input (J) if \(100 \mathrm{kg}\) undergoes the process in a constant-volume container. What is the physical significance of the difference between the numerical values of these two quantities?

Superheated steam at \(T_{1}\left(^{\circ} \mathrm{C}\right)\) and 20.0 bar is blended with saturated steam at \(T_{2}\left(^{\circ} \mathrm{C}\right)\) and 10.0 bar in a ratio (1.96 kg of steam at 20 bar)/(1.0 kg of steam at 10 bar). The product stream is at 250^'C and 10.0 bar. The process operates at steady state. (a) Calculate \(T_{1}\) and \(T_{2},\) assuming that the blender operates adiabatically. (b) If in fact heat is being lost from the blender to the surroundings, is your estimate of \(T_{1}\) too high or too low? Briefly explain.

Write and simplify the closed-system energy balance (Equation \(7.3-4\) ) for each of the following processes, and state whether nonzero heat and work terms are positive or negative. Begin by defining the system. The solution of Part (a) is given as an illustration. (a) The contents of a closed flask are heated from \(25^{\circ} \mathrm{C}\) to \(80^{\circ} \mathrm{C}\). (b) A tray filled with water at \(20^{\circ} \mathrm{C}\) is put into a freezer. The water tums into ice at \(-5^{\circ} \mathrm{C}\). (Note: When a substance expandsit does work on its surroundings and when it contracts the surroundings do work on it.) (c) A chemical reaction takes place in a closed adiabatic (perfectly insulated) rigid container. (d) Repeat Part (c), only suppose that the reactor is isothermal rather than adiabatic and that when the reaction was carried out adiabatically, the temperature in the reactor increased.

One thousand liters of a 95 wt\% glycerol- \(5 \%\) water solution is to be diluted to \(60 \%\) glycerol by adding a \(35 \%\) solution pumped from a large storage tank through a \(5-\mathrm{cm}\) ID pipe at a steady rate. The pipe discharges at a point 23 m higher than the liquid surface in the storage tank. The operation is carried out isothermally and takes 13 min to complete. The friction loss ( \(\hat{F}\) of Equation \(7.7-2\) ) is \(50 \mathrm{J} / \mathrm{kg}\). Calculate the final solution volume and the shaft work in \(\mathrm{kW}\) that the pump must deliver, assuming that the surface of the stored solution and the pipe outlet are both at 1 atm. Data: \(\quad \rho_{\mathrm{H}_{2} \mathrm{O}}=1.00 \mathrm{kg} / \mathrm{L}, \rho_{\mathrm{gly}}=1.26 \mathrm{kg} / \mathrm{L} .\) (Use to estimate solution densities.)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.