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The pressure in a vessel containing methane and water at \(70^{\circ} \mathrm{C}\) is 10 atm. At the given temperature, the Henry's law constant for methane is \(6.66 \times 10^{4}\) atm/mole fraction. Estimate the mole fraction of methane in the liquid.

Short Answer

Expert verified
The mole fraction of methane in the liquid is \(1.50 \times 10^{-4}\)

Step by step solution

01

Understand Henry's Law

Henry's law is used to predict how much gas can be dissolved in a liquid and it is stated as: the partial pressure of the gas is equal to the Henry's law constant times the mole fraction of gas in the liquid. As a formula it can be represented as: \( P = kH.x \), where P is the partial pressure, kH is the Henry's law constant and x is the mole fraction.
02

Rearrange the Formula

To solve for the mole fraction (x), the Henry's law formula needs to be rearranged. Thus, we get: \( x = P/kH \)
03

Substitute the Values

The given values for P and kH are 10 atm and \(6.66 \times 10^{4}\) atm/mole fraction respectively. Substitute these values into the rearranged formula: \( x = 10 / 6.66 \times 10^{4} = 1.50 \times 10^{-4} \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Dissolved Gases in Liquids
Understanding how gases dissolve in liquids is fundamental in many processes, ranging from natural phenomena like breathing and photosynthesis to industrial applications such as soft drink carbonation and water purification. At a glance, Henry's Law helps us quantify this solubility.

When a gas comes in contact with a liquid, it tends to dissolve until an equilibrium is reached. This equilibrium is where the rate of gas molecules entering the solution is equal to the rate of gas molecules escaping back into the gas phase. Henry's Law states that at constant temperature, the amount of a given gas that dissolves in a given type and volume of liquid is directly proportional to the partial pressure of that gas in contact with the liquid.

In practical terms, an increase in the gas pressure over the liquid will result in more gas being dissolved, and this relationship is quantified by the Henry's law constant. Each gas has its own constant, which changes with temperature and the solute-solvent combination. Hence, chemical engineers must always refer to data at the specified conditions when calculating solubilities.
Chemical Engineering Principles
Chemical engineering encompasses principles that bridge chemistry, physics, and mathematics to process materials into useful forms. One key aspect of chemical engineering is the understanding of mass transfer, which is the migration of various components in a system.

An example of mass transfer is when a gas dissolves in a liquid. Here, chemical engineers need to know how much of a gas will dissolve, which depends on the interactions between molecules and the phase equilibrium conditions. This application of chemical engineering principles is essential for designing and operating equipment such as reactors, absorbers, and strippers, which handle gas-liquid systems and require careful consideration of the equilibrium relations provided by laws like Henry's Law.

Chemical engineers use mathematical models, often rooted in these principles, to predict the behavior of chemical systems. The mole fraction calculation of methane in water under given temperature and pressure conditions, as in the provided exercise, reflects one of these practical applications.
Mole Fraction Calculation
The mole fraction is a way of expressing the concentration of a component in a mixture. It is defined as the number of moles of a component divided by the total number of moles of all components in the mixture. To calculate the mole fraction, one can use the equation derived from Henry's Law, which provides a direct relationship between the partial pressure of the gas ( P ) and the mole fraction ( x ) when the Henry's Law constant ( kH ) is known.

In the case of the exercise, by rearranging Henry's Law and substituting the known values, we obtained the mole fraction of methane in the liquid under the given conditions. This calculation is vital in scenarios where precise knowledge of composition is crucial, like maintaining the quality of a product, ensuring safety in operations, or controlling environmental emissions. Accurate mole fraction calculations contribute significantly to the efficiency and safety of chemical processes.

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Most popular questions from this chapter

The feed to a distillation column (sketched below) is a 45.0 mole\% \(n\) -pentane- 55.0 mole\% n-hexane liquid mixture. The vapor stream leaving the top of the column, which contains 98.0 mole\% pentane and the balance hexane, goes to a total condenser (which means all the vapor is condensed). Half of the liquid condensate is returned to the top of the column as reflux and the rest is withdrawn as overhead product (distillate) at a rate of \(85.0 \mathrm{kmol} / \mathrm{h}\). The distillate contains \(95.0 \%\) of the pentane fed to the column. The liquid stream leaving the bottom of the column goes to a reboiler. Part of the stream is vaporized; the vapor is returned to the bottom of the column as boilup, and the residual liquid is withdrawn as bottoms product.(a) Calculate the molar flow rate of the feed stream and the molar flow rate and composition of the bottoms product stream. (b) Estimate the temperature of the vapor entering the condenser, assuming that it is saturated (at its dew point) at an absolute pressure of 1 atm and that Raoult's law applies to both pentane and hexane. Then estimate the volumetric flow rates of the vapor stream leaving the column and of the liquid distillate product. State any assumptions you make. (c) Estimate the temperature of the reboiler and the composition of the vapor boilup, again assuming operation at 1 atm.(d) Calculate the minimum diameter of the pipe connecting the column and the condenser if the maximum allowable vapor velocity in the pipe is \(10 \mathrm{m} / \mathrm{s}\). Then list all the assumptions underlying the calculation of that number.

State whether you would use Raoult's law or Henry's law to perform vapor- liquid equilibrium calculations for each component in the following liquid mixtures: (a) water and dissolved nitrogen; (b) hexane, octane, and decane; and (c) \(\mathrm{CO}_{2}\) and water in club soda or any other carbonated beverage.

A correlation for methane solubility in seawater \(^{13}\) is given by the equation $$\begin{aligned}\ln \beta=&-67.1962+99.1624\left(\frac{100}{T}\right)+27.9015 \ln \left(\frac{T}{100}\right) \\\&+S\left[-0.072909+0.041674\left(\frac{T}{100}\right)-0.0064603\left(\frac{T}{100}\right)^{2}\right]\end{aligned}$$.where \(\beta\) is volume of gas in \(\mathrm{mL}\) at STP per unit volume (mL) of water when the partial pressure of methane is \(760 \mathrm{mm} \mathrm{Hg}, T\) is temperature in Kelvin, and \(S\) is salinity in parts per thousand (ppt) by weight. At conditions of interest, the average salinity is 35 ppt, the temperature is \(42^{\circ} \mathrm{F}\), and the average density of seawater is \(1.027 \mathrm{g} / \mathrm{cm}^{3}\).(a) Estimate the mole fraction of methane in seawater for equilibrium at the given conditions. Use a mean molecular weight of \(18.4 \mathrm{g} / \mathrm{mol}\) for seawater. What is the Henry's law constant at this temperature and salinity? (b) What does the above equation say about the effect of \(S\) on methane solubility? (c) Use the Henry's law constant from Part (a) to estimate methane solubility at the given temperature and salinity, but 5000 ft below the ocean surface. (Hint: Estimate the pressure at that depth.)(d) At the low temperatures and high pressures associated with the depths described in Part (c), methane can combine with water to form methane hydrates, which may affect bothenergy availability and the environment. Explain (i) how such behavior would influence the results in Part (c) and (ii) how dissolution of methane in seawater might affect energy availability and the environment.

Air at \(25^{\circ} \mathrm{C}\) and 1 atm with a relative humidity of \(25 \%\) is to be dehumidified in an adsorption column packed with silica gel. The equilibrium adsorptivity of water on silica gel is given by the expression \(^{19}\).$$X^{*}(\mathrm{kg} \text { water/ } 100 \mathrm{kg} \text { silica gel })=12.5 \frac{p_{\mathrm{H}_{2} \mathrm{O}}}{p_{\mathrm{H}_{2} \mathrm{O}}^{*}}$$ where \(p_{\mathrm{H}_{2} \mathrm{O}}\) is the partial pressure of water in the gas contacting the silica gel and \(p_{\mathrm{H}, \mathrm{O}}^{*}\) is the vapor pressure of water at the system temperature. Air is fed to the column at a rate of 1.50 L/min until the silica gel is saturated (i.e., until it reaches equilibrium with the feed air), at which point the flow is stopped and the silica gel regenerated. (a) Calculate the minimum amount of silica gel needed in the column if regeneration is to take place no more frequently than every two hours. State any assumptions you make. (b) Briefly describe this process in terms that a high school student would have no trouble understanding. (What is the process designed to do, what happens within the column, and why is regeneration of the column packing necessary?)

In an attempt to conserve water and to be awarded LEED (Leadership in Energy and Environmental Design) certification, a 20,000-liter cistem has been installed during construction of a new building. The cistem collects water from an HVAC (heating, ventilation, and air-conditioning) system designed to provide 2830 cubic meters of air per minute at \(22^{\circ} \mathrm{C}\) and \(50 \%\) relative humidity after converting it from ambient conditions \(\left(31^{\circ} \mathrm{C}, 70 \% \text { relative humidity }\right) .\) The collected condensate serves as the source of water for lawn maintenance. Estimate (a) the rate of intake of air at ambient conditions in cubic feet per minute and (b) the hours of operation required to fill the cistern.

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