/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 50 A correlation for methane solubi... [FREE SOLUTION] | 91Ó°ÊÓ

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A correlation for methane solubility in seawater \(^{13}\) is given by the equation $$\begin{aligned}\ln \beta=&-67.1962+99.1624\left(\frac{100}{T}\right)+27.9015 \ln \left(\frac{T}{100}\right) \\\&+S\left[-0.072909+0.041674\left(\frac{T}{100}\right)-0.0064603\left(\frac{T}{100}\right)^{2}\right]\end{aligned}$$.where \(\beta\) is volume of gas in \(\mathrm{mL}\) at STP per unit volume (mL) of water when the partial pressure of methane is \(760 \mathrm{mm} \mathrm{Hg}, T\) is temperature in Kelvin, and \(S\) is salinity in parts per thousand (ppt) by weight. At conditions of interest, the average salinity is 35 ppt, the temperature is \(42^{\circ} \mathrm{F}\), and the average density of seawater is \(1.027 \mathrm{g} / \mathrm{cm}^{3}\).(a) Estimate the mole fraction of methane in seawater for equilibrium at the given conditions. Use a mean molecular weight of \(18.4 \mathrm{g} / \mathrm{mol}\) for seawater. What is the Henry's law constant at this temperature and salinity? (b) What does the above equation say about the effect of \(S\) on methane solubility? (c) Use the Henry's law constant from Part (a) to estimate methane solubility at the given temperature and salinity, but 5000 ft below the ocean surface. (Hint: Estimate the pressure at that depth.)(d) At the low temperatures and high pressures associated with the depths described in Part (c), methane can combine with water to form methane hydrates, which may affect bothenergy availability and the environment. Explain (i) how such behavior would influence the results in Part (c) and (ii) how dissolution of methane in seawater might affect energy availability and the environment.

Short Answer

Expert verified
The exercise demonstrates how solubility of methane in seawater is determined under various conditions. It also highlights the impact of methane dissolution on energy availability and the environment. A high salinity decreases the solubility of methane according to the given equation, and the formation of methane hydrates at low temperatures and high pressures reduces the methane concentration in seawater. The dissolution of methane can provide a potential source of energy but may have detrimental effects on the marine life, acidity, and contribute to potential climate change.

Step by step solution

01

Calculation of mole fraction of methane

Calculate the mole fraction of methane in seawater using the equation: \(\ln \beta = -67.1962 + 99.1624 \left (\frac{100}{T} \right) + 27.9015 \ln \left (\frac{T}{100} \right) + S\left[-0.072909 + 0.041674 \left(\frac{T}{100} \right) - 0.0064603 \left(\frac{T}{100} \right)^2\right]\). Evaluate \(\beta\) by approximating the given temperature and salinity into the equation. Determine the mole fraction of CH4 by dividing the gas volume by the volume of the water and multiplying by the density of the water at STP (Standard Temperature and Pressure) then dividing it by the molecular weight of CH4.
02

Determination of Henry's law constant

Calculate Henry's law constant using the formula: \(K_{H} = P / c_{\text{{aq}}}\), where \(P\) is the partial pressure of the gas and \(c_{\text{{aq}}}\) is the molar concentration of the gas. Use the calculated mole fraction from step 1 to determine \(c_{\text{{aq}}}\) and the condition of the problem for the value of \(P\). The result is the Henry's law constant at the specified temperature and salinity.
03

Discuss the effect of salinity on methane solubility

The effect of salinity \(S\) on methane solubility comes from the term in the equation that involves \(S\). As \(S\) increases, the value of that term and therefore the overall value of \(\beta\), decreases. Therefore, an increase in salinity decreases the solubility of methane in seawater.
04

Calculate methane solubility at below ocean surface

Estimate the pressure at 5000 ft below the surface, then use the Henry's law constant from step 2 to estimate the methane solubility at this pressure and the given temperature and salinity.
05

Explanation of methane solubility, energy availability, and environmental impact

(i) The formation of methane hydrates at low temperatures and high pressures would decrease the solubility of methane by removing methane molecules from the water and incorporating them into the hydrate structure. This would result in lower concentrations of methane in seawater compared to the estimate in part (c). (ii) Dissolution of methane in seawater can affect energy availability because methane is a potential energy source. Environmental impacts may include effects on marine life, contributions to acidity, and potential climate change impacts if released to the atmosphere.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Henry's Law Constant Calculation
Understanding the Henry's Law constant is fundamental to predicting how gases like methane dissolve in seawater. At its core, Henry's Law states that the concentration of a dissolved gas in a liquid is directly proportional to the pressure of that gas above the liquid. The mathematical relationship is given by the formula
\( K_H = \frac{P}{c_{\text{aq}}} \),
where \( K_H \) is the Henry's Law constant, \( P \) is the partial pressure of the gas and \( c_{\text{aq}} \) is the aqueous concentration of the gas.

To calculate this constant for methane solubility in seawater, you substitute the appropriate values for methanol into the above equation, which involves using the mole fraction obtained via the solubility correlation given in the problem text. This calculation provides critical information for environmental scientists and chemical engineers assessing the behavior of methane in marine environments.

In educational exercises, it's important to illustrate step-by-step how to transition from the equation to calculating the mole fraction and finally, to determining the Henry's Law constant. This process involves understanding logarithms, temperature effect, and the role of salinity, ensuring a comprehensive approach to understanding solubility principles.
Salinity Effects on Gas Solubility
Salinity is a key factor that influences the solubility of gases in seawater. As you delve into the chemical properties of water and gas interactions, salinity's role becomes more apparent. The aforementioned solubility equation includes a term with variable \( S \) which represents salinity. This part of the equation takes into account the ionic strength of the water, which impacts the behavior of gas molecules.

Generally, an increase in salinity leads to a decrease in gas solubility. This effect can be attributed to the 'salting out' phenomenon, where the presence of salts in water reduces the availability of space for gas molecules, leading to decreased solubility. For methane, a higher salinity means less dissolved methane at equilibrium, which is crucial for understanding how changes in ocean salinity can impact methane distribution in water bodies.

From an educational perspective, it is beneficial to explore the impact of salinity variations through graphical illustration of solubility trends, or by solving problems that compare different salinity levels. This reinforces the concept and can elucidate the complex interplay between various environmental factors and gas solubility.
Methane Hydrates Environmental Impact
Methane hydrates represent a unique interaction between methane and water under specific conditions, typically found in deep-sea sediments. They are ice-like structures where methane is trapped within the crystalline lattice of water molecules. This phenomenon is significant for two main reasons: energy potential and environmental concerns.

From an energy standpoint, methane hydrates are a vast source of natural gas, making them an area of interest for future energy extraction. However, their environmental impact cannot be overlooked. The formation of methane hydrates alters the expected solubility of methane in seawater by trapping the gas, which could lead to underestimations of methane concentrations when not accounted for in models.

Moreover, the potential release of methane, a potent greenhouse gas, during hydrate breakdown poses a risk for climate change. This release can occur naturally or as a result of human interventions like deep-sea drilling. In educational terms, discussing methane hydrates offers a chance to integrate chemistry with environmental science, linking molecular interactions to global climate phenomena and energy resource discussions. Through such interdisciplinary exploration, students can appreciate the broader implications of seemingly isolated chemical concepts.

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Most popular questions from this chapter

A fuel cell is an electrochemical device in which hydrogen reacts with oxygen to produce water and DC electricity. A 1-watt proton-exchange membrane fuel cell (PEMFC) could be used for portable applications such as cellular telephones, and a \(100-\mathrm{kW}\) PEMFC could be used to power an automobile. The following reactions occur inside the PEMFC:Anode: \(\quad \mathrm{H}_{2} \rightarrow 2 \mathrm{H}^{+}+2 \mathrm{e}^{-}\) Cathode: \(\quad \frac{1}{2} \mathrm{O}_{2}+2 \mathrm{H}^{+}+2 \mathrm{e}^{-} \rightarrow \mathrm{H}_{2} \mathrm{O}\) Overall: \(\quad \overline{\mathrm{H}}_{2}+\frac{1}{2} \mathrm{O}_{2} \rightarrow \mathrm{H}_{2} \mathrm{O}\) A flowchart of a single cell of a PEMFC is shown below. The complete cell would consist of a stack of such cells in series, such as the one shown in Problem 9.19.The cell consists of two gas channels separated by a membrane sandwiched between two flat carbonpaper electrodes- -the anode and the cathode- -that contain imbedded platinum particles. Hydrogen flows into the anode chamber and contacts the anode, where \(\mathrm{H}_{2}\) molecules are catalyzed by the platinum to dissociate and ionize to form hydrogen ions (protons) and electrons. The electrons are conducted throughthe carbon fibers of the anode to an extemal circuit, where they pass to the cathode of the next cell in the stack. The hydrogen ions permeate from the anode through the membrane to the cathode.Humid air is fed into the cathode chamber, and at the cathode \(\mathrm{O}_{2}\) molecules are catalytically split to form oxygen atoms, which combine with the hydrogen ions coming through the membrane and electrons coming from the external circuit to form water. The water desorbs into the cathode gas and is carried out of the cell. The membrane material is a hydrophilic polymer that absorbs water molecules and facilitates the transport of the hydrogen ions from the anode to the cathode. Electrons come from the anode of the cell at one end of the stack and flow through an extemal circuit to drive the device that the fuel cell is powering, while the electrons coming from the device flow back to the cathode at the opposite end of the stack to complete the circuit. is important to keep the water content of the cathode gas between upper and lower limits. If the content reaches a value for which the relative humidity would exceed \(100 \%,\) condensation occurs at the cathode (flooding), and the entering oxygen must diffuse through a liquid water film before it can react. The rate of this diffusion is much lower than the rate of diffusion through the gas film normally adjacent to the cathode, and so the performance of the fuel cell deteriorates. On the other hand, if there is not enough water in the cathode gas (less than \(85 \%\) relative humidity), the membrane dries out and cannot transport hydrogen efficiently, which also leads to reduced performance. 400-sell 300-yolt PEMFS anerates at stady state witha nonwer outnul of 36 k W, The air fod to It is important to keep the water content of the cathode gas between upper and lower limits. If the content reaches a value for which the relative humidity would exceed \(100 \%,\) condensation occurs at the cathode (flooding), and the entering oxygen must diffuse through a liquid water film before it can react. The rate of this diffusion is much lower than the rate of diffusion through the gas film normally adjacent to the cathode, and so the performance of the fuel cell deteriorates. On the other hand, if there is not enough water in the cathode gas (less than \(85 \%\) relative humidity), the membrane dries out and cannot transport hydrogen efficiently, which also leads to reduced performance.A 400-cell 300-volt PEMFC operates at steady state with a power output of 36 kW. The air fed to the cathode side is at \(20.0^{\circ} \mathrm{C}\) and roughly 1.0 atm (absolute) with a relative humidity of \(70.0 \%\) and a volumetric flow rate of \(4.00 \times 10^{3}\) SLPM (standard liters per minute). The gas exits at \(60^{\circ} \mathrm{C}\). (a) Explain in your own words what happens in a single cell of a PEMFC. (b) The stoichiometric hydrogen requirement for a PEMFC is given by \(\left(n_{\mathrm{Hz}}\right)_{\text {conanmad }}=I N / 2 F,\) where \(I\) is the current in amperes (coulomb/s), \(N\) is the number of single cells in the fuel cell stack, and \(F\) is the Faraday constant, 96,485 coulombs of charge per mol of electrons. Derive this expression. (Hint: Recall that since the cells are stacked in series the same current flows through each one, and the same quantity of hydrogen must be consumed in each single cell to produce that current at each anode.) (c) Use the expression of Part (b) to determine the molar rates of oxygen consumed and water generated in the unit with the given specifications, both in units of mol/min. (Remember that power = voltage \(\times\) current.) Then determine the relative humidity of the cathode exit stream, \(h_{\mathrm{r} \text { rout. }}\) (d) Determine the minimum cathode inlet flow rate in SLPM to prevent the fuel cell from flooding ( \(h_{\mathrm{r}, \text { out }}=100 \%\) ) and the maximum flow rate to prevent it from drying \(\left(h_{\mathrm{r}, \text { out }}=85 \%\right)\) .

Recovery and processing of various oils are important elements of the agricultural and food industries. For example, soybean hulls are removed from the beans, which are then flaked and contacted with hexane. The hexane extracts soybean oil and leaves very little oil in the residual solids. The solids are dried at an elevated temperature, and the dried solids are used to feed livestock or further processed to extract soy protein. The gas stream leaving the dryer is at \(80^{\circ} \mathrm{C}\) 1 atm absolute, and 50\% relative saturation.(a) To recover hexane, the gas leaving the dryer is fed to a condenser, which operates at 1 atm absolute. The gas leaving the condenser contains 5.00 mole \(\%\) hexane, and the hexane condensate is recovered at a rate of \(1.50 \mathrm{kmol} / \mathrm{min}\). (b) In an altemative arrangement, the gas leaving the dryer is compressed to 10.0 atm and the temperature simultancously is increased so that the relative saturation remains at \(50 \% .\) The gas then is cooled at constant pressure to produce a stream containing 5.00 mole \(\%\) hexane. Calculate the final gas temperature and the ratio of volumetric flow rates of the gas streams leaving and entering the condenser. State any assumptions you make.(c) What would you need to know to determine which of processes (a) and (b) is more cost- effective?

An important parameter in the design of gas absorbers is the ratio of the flow rate of the feed liquid to that of the feed gas. The lower the value of this ratio, the lower the cost of the solvent required to process a given quantity of gas but the taller the absorber must be to achieve a specified separation.Propane is recovered from a 7 mole \(\%\) propane \(-93 \%\) nitrogen mixture by contacting the mixture with liquid \(n\) -decane. An insignificant amount of decane is vaporized in the process, and \(98.5 \%\) of the propane entering the unit is absorbed.(a) The highest possible propane mole fraction in the exiting liquid is that in equilibrium with the propane mole fraction in the feed gas (a condition requiring an infinitely tall column). Using Raoult's law to relate the mole fractions of propane in the feed gas and liquid, calculate the ratio \(\left(\dot{n}_{L_{1}} / \dot{n}_{G_{2}}\right)\) corresponding to this limiting condition.(b) Suppose the actual feed ratio \(\left(\dot{n}_{L_{1}} / \dot{n}_{G_{2}}\right)\) is 1.2 times the value calculated in Part (a) and the percentage of the entering propane absorbed is the same (98.5\%). Calculate the mole fraction of propane in the exiting liquid.(c) What are the costs and benefits associated with increasing \(\left(\dot{n}_{L_{1}} / \dot{n}_{G_{2}}\right)\) from its minimum value [the value calculated in Part (a)]? What would you have to know to determine the most cost-effective value of this ratio?

In the manufacture of an active pharmaceutical ingredient (API), the API goes through a final purification step in which it is crystallized, filtered, and washed. The washed crystals contain \(47 \%\) water. They are fed to a tunnel dryer and leave the dryer at a rate of \(165 \mathrm{kg} / \mathrm{h}\) containing \(5 \%\) adhered moisture. Dry air enters the dryer at \(145^{\circ} \mathrm{F}\) and \(1 \mathrm{atm},\) and the outlet air is at \(130^{\circ} \mathrm{F}\) and 1 atm with a relative humidity of \(50 \% .\) Calculate the rate \((\mathrm{kg} / \mathrm{h})\) at which the API enters the dryer and the volumetric flow rate \(\left(\mathrm{ft}^{3} / \mathrm{h}\right)\) of inlet air.

A \(50.0-\mathrm{L}\) tank contains an air-carbon tetrachloride gas mixture at an absolute pressure of \(1 \mathrm{atm}, \mathrm{a}\) temperature of \(34^{\circ} \mathrm{C},\) and a relative saturation of \(30 \% .\) Activated carbon is added to the tank to remove the \(\mathrm{CCl}_{4}\) from the gas by adsorption and the tank is then sealed. The volume of added activated carbon may be assumed negligible in comparison to the tank volume.(a) Calculate \(p_{\mathrm{CCl}_{4}}\) at the moment the tank is sealed, assuming ideal-gas behavior and neglecting adsorption that occurs prior to sealing. (b) Calculate the total pressure in the tank and the partial pressure of carbon tetrachloride at a point when half of the CCl_ initially in the tank has been adsorbed. Note: It was shown in Example \(6.7-1\) that at \(34^{\circ} \mathrm{C}\).$$X^{*}\left(\frac{\mathrm{g} \mathrm{CCl}_{4} \text { adsorbed }}{\mathrm{g} \text { carbon }}\right)=\frac{0.0762 p_{\mathrm{CCl}_{4}}}{1+0.096 p_{\mathrm{CCl}_{4}}}$$ where \(p_{\mathrm{CCl}_{4}}\) is the partial pressure (in \(\mathrm{mm} \mathrm{Hg}\) ) of carbon tetrachloride in the gas contacting the carbon.(c) How much activated carbon must be added to the tank to reduce the mole fraction of \(\mathrm{CCl}_{4}\) in the gas to 0.001?

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