/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 35 In the manufacture of an active ... [FREE SOLUTION] | 91Ó°ÊÓ

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In the manufacture of an active pharmaceutical ingredient (API), the API goes through a final purification step in which it is crystallized, filtered, and washed. The washed crystals contain \(47 \%\) water. They are fed to a tunnel dryer and leave the dryer at a rate of \(165 \mathrm{kg} / \mathrm{h}\) containing \(5 \%\) adhered moisture. Dry air enters the dryer at \(145^{\circ} \mathrm{F}\) and \(1 \mathrm{atm},\) and the outlet air is at \(130^{\circ} \mathrm{F}\) and 1 atm with a relative humidity of \(50 \% .\) Calculate the rate \((\mathrm{kg} / \mathrm{h})\) at which the API enters the dryer and the volumetric flow rate \(\left(\mathrm{ft}^{3} / \mathrm{h}\right)\) of inlet air.

Short Answer

Expert verified
The rate at which the API enters the dryer is 92.05 \( \mathrm{kg/h} \). The volumetric flow rate of the air can be calculated using the ideal gas law and the result from the psychrometric chart.

Step by step solution

01

Calculate the total mass of API and water entering the dryer

The API leaves the dryer at a rate of \(165 \mathrm{kg} / \mathrm{h}\) containing \(5 \%\) adhered moisture. So, the mass of process taking part in the drying process is: \(165 \mathrm{kg/h} = 0.95 * \mathrm{Mass\ of\ API\ and\ water\ entering\ the\ dryer}\), rearranging this equation gives the total mass entering the dryer as \(\frac{165 \mathrm{kg/h}}{0.95} = 173.68 \mathrm{kg/h}\)
02

Determine the rate at which the API enters the dryer

As it was given in the problem, the input contains 47% water. So, the mass of API that enters the dryer is: \((1 - 0.47) * \mathrm{total mass entering the dryer} = (1 - 0.47) * 173.68 \mathrm{kg/h} = 92.05 \mathrm{kg/h}\)
03

Calculate the moisture content in the entering API

The moisture content in the entering API is given by the excess of the total mass entering the over the mass of API content, that is \(173.68 \mathrm{kg/h} - 92.05 \mathrm{kg/h} = 81.63 \mathrm{kg/h}\)
04

Calculate the moisture content leaving the dryer

The moisture content leaving the dryer (which is 5% of the output) can be calculated as: \(0.05 * 165 \mathrm{kg/h} = 8.25 \mathrm{kg/h}\)
05

Compute the rate of evaporation taking place in the dryer

The rate of evaporation is equal to the difference in moisture content entering and leaving the dryer, that is \(81.63 \mathrm{kg/h} - 8.25 \mathrm{kg/h} = 73.38 \mathrm{kg/h}\)
06

Calculate the volumetric flow rate of the inlet air

Using the psychometric chart, we can find out the humidity ratio (the amount of water vapor in the air in kg of water/kg of dry air) at \(130^{\circ}F\) and 50% relative humidity. Using this humidity ratio, we can calculate the total dry air that enters the dryer as: \( \mathrm{total dry air} = \frac{73.38 \mathrm{kg/h}}{\mathrm{humidity ratio}}\). Once this value is found, the volumetric flow rate can be calculated using the ideal gas law where the volume is given by \(V = nRT/P\). Here, n is the number of moles (which equals mass/ molecular weight), R is the ideal gas constant and T is the temperature of the air entering the dryer. The pressure is at 1 atmosphere, so it is equal to 1 atm pressure.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mass Balance Calculations
Understanding mass balance calculations is crucial for aspiring chemical engineers, particularly when dealing with processes like drying in the pharmaceutical industry. Mass balance involves accounting for the material entering and leaving a system, ensuring that the mass is conserved through the process.

To simplify, imagine a balancing scale where everything that goes in must be accounted for either by transforming or coming out in some form. In the context of our example, the washed crystals initially have a certain water content, the amount of which will decrease due to drying. Any discrepancy in these numbers would mean a loss or gain of mass, breaking our fundamental law of conservation.

For students, the challenge often lies in the initial setup: distinguishing between different streams (in this case, solid API and water) and recognizing that while the water content changes, the amount of API should remain constant, assuming no reaction or loss within the dryer. Here's a tip: Always start by identifying all the inputs and outputs in their respective forms before any further calculation.
Psychrometric Chart Application
The psychrometric chart is an invaluable tool for chemical engineers to understand and analyze air-water vapor mixtures, especially when dealing with drying processes.

A psychrometric chart plots various properties of air at a constant pressure over a range of temperatures. This visual representation allows engineers to determine the moisture content of air, track changes in temperature and humidity, and calculate the energy involved in heating or cooling processes.

In the exercise, the chart is used to find the humidity ratio — a critical step in the mass balance that contributes to our understanding of the drying air's capacity. The chart can seem intimidating at first, but it's all about interpreting lines and curves. Remember to locate the initial air temperature and follow the lines to the given relative humidity. This intersection gives you the exact state of air needed to help determine the mass of water it can carry. Engaging with real psychrometric charts and practicing the steps to read them can demystify this process significantly.
Pharmaceutical Ingredient Drying Process
The drying process of pharmaceutical ingredients requires precise control and understanding to ensure product quality and consistency. The purpose of drying is to remove the solvent (usually water) from the crystallized API to obtain the desired purity and concentration.

The key to mastering these operations lies in controlling temperature and humidity, which involves a thorough application of the psychrometric principles. As the wet API enters the dryer, we aim to evaporate the moisture without affecting the chemical structure or integrity of the API. This process is not only about understanding the physical removal of water but also about anticipating changes in the product and the operation conditions.

Understanding the end-to-end process, from moisture content to drying air conditions, is essential. It helps ensure that results are consistent and up to the high standards demanded by pharmaceutical applications. For students working through this kind of problem, visualizing the equipment, the changes in state, and the energy exchanges can deepen comprehension beyond the formulaic approach.

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Most popular questions from this chapter

Liquid methyl ethyl ketone \((\mathrm{MEK})\) is introduced into a vessel containing air. The system temperature is increased to \(55^{\circ} \mathrm{C},\) and the vessel contents reach equilibrium with some MEK remaining in the liquid state. The equilibrium pressure is \(1200 \mathrm{mm} \mathrm{Hg}\).(a) Use the Gibbs phase rule to determine how many degrees of freedom exist for the system at equilibrium. State the meaning of your result in your own words.(b) Mixtures of MEK vapor and air that contain between 1.8 mole\% MEK and 11.5 mole\% MEK can ignite and burn explosively if exposed to a flame or spark. Determine whether or not the given vessel constitutes an explosion hazard.

Sodium bicarbonate is synthesized by reacting sodium carbonate with carbon dioxide and water at \(70^{\circ} \mathrm{C}\) and \(2.0 \mathrm{atm}\) gauge pressure: $$\mathrm{Na}_{2} \mathrm{CO}_{3}+\mathrm{CO}_{2}+\mathrm{H}_{2} \mathrm{O} \rightarrow 2 \mathrm{NaHCO}_{3}$$ An aqueous solution containing 7.00 wt\% sodium carbonate and a gas stream containing 70.0 mole\% \(\mathrm{CO}_{2}\) and the balance air are fed to the reactor. All of the sodium carbonate and some of the carbon dioxide in the feed react. The gas leaving the reactor, which contains the air and unreacted \(\mathrm{CO}_{2},\) is saturated with water vapor at the reactor conditions. A liquid-solid slurry of sodium bicarbonate crystals in a saturated aqueous solution containing \(2.4 \mathrm{wt} \%\) dissolved sodium bicarbonate and a negligible amount of dissolved \(\mathrm{CO}_{2}\) leaves the reactor and is pumped to a filter. The wet filter cake contains 86 wt\% sodium bicarbonate crystals and the balance saturated solution, and the filtrate also is saturated solution. The production rate of solid crystals is \(500 \mathrm{kg} / \mathrm{h}\).Suggestion: Although the problems to be given can be solved in terms of the product flow rate of \(500 \mathrm{kg} \mathrm{NaHCO}_{3}(\mathrm{s}) / \mathrm{h},\) it might be easier to assume a different basis and then scale the process to the desired production rate of crystals.(a) Calculate the composition (component mole fractions) and volumetric flow rate \(\left(\mathrm{m}^{3} / \mathrm{min}\right)\) of the gas stream leaving the reactor. (b) Calculate the feed rate of gas to the process in standard cubic meters/min \(\left[\mathrm{m}^{3}(\mathrm{STP}) / \mathrm{min}\right]\) (c) Calculate the flow rate \((\mathrm{kg} / \mathrm{h})\) of the liquid feed to the process. What more would you need to know to calculate the volumetric flow rate of this stream? (d) The filtrate was assumed to leave the filter as a saturated solution at \(70^{\circ} \mathrm{C}\). What would be the effect on your calculations if the temperature of the filtrate actually dropped to \(50^{\circ} \mathrm{C}\) as it passed through the filter? (e) The reactor pressure of 2 atm gauge was arrived at in an optimization study. What benefit do you suppose would result from increasing the pressure? What penalty would be associated with this increase? The term "Henry's law" should appear in your explanation. (Hint: The reaction occurs in the liquid phase and the \(\mathrm{CO}_{2}\) enters the reactor as a gas. What step must precede the reaction?)

The constituent partial pressures of a gas in equilibrium with a liquid solution at \(30^{\circ} \mathrm{C}\) and \(1 \mathrm{atm}\) containing \(2 \mathrm{Ib}_{\mathrm{m}} \mathrm{SO}_{2} / 100 \mathrm{lb}_{\mathrm{m}} \mathrm{H}_{2} \mathrm{O}\) are \(p_{\mathrm{H}_{2} \mathrm{O}}=31.6 \mathrm{mm} \mathrm{Hg}\) and \(p_{\mathrm{SO}_{2}}=176 \mathrm{mm} \mathrm{Hg} .\) The balance of the gas is air.(a) Calculate the partial pressure of air. If you make any assumptions, state what they are. (b) Suppose the only data available on this system gave \(p_{\mathrm{SO}_{2}}=176 \mathrm{mm}\) Hg, but there was no information given on the equilibrium partial pressure of water. Use Raoult's law to estimate a value for this quantity.Assuming that the value given in the problem statement is correct, what percentage error results from using Raoult's law? (c) The same system was examined in Example \(6.4-1 .\) What percentage errors in the two calculated quantities would result from using Raoult's law for the partial pressure of water?

A \(50.0-\mathrm{L}\) tank contains an air-carbon tetrachloride gas mixture at an absolute pressure of \(1 \mathrm{atm}, \mathrm{a}\) temperature of \(34^{\circ} \mathrm{C},\) and a relative saturation of \(30 \% .\) Activated carbon is added to the tank to remove the \(\mathrm{CCl}_{4}\) from the gas by adsorption and the tank is then sealed. The volume of added activated carbon may be assumed negligible in comparison to the tank volume.(a) Calculate \(p_{\mathrm{CCl}_{4}}\) at the moment the tank is sealed, assuming ideal-gas behavior and neglecting adsorption that occurs prior to sealing. (b) Calculate the total pressure in the tank and the partial pressure of carbon tetrachloride at a point when half of the CCl_ initially in the tank has been adsorbed. Note: It was shown in Example \(6.7-1\) that at \(34^{\circ} \mathrm{C}\).$$X^{*}\left(\frac{\mathrm{g} \mathrm{CCl}_{4} \text { adsorbed }}{\mathrm{g} \text { carbon }}\right)=\frac{0.0762 p_{\mathrm{CCl}_{4}}}{1+0.096 p_{\mathrm{CCl}_{4}}}$$ where \(p_{\mathrm{CCl}_{4}}\) is the partial pressure (in \(\mathrm{mm} \mathrm{Hg}\) ) of carbon tetrachloride in the gas contacting the carbon.(c) How much activated carbon must be added to the tank to reduce the mole fraction of \(\mathrm{CCl}_{4}\) in the gas to 0.001?

An air conditioner is designed to bring \(10,000 \mathrm{ft}^{3} / \mathrm{min}\) of outside air \(\left(90^{\circ} \mathrm{F}, 29.8 \text { inches } \mathrm{Hg} .88 \%\right.\) relative humidity) to \(40^{\circ} \mathrm{F}\), thereby condensing a portion of the water vapor, and then to reheat the air before releasing it into a room at \(65^{\circ} \mathrm{F}\). Calculate the rate of condensation (gallons \(\mathrm{H}_{2} \mathrm{O} / \mathrm{min}\) ) and the volumetric flow rate of the air delivered to the room. (Suggestion: On the flowchart, treat the coolingcondensation and the reheating as separate process steps.)

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