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State whether you would use Raoult's law or Henry's law to perform vapor- liquid equilibrium calculations for each component in the following liquid mixtures: (a) water and dissolved nitrogen; (b) hexane, octane, and decane; and (c) \(\mathrm{CO}_{2}\) and water in club soda or any other carbonated beverage.

Short Answer

Expert verified
Mixture (a) water and dissolved nitrogen: Henry's law. Mixture (b) hexane, octane, and decane: Raoult's law. Mixture (c) \(\mathrm{CO}_{2}\) and water in club soda or any other carbonated beverage: Henry's law.

Step by step solution

01

Identifying Laws for Mixture (a)

Mixture (a) contains water and dissolved nitrogen. Nitrogen is a gas dissolved in a liquid, thus, for this component, Henry's law would be more applicable. Water is a liquid in a single component, Raoult's law would be applied here, but in the context of the whole mixture, Henry's law will prevail since it can confine nitrogen gas into the liquid.
02

Identifying Laws for Mixture (b)

Mixture (b) consists of hexane, octane, and decane, which are all non-polar hydrocarbons. They form an ideal or nearly ideal solution, which is the condition under which Raoult's law is applicable. Thus, Raoult's law would be used for the vapor-liquid equilibrium calculations of this mixture.
03

Identifying Laws for Mixture (c)

\(\mathrm{CO}_{2}\) and water in club soda or any other carbonated beverage, is a example of a gas (carbon dioxide) dissolved in a liquid (water). As with mixture (a), Henry's law would be used to determine the vapor-liquid equilibrium in this beverage, since it allows for approximation of the solubility of the gas in the liquid. Water as was in mixture (a) would go by Raoult's law, but considering the mixture as a whole, Henry's law is preferred.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Raoult's Law
Raoult's Law is a fundamental principle used in chemistry to describe how the vapor pressure of an ideal solution is related to the vapor pressures of the pure components. When you have a mixture of liquids, the total vapor pressure is determined by the weighted sum of the vapor pressures of each component. This is according to their mole fractions in the mixture. Raoult's law is particularly useful for ideal or nearly ideal solutions, where interactions between the molecules of different components are similar to those of molecules in pure substance.

In mathematical terms, Raoult's Law is written as follows:
  • For component A in a solution: \( P_A = P_A^0 \cdot x_A \)
  • Here, \( P_A \) is the partial vapor pressure, \( P_A^0 \) is the vapor pressure of the pure substance, and \( x_A \) is the mole fraction of component A in the solution.
Raoult’s Law is typically applied when considering mixtures of similar molecules such as hydrocarbons, i.e., hexane, octane, and decane, which together behave like an ideal solution. It's essential to understand that deviations from this law can occur in solutions that aren't ideal, leading to positive or negative deviations depending on interactions between different molecules.
Henry's Law
Henry's Law helps us understand the behavior of gases in liquids. It states that the amount of gas that dissolves in a liquid is directly proportional to the partial pressure of that gas above the liquid. Henry's Law is crucial for understanding vapor-liquid equilibria involving gases because it allows for the prediction of how much gas will dissolve in a liquid under varying pressure conditions. This law finds its applications in scenarios such as nitrogen dissolving in water or carbon dioxide in beverages like club soda.

The formula for Henry’s Law is:
  • \( C = k_H \cdot P \)
  • Where \( C \) is the concentration of the gas in the liquid, \( k_H \) is Henry's constant, and \( P \) is the partial pressure of the gas.
Understanding Henry's Law is key in designing and operating systems where gas-liquid interactions are critical, such as in the carbonation of beverages, and in several industrial applications like chemical reactors. The law's utility is significant when working with dilute solutions where gas molecules do not interact significantly with each other.
Chemical Processes
Chemical processes often involve a series of steps where reactants are converted to products. The reactants may be gases, liquids, or solids, and understanding their behavior through laws like Raoult's and Henry's is crucial for efficient process design and optimization. In many chemical processes, achieving a balance between different phases, such as vapor and liquid, is essential to ensure maximum yield and purity of the desired products.

Chemical engineers and scientists heavily rely on vapor-liquid equilibrium calculations to determine the conditions under which these phases exist. For example, knowledge of when to apply Raoult's or Henry's Law can directly impact the accuracy of the process design, whether it's the distillation of hydrocarbons or the fermentation processes producing carbon dioxide.
  • Vapor-liquid equilibrium is essential for distillation, where separation of components depends on their different volatilities.
  • In refrigeration, understanding these processes ensures efficient heat transfer.
Grasping these concepts fully helps provide a solid foundation for success in chemical engineering and related fields, guiding students to make informed decisions when confronted with real-world challenges.

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Most popular questions from this chapter

A quantity of methyl acetate is placed in an open, transparent, three-liter flask and boiled long enough to purge all air from the vapor space. The flask is then sealed and allowed to equilibrate at \(30^{\circ} \mathrm{C},\) at which temperature methyl acetate has a vapor pressure of \(269 \mathrm{mm}\) Hg. Visual inspection shows \(10 \mathrm{mL}\) of liquid methyl acetate present.(a) What is the pressure in the flask at equilibrium? Explain your reasoning.(b) What is the total mass (grams) of methyl acetate in the flask? What fraction is in the vapor phase at equilibrium?(c) The above answers would be different if the species in the vessel were ethyl acetate because methyl acetate and ethyl acetate have different vapor pressures. Give a rationale for that difference.

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An air conditioner is designed to bring \(10,000 \mathrm{ft}^{3} / \mathrm{min}\) of outside air \(\left(90^{\circ} \mathrm{F}, 29.8 \text { inches } \mathrm{Hg} .88 \%\right.\) relative humidity) to \(40^{\circ} \mathrm{F}\), thereby condensing a portion of the water vapor, and then to reheat the air before releasing it into a room at \(65^{\circ} \mathrm{F}\). Calculate the rate of condensation (gallons \(\mathrm{H}_{2} \mathrm{O} / \mathrm{min}\) ) and the volumetric flow rate of the air delivered to the room. (Suggestion: On the flowchart, treat the coolingcondensation and the reheating as separate process steps.)

A stage of a separation process is defined as an operation in which components of one or more feed streams divide themselves between two phases, and the phases are taken off separately. In an ideal stage or equilibrium stage, the effluent (exit) streams are in equilibrium with each other.Distillation columns often consist of a series of vertically distributed stages. Vapor flows upward and liquid flows downward between adjacent stages; some of the liquid fed to each stage vaporizes,and some of the vapor fed to each stage condenses. A representation of a section of a distillation column is shown below. (See Problem 4.42 for a more realistic representation.) Consider a distillation column operating at 0.4 atm absolute in which benzene and styrene are being separated. A vapor stream containing 65 mole\% benzene and 35 mole\% styrene enters stage 1 at a rate of \(200 \mathrm{mol} / \mathrm{h}\), and liquid containing 55 mole\% benzene and 45 mole\% styrene leaves this stage at a rate of 150 mol/h. You may assume (1) the stages are ideal, (2) Raoult's law can be used to relate the compositions of the streams leaving each stage, and (3) the total vapor and liquid molar flow rates do not change by a significant amount from one stage to the next.(a) How would you expect the mole fraction of benzene in the liquid to vary from one stage to another, beginning with stage 1 and moving up the column? In light of your answer and considering that the pressure remains essentially constant from one stage to another, how would you then expect the temperature to vary at progressively higher stages? Briefly explain. (b) Estimate the temperature at stage 1 and the compositions of the vapor stream leaving this stage and the liquid stream entering it. Then repeat these calculations for stage 2 . (c) Describe how you would calculate the number of ideal stages required to reduce the styrene content of the vapor to less than 5 mole\%.

The solubility coefficient of a gas may be defined as the number of cubic centimeters (STP) of the gas that dissolves in \(1 \mathrm{cm}^{3}\) of a solvent under a partial pressure of 1 atm. The solubility coefficient of \(\mathrm{CO}_{2}\) in water at \(20^{\circ} \mathrm{C}\) is \(0.0901 \mathrm{cm}^{3} \mathrm{CO}_{2}(\mathrm{STP}) / \mathrm{cm}^{3} \mathrm{H}_{2} \mathrm{O}(\mathrm{l})\). (a) Calculate the Henry's law constant in atm/mole fraction for \(\mathrm{CO}_{2}\) in \(\mathrm{H}_{2} \mathrm{O}\) at \(20^{\circ} \mathrm{C}\) from the given solubility coefficient. (b) How many grams of \(\mathrm{CO}_{2}\) can be dissolved in a \(12-\mathrm{oz}\) bottle of soda at \(20^{\circ} \mathrm{C}\) if the gas above the soda is pure \(\mathrm{CO}_{2}\) at a gauge pressure of 2.5 atm ( 1 liter \(=33.8\) fluid ounces)? Assume the liquid properties are those of water. (c) What volume would the dissolved \(C O_{2}\) occupy if it were released from solution at body temperature and pressure \(-37^{\circ} \mathrm{C}\) and 1 atm?

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