/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 21 A storage tank for liquid \(n\) ... [FREE SOLUTION] | 91Ó°ÊÓ

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A storage tank for liquid \(n\) -octane has a diameter of \(30 \mathrm{ft}\) and a height of \(20 \mathrm{ft}\). During a typical \(24-\mathrm{h}\) period the level of liquid octane falls from 18 ft to 8 ft, after which fresh octane is pumped into the tank to return the level to \(18 \mathrm{ft}\). As the level in the tank falls, nitrogen is fed into the free space to maintain the pressure at 16 psia; when the tank is being refilled, the pressure is maintained at 16 psia by discharging gas from the vapor space to the environment. The nitrogen in the tank may be considered saturated with octane vapor at all times. The average tank temperature is \(90^{\circ} \mathrm{F}\). (a) What is the daily rate, in gallons and \(1 \mathrm{b}_{\mathrm{m}}\), at which octane is used? (b) What is the variation in absolute pressure at the bottom of the tank in inches of mercury? (c) How much octane is lost to the environment during a 24 -h period? (d) Why is nitrogen used in the vapor space of the tank when air would be cheaper? (e) Suggest a means by which the octane can be recovered from the gas stream discharged to the atmosphere.

Short Answer

Expert verified
The daily rate of octane usage will be obtained by calculating the volume of the tank segment corresponding to the drop in liquid level. The variation in the absolute pressure is due to the changing height of the liquid column and can be related through the hydrostatic pressure equation. The octane lost will be proportional to the volume of the nitrogen discharged which may be calculated considering the volume changes in the tank. Nitrogen is used to prevent any unwanted reactions in the tank. Recovering the octane could be achieved by methods like condensation, absorption or adsorption.

Step by step solution

01

Calculate the daily rate of octane usage

The daily rate of octane usage can be calculated by considering the drop in the level in the tank. The volume of the octane used is the volume of the cylindrical segment of the tank with height equal to the drop in the level (18 ft - 8 ft = 10 ft). Use the formula for the volume of a cylinder, \(V = \pi r^2 h\), where r is the radius (half of the diameter, so 15 ft) and h is the height (10 ft). The result will be in cubic feet and needs to be converted into gallons and \(1 \mathrm{bm}\) using appropriate conversion factors. You must have the appropriate conversion rates at hand.
02

Compute the variation in absolute pressure at the bottom of the tank

The variation in pressure at the bottom of the tank is due to the changing height of the liquid octane column. It can be calculated from the pressure difference due just to the height of the liquid column using the hydrostatic pressure equation \(\Delta P = \rho g \Delta h\), where \(\rho\) is the density of the fluid, g is the acceleration due to gravity and \(\Delta h\) is the change in height. The density of octane at the given temperature and the value of g should be known in appropriate units. The result will be in psia and needs to be converted into inches of mercury using the correct conversion factor.
03

Determine the amount of octane lost

The octane is lost to the environment when gas from the vapor space is discharged. The quantity of octane carried away would be proportional to the volume of nitrogen discharged and the solubility of octane in nitrogen. You'll need to calculate the volume of the nitrogen discharged using the volume of the empty space in the tank and the concepts of gas laws. Using the known vapor volume of octane in nitrogen, calculate the octane lost.
04

Reason the use of nitrogen and suggest recovery methods

The reason for using nitrogen in the tank rather than air can be inferred considering the reactivity of the gases. Nitrogen is inert and hence avoids any unwanted reactions, whereas air contains oxygen which could cause oxidation or combustion on contact with octane vapors. Techniques such as condensation, absorption or adsorption processes can be suggested for recovering the octane from the gas stream discharged.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Volumetric Flow Rate Calculation
The volumetric flow rate of a liquid is a measure of the volume of liquid that moves through a given surface area per unit time. It's an essential concept in chemical engineering, as it helps determine how fast a fluid is being used or produced in a process. To calculate the daily rate of octane usage in a storage tank, we consider the volume of octane that the tank loses as the liquid level drops.

To find this volume, we apply the formula for the volume of a cylinder, which is \( V = \pi r^2 h \), where \( r \) is the tank's radius and \( h \) is the change in the liquid's height over 24 hours. By converting this volume from cubic feet to gallons or barrels, we can find the daily volumetric flow rate of octane being used. This rate is pertinent for designing and controlling the storage and usage systems for bulk liquids like octane.
Hydrostatic Pressure Variation
Hydrostatic pressure refers to the pressure exerted by a fluid at rest, due to the force of gravity. It varies with the height of the fluid column above the point of measurement. In the context of the storage tank containing liquid octane, the hydrostatic pressure at the bottom of the tank changes as the liquid level decreases.

The pressure variation is calculated using the hydrostatic pressure equation \(\Delta P = \rho g \Delta h\), where \(\rho\) is the fluid's density, \(g\) is the acceleration due to gravity, and \(\Delta h\) is the change in height of the liquid column. The calculation provides us with the pressure variation in absolute terms, which we can then convert to a more familiar unit such as inches of mercury, allowing for more practical interpretation and usage in the design of pressure maintenance systems.
Environmental Impact of Chemical Processes
Chemical engineering operations can have significant environmental impacts. One aspect of this is the release of chemicals into the atmosphere during process operations. In the case of the storage tank, octane vapors are lost to the environment when nitrogen is discharged to maintain pressure. This loss contributes to pollution and represents a waste of resources.

To assess the environmental impact, we need to determine the amount of octane lost. This requires an understanding of the vapor-liquid equilibrium of octane in nitrogen, as well as calculations based on the tank's vapor space and the properties of the gas mixture. Furthermore, we must consider the environmental regulations governing the emission of volatile organic compounds (VOCs) like octane and strive for sustainable practices, such as recovering octane from the discharged gas to minimize negative environmental effects.
Gas-Solid Operations
In chemical engineering, gas-solid operations involve the contact of gases with solid particles, which is crucial for processes like filtration, drying, and adsorption. This concept is applicable when considering nitrogen use in the vapor space of a storage tank and the subsequent recovery of octane.

The preference for nitrogen over air is to prevent reactions between the oxygen in the air and octane vapors, which could lead to hazards or product degradation. To recover octane from the discharged nitrogen stream, engineering solutions such as adsorption, where octane is captured on the surface of solid adsorbents, can be employed. These operations require a thorough understanding of phase behavior, reaction kinetics, and material properties to ensure efficient recovery and safe operation.

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Most popular questions from this chapter

Pure chlorobenzene is contained in a flask attached to an open-end mercury manometer. When the flask contents are at \(58.3^{\circ} \mathrm{C}\), the height of the mercury in the arm of the manometer connected to the flask is \(747 \mathrm{mm}\) and that in the arm open to the atmosphere is \(52 \mathrm{mm} . \mathrm{At} 110^{\circ} \mathrm{C},\) the mercury level is \(577 \mathrm{mm}\) in the arm connected to the flask and \(222 \mathrm{mm}\) in the other arm. Atmospheric pressure is \(755 \mathrm{mm} \mathrm{Hg}\). (a) Extrapolate the data using the Clausius-Clapeyron equation to estimate the vapor pressure of chlorobenzene at \(130^{\circ} \mathrm{C}\). (b) Air saturated with chlorobenzene at \(130^{\circ} \mathrm{C}\) and \(101.3 \mathrm{kPa}\) is cooled to \(58.3^{\circ} \mathrm{C}\) at constant pressure. Estimate the percentage of the chlorobenzene originally in the vapor that condenses. (See Example 6.3-2.)(c) Summarize the assumptions you made in doing the calculation of Part (b).

An adult inhales approximately 12 times per minute, taking in about 500 mL of air with each inhalation. Oxygen and carbon dioxide are exchanged in the lungs, but there is essentially no exchange of nitrogen. The exhaled air has a mole fraction of nitrogen of 0.75 and is saturated with water vapor at body temperature, \(37^{\circ} \mathrm{C}\). If ambient conditions are \(25^{\circ} \mathrm{C}, 1\) atm, and \(50 \%\) relative humidity, what volume of liquid water (mL) would have to be consumed over a two-hour period to replace the water loss from breathing? How much would have to be consumed if the person is on an airplane where the temperature, pressure, and relative humidity are respectively \(25^{\circ} \mathrm{C}, 1 \mathrm{atm},\) and \(10 \% ?\)

The vapor pressure of ethylene glycol at several temperatures is given below:$$\begin{array}{|l|r|r|r|r|r|r|}\hline T\left(^{\circ} \mathrm{C}\right) & 79.7 & 105.8 & 120.0 & 141.8 & 178.5 & 197.3 \\\\\hline p^{*}(\mathrm{mm} \mathrm{Hg}) & 5.0 & 20.0 & 40.0 & 100.0 & 400.0 & 760.0 \\\\\hline\end{array}$$ a semilog plot e vapor-pressure data and determine a linear expression for \(\ln p^{*}\) function of \(1 / T(\mathrm{K}) .\) Use the results to estimate the heat of vaporization \((\mathrm{kJ} / \mathrm{mol})\) of ethylene glycol, and then use that value in the Clausius-Clapeyron equation to estimate the vapor pressures at each of the temperatures given in the table.(b) Repeat Part (a) using the Slope and Intercept functions of APEx to obtain the expression for \(\ln p^{*}\) vs. \(1 / T(\mathrm{K})\).(c) Use the results from Part (b) to estimate vapor pressures of ethylene glycol at \(50^{\circ} \mathrm{C}, 80^{\circ} \mathrm{C},\) and \(110^{\circ} \mathrm{C} .\) Also estimate the boiling point of this substance at system pressures of \(760 \mathrm{mm} \mathrm{Hg}\) and 2000 mm Hg. Compare all five results with those obtained directly using APEx functions. In which of the estimates at the given temperatures and pressures would you have the least confidence? Explain your reasoning.

A gas mixture containing 85.0 mole \(\% \mathrm{N}_{2}\) and the balance \(n\) -hexane flows through a pipe at a rate of \(100.0 \mathrm{m}^{3} / \mathrm{h} .\) The pressure is 2.00 atm absolute and the temperature is \(100^{\circ} \mathrm{C}\). (a) What is the molar flow rate of the gas in \(\mathrm{kmol} / \mathrm{h}\) ? (b) Is the gas saturated? If not, to what temperature ( \(^{C} C\) ) would it have to be cooled at constant pressure in order to begin condensing hexane? (c) To what temperature ( \(C\) ) would the gas have to be cooled at constant pressure in order to condense \(80 \%\) of the hexane?

A fuel cell is an electrochemical device in which hydrogen reacts with oxygen to produce water and DC electricity. A 1-watt proton-exchange membrane fuel cell (PEMFC) could be used for portable applications such as cellular telephones, and a \(100-\mathrm{kW}\) PEMFC could be used to power an automobile. The following reactions occur inside the PEMFC:Anode: \(\quad \mathrm{H}_{2} \rightarrow 2 \mathrm{H}^{+}+2 \mathrm{e}^{-}\) Cathode: \(\quad \frac{1}{2} \mathrm{O}_{2}+2 \mathrm{H}^{+}+2 \mathrm{e}^{-} \rightarrow \mathrm{H}_{2} \mathrm{O}\) Overall: \(\quad \overline{\mathrm{H}}_{2}+\frac{1}{2} \mathrm{O}_{2} \rightarrow \mathrm{H}_{2} \mathrm{O}\) A flowchart of a single cell of a PEMFC is shown below. The complete cell would consist of a stack of such cells in series, such as the one shown in Problem 9.19.The cell consists of two gas channels separated by a membrane sandwiched between two flat carbonpaper electrodes- -the anode and the cathode- -that contain imbedded platinum particles. Hydrogen flows into the anode chamber and contacts the anode, where \(\mathrm{H}_{2}\) molecules are catalyzed by the platinum to dissociate and ionize to form hydrogen ions (protons) and electrons. The electrons are conducted throughthe carbon fibers of the anode to an extemal circuit, where they pass to the cathode of the next cell in the stack. The hydrogen ions permeate from the anode through the membrane to the cathode.Humid air is fed into the cathode chamber, and at the cathode \(\mathrm{O}_{2}\) molecules are catalytically split to form oxygen atoms, which combine with the hydrogen ions coming through the membrane and electrons coming from the external circuit to form water. The water desorbs into the cathode gas and is carried out of the cell. The membrane material is a hydrophilic polymer that absorbs water molecules and facilitates the transport of the hydrogen ions from the anode to the cathode. Electrons come from the anode of the cell at one end of the stack and flow through an extemal circuit to drive the device that the fuel cell is powering, while the electrons coming from the device flow back to the cathode at the opposite end of the stack to complete the circuit. is important to keep the water content of the cathode gas between upper and lower limits. If the content reaches a value for which the relative humidity would exceed \(100 \%,\) condensation occurs at the cathode (flooding), and the entering oxygen must diffuse through a liquid water film before it can react. The rate of this diffusion is much lower than the rate of diffusion through the gas film normally adjacent to the cathode, and so the performance of the fuel cell deteriorates. On the other hand, if there is not enough water in the cathode gas (less than \(85 \%\) relative humidity), the membrane dries out and cannot transport hydrogen efficiently, which also leads to reduced performance. 400-sell 300-yolt PEMFS anerates at stady state witha nonwer outnul of 36 k W, The air fod to It is important to keep the water content of the cathode gas between upper and lower limits. If the content reaches a value for which the relative humidity would exceed \(100 \%,\) condensation occurs at the cathode (flooding), and the entering oxygen must diffuse through a liquid water film before it can react. The rate of this diffusion is much lower than the rate of diffusion through the gas film normally adjacent to the cathode, and so the performance of the fuel cell deteriorates. On the other hand, if there is not enough water in the cathode gas (less than \(85 \%\) relative humidity), the membrane dries out and cannot transport hydrogen efficiently, which also leads to reduced performance.A 400-cell 300-volt PEMFC operates at steady state with a power output of 36 kW. The air fed to the cathode side is at \(20.0^{\circ} \mathrm{C}\) and roughly 1.0 atm (absolute) with a relative humidity of \(70.0 \%\) and a volumetric flow rate of \(4.00 \times 10^{3}\) SLPM (standard liters per minute). The gas exits at \(60^{\circ} \mathrm{C}\). (a) Explain in your own words what happens in a single cell of a PEMFC. (b) The stoichiometric hydrogen requirement for a PEMFC is given by \(\left(n_{\mathrm{Hz}}\right)_{\text {conanmad }}=I N / 2 F,\) where \(I\) is the current in amperes (coulomb/s), \(N\) is the number of single cells in the fuel cell stack, and \(F\) is the Faraday constant, 96,485 coulombs of charge per mol of electrons. Derive this expression. (Hint: Recall that since the cells are stacked in series the same current flows through each one, and the same quantity of hydrogen must be consumed in each single cell to produce that current at each anode.) (c) Use the expression of Part (b) to determine the molar rates of oxygen consumed and water generated in the unit with the given specifications, both in units of mol/min. (Remember that power = voltage \(\times\) current.) Then determine the relative humidity of the cathode exit stream, \(h_{\mathrm{r} \text { rout. }}\) (d) Determine the minimum cathode inlet flow rate in SLPM to prevent the fuel cell from flooding ( \(h_{\mathrm{r}, \text { out }}=100 \%\) ) and the maximum flow rate to prevent it from drying \(\left(h_{\mathrm{r}, \text { out }}=85 \%\right)\) .

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