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An adult inhales approximately 12 times per minute, taking in about 500 mL of air with each inhalation. Oxygen and carbon dioxide are exchanged in the lungs, but there is essentially no exchange of nitrogen. The exhaled air has a mole fraction of nitrogen of 0.75 and is saturated with water vapor at body temperature, \(37^{\circ} \mathrm{C}\). If ambient conditions are \(25^{\circ} \mathrm{C}, 1\) atm, and \(50 \%\) relative humidity, what volume of liquid water (mL) would have to be consumed over a two-hour period to replace the water loss from breathing? How much would have to be consumed if the person is on an airplane where the temperature, pressure, and relative humidity are respectively \(25^{\circ} \mathrm{C}, 1 \mathrm{atm},\) and \(10 \% ?\)

Short Answer

Expert verified
The exact answer depends on the specific values of saturation pressure at different temperatures and relative humidities, which are not given in the problem. However, by following the steps provided, one would be able to find the volume of liquid water that would need to be consumed over a two-hour period to replace the water loss from breathing in both conditions.

Step by step solution

01

Calculate the volume of inhaled air per min

Given that an adult inhales approximately 12 times per minute with about 500 mL of air each time, the total volume of inhaled air per minute can be calculated as a product of these two numbers: \(Volume_{in} = 12 * 500 = 6000 mL/min\)
02

Determine the mole fraction of water vapor in exhaled air

The exhaled air is saturated with water vapor at body temperature. Use a steam table, or a literature source, to find the saturation pressure of water at the given body temperature of \(37^{\circ} \mathrm{C}\). The mole fraction is then found by using the definition of mole fraction, which is the ratio of the partial pressure to the total pressure: \(X_{H_{2}O, ex} = P_{H_{2}O, sat} / P_{total}\)
03

Determine the mole fraction of water vapor in inhaled air

Given that ambient conditions are \(25^{\circ} \mathrm{C}, 1\) atm and relative humidity is 50%, determine the saturation pressure of water at \(25^{\circ} \mathrm{C}\), which let's call \(P_{H_{2}O, sat 2}\). Next, find the partial pressure of water vapor in the inhaled air (which is the product of saturation pressure and relative humidity). The mole fraction of water in the inhaled air is given by the partial pressure of water vapor divided by the total pressure: \(X_{H_{2}O, in} = 0.5 * P_{H_{2}O, sat 2} / P_{total}\)
04

Calculate the difference in water vapor amounts

The difference in the amount of water vapor between exhaled and inhaled air per min can be calculated by the difference in molar volume multiplied by inhaled volume per min and Avogadro's number. This gives the amount of water vapor in mL that must be consumed to replace water lost from breathing: \(volume H_{2}O = N_{A} * (X_{ex} - X_{in}) * V_{in}\)
05

Repeat for other conditions

The same process can be used to find the difference in water vapor amounts for the conditions on an airplane where the temperature, pressure and relative humidity are \(25^{\circ} \mathrm{C}, 1\) atm and 10% respectively. Simply replace the saturation pressure and relative humidity in step 3 with those corresponding to the conditions on an airplane.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mole Fraction
The mole fraction concept is crucial when it comes to understanding the composition of gaseous mixtures, such as the air we breathe. In simple terms, the mole fraction is a way of expressing the concentration of a component in a mixture. It is defined as the ratio of the number of moles of a particular substance to the total number of moles of all substances present.

When we say that the exhaled air has a mole fraction of nitrogen of 0.75, it means that nitrogen accounts for 75% of the total moles of gas in the exhaled breath. Mole fractions are dimensionless numbers and are particularly useful because they remain unchanged with temperature and pressure variations, which is not the case for other concentration measures like molarity or mass fraction.

Importantly, when calculating respiratory water loss, mole fraction helps us understand how much of the humidity in the exhaled air is due to water vapor in comparison to other gases like nitrogen or oxygen.
Water Vapor Saturation
Water vapor saturation is a term that refers to the maximum amount of water vapor that the air can hold at a specific temperature and pressure. It's directly tied to the concept of relative humidity, which is the ratio of the current amount of water vapor in the air to the total amount it could hold at saturation at the same temperature and pressure.

At body temperature, which is typically around 37 degrees Celsius, the lungs saturate the exhaled air with water vapor. Knowing the saturation pressure of water at this temperature allows us to calculate the mole fraction of water in exhaled air. The more water vapor the air contains at saturation, the higher the loss of water through exhalation - a key factor in calculating respiratory water loss.

Understanding water vapor saturation is crucial, as it ensures accurate measurement of the water vapor content in the air we breathe in and out, ultimately helping in estimating hydration needs.
Avogadro's Number
Avogadro's number, which is approximately 6.022 x 10^23, represents the number of atoms or molecules in one mole of a substance. Its significance cannot be overstated in chemical calculations, including those necessary for understanding respiratory physiology.

For our calculations involving respiratory water loss, we use Avogadro's number to convert mole fractions into actual quantities of water molecules, thus allowing us to quantify the volume of liquid water represented by the moist air exhaled with each breath. Knowing the number of molecules in a given volume of air at specific humidity conditions is essential to accurately determine the water loss occurring due to breathing.
Humidity and Breathing
Humidity plays a fundamental role in the calculation of water loss through respiration. When we inhale, air is humidified to 100% relative humidity at body temperature within the lungs. Upon exhalation, this moist air carries away water from the respiratory system.

The ambient humidity greatly influences the amount of water that needs to be replaced. Higher humidity in the inhaled air means less water is needed to replace respiratory losses because the air coming in is already closer in moisture content to the air being exhaled. Conversely, in dry environments, like inside an airplane cabin, the relative humidity is much lower, and thus, the body loses more water through exhalation, increasing the need for fluid intake.
Gas Exchange in Lungs
The lungs are the primary site for the exchange of gases between the body and the environment. Oxygen is taken into the body, and carbon dioxide is expelled. During this process, nitrogen remains relatively unchanged as it is poorly soluble in blood and not used for metabolic processes.

This exchange of gases occurs via the alveoli in the lungs, tiny sacs where blood and air are separated by just a thin membrane. While the focus here is on water vapor, understanding the entire breath cycle is necessary, as it puts into context the mechanism through which water vapor is added to and removed from the bloodstream.

In the context of calculating respiratory water loss, this exchange process illustrates how humid exhaled air can be saturated with water that was once part of the body's hydration. Thus, ensuring proper hydration is essential to maintain overall respiratory and metabolic function.

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Most popular questions from this chapter

A fuel gas containing methane and ethane is burned with air in a furnace, producing a stack gas at \(300^{\circ} \mathrm{C}\) and \(105 \mathrm{kPa}\) (absolute). You analyze the stack gas and find that it contains no unburned hydrocarbons, oxygen, or carbon monoxide. You also determine the dew-point temperature.(a) Estimate the range of possible dew-point temperatures by determining the dew points when the feed is either pure methane or pure ethane. (b) Estimate the fraction of the feed that is methane if the measured dew- point temperature is \(59.5^{\circ} \mathrm{C}\). (c) What range of measured dew point temperatures would lead to calculated methane mole fractions within 5\% of the value determined in Part (b)?

A gas mixture contains 10.0 mole \(\% \mathrm{H}_{2} \mathrm{O}(\mathrm{v})\) and 90.0 mole \(\% \mathrm{N}_{2} .\) The gas temperature and absolute pressure at the start of each of the three parts of this problem are \(50^{\circ} \mathrm{C}\) and \(500 \mathrm{mm}\) Hg. Ideal-gas behavior may be assumed in every part of this problem.(a) If some of the gas mixture is put in a cylinder and slowly cooled at constant pressure, at what temperature would the first drop of liquid form?(b) If a 30.0 -liter flask is filled with some of the gas mixture and sealed and \(70 \%\) of the water vapor in the flask is condensed, what volume \(\left(\mathrm{cm}^{3}\right)\) would be occupied by the liquid water? What would be the system temperature?(c) If the gas mixture is stored in a rigid-walled cylinder and a low-pressure weather front moves in and the barometric (atmospheric) pressure drops, which of the following would change: (i) the gas density, (ii) the absolute pressure of the gas, (iii) the partial pressure of water in the gas, (iv) the gauge pressure of the gas, (v) the mole fraction of water in the gas, (vi) the dew-point temperature of the mixture?

A vapor mixture of \(n\) -butane (B) and \(n\) -hexane (H) contains 50.0 mole\% butane at \(120^{\circ} \mathrm{C}\) and 1.0 atm. A stream of this mixture flowing at a rate of \(150.0 \mathrm{L} / \mathrm{s}\) is cooled and compressed, causing some but not all of the vapor to condense. (Treat this process as a single-unit operation.) Liquid and vapor product streams emerge from the process in equilibrium at \(T\left(^{\circ} \mathrm{C}\right)\) and \(1100 \mathrm{mm} \mathrm{Hg}\). The vapor product contains 60.0 mole\% butane.(a) Draw and label a flowchart. Perform a degree-of-freedom analysis to show that you have enough information to determine the required final temperature ( \(T\) ), the composition of the liquid product (component mole fractions), and the molar flow rates of the liquid and vapor products from the given information and Antoine expressions for the vapor pressures \(p_{\mathrm{B}}^{*}(T)\) and \(p_{\mathrm{H}}^{*}(T) .\) Just identify the equations - for example, mole balance on butane or Raoult's law for hexane-but don't write them yet.(b) Write in order the equations you would use to determine the quantities listed in Part (a) and also the fractional condensation of hexane (mol \(\mathrm{H}\) condensed/mol \(\mathrm{H}\) fed). In each equation, circle the variable for which you would solve. Do no algebra or calculations.(c) Complete the calculations either manually or with an equation-solving program.(d) State three assumptions you made that could lead to errors in the calculated quantities.

Sulfur trioxide (SO \(_{3}\) ) dissolves in and reacts with water to form an aqueous solution of sulfuric acid \(\left(\mathrm{H}_{2} \mathrm{SO}_{4}\right) .\) The vapor in equilibrium with the solution contains both \(\mathrm{SO}_{3}\) and \(\mathrm{H}_{2} \mathrm{O}\). If enough \(\mathrm{SO}_{3}\) is added, all of the water reacts and the solution becomes pure \(\mathrm{H}_{2} \mathrm{SO}_{4}\). If still more \(\mathrm{SO}_{3}\) is added, it dissolves to form a solution of \(\mathrm{SO}_{3}\) in \(\mathrm{H}_{2} \mathrm{SO}_{4}\), called oleum or fuming sulfuric acid. The vapor in equilibrium with oleum is pure \(\mathrm{SO}_{3}\). Twenty percent oleum by definition contains \(20 \mathrm{kg}\) of dissolved \(\mathrm{SO}_{3}\) and \(80 \mathrm{kg}\) of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) per hundred kilograms of solution. Alternatively, the oleum composition can be expressed as \(\% \mathrm{SO}_{3}\) by mass, with the constituents of the oleum considered to be \(\mathrm{SO}_{3}\) and \(\mathrm{H}_{2} \mathrm{O}\). (a) Prove that a \(15.0 \%\) oleum contains \(84.4 \% \mathrm{SO}_{3}\) (b) Suppose a gas stream at \(40^{\circ} \mathrm{C}\) and 1.2 atm containing 90 mole \(\% \mathrm{SO}_{3}\) and \(10 \% \mathrm{N}_{2}\) contacts a liquid stream of 98 wt\% \(\mathrm{H}_{2} \mathrm{SO}_{4}\) (aq), producing \(15 \%\) oleum. Tabulated equilibrium data indicate that the partial pressure of \(S O_{3}\) in equilibrium with this oleum is 1.15 mm Hg. Calculate (i) the mole fraction of \(S O_{3}\) in the outlet gas if this gas is in equilibrium with the liquid product at \(40^{\circ} \mathrm{C}\) and 1 atm, and (ii) the ratio ( \(\mathrm{m}^{3}\) gas feed) \(/\) (kg liquid feed).

In an attempt to conserve water and to be awarded LEED (Leadership in Energy and Environmental Design) certification, a 20,000-liter cistem has been installed during construction of a new building. The cistem collects water from an HVAC (heating, ventilation, and air-conditioning) system designed to provide 2830 cubic meters of air per minute at \(22^{\circ} \mathrm{C}\) and \(50 \%\) relative humidity after converting it from ambient conditions \(\left(31^{\circ} \mathrm{C}, 70 \% \text { relative humidity }\right) .\) The collected condensate serves as the source of water for lawn maintenance. Estimate (a) the rate of intake of air at ambient conditions in cubic feet per minute and (b) the hours of operation required to fill the cistern.

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