/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 26 An adult inhales approximately 1... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

An adult inhales approximately 12 times per minute, taking in about 500 mL of air with each inhalation. Oxygen and carbon dioxide are exchanged in the lungs, but there is essentially no exchange of nitrogen. The exhaled air has a mole fraction of nitrogen of 0.75 and is saturated with water vapor at body temperature, \(37^{\circ} \mathrm{C}\). If ambient conditions are \(25^{\circ} \mathrm{C}, 1\) atm, and \(50 \%\) relative humidity, what volume of liquid water (mL) would have to be consumed over a two-hour period to replace the water loss from breathing? How much would have to be consumed if the person is on an airplane where the temperature, pressure, and relative humidity are respectively \(25^{\circ} \mathrm{C}, 1 \mathrm{atm},\) and \(10 \% ?\)

Short Answer

Expert verified
The exact answer depends on the specific values of saturation pressure at different temperatures and relative humidities, which are not given in the problem. However, by following the steps provided, one would be able to find the volume of liquid water that would need to be consumed over a two-hour period to replace the water loss from breathing in both conditions.

Step by step solution

01

Calculate the volume of inhaled air per min

Given that an adult inhales approximately 12 times per minute with about 500 mL of air each time, the total volume of inhaled air per minute can be calculated as a product of these two numbers: \(Volume_{in} = 12 * 500 = 6000 mL/min\)
02

Determine the mole fraction of water vapor in exhaled air

The exhaled air is saturated with water vapor at body temperature. Use a steam table, or a literature source, to find the saturation pressure of water at the given body temperature of \(37^{\circ} \mathrm{C}\). The mole fraction is then found by using the definition of mole fraction, which is the ratio of the partial pressure to the total pressure: \(X_{H_{2}O, ex} = P_{H_{2}O, sat} / P_{total}\)
03

Determine the mole fraction of water vapor in inhaled air

Given that ambient conditions are \(25^{\circ} \mathrm{C}, 1\) atm and relative humidity is 50%, determine the saturation pressure of water at \(25^{\circ} \mathrm{C}\), which let's call \(P_{H_{2}O, sat 2}\). Next, find the partial pressure of water vapor in the inhaled air (which is the product of saturation pressure and relative humidity). The mole fraction of water in the inhaled air is given by the partial pressure of water vapor divided by the total pressure: \(X_{H_{2}O, in} = 0.5 * P_{H_{2}O, sat 2} / P_{total}\)
04

Calculate the difference in water vapor amounts

The difference in the amount of water vapor between exhaled and inhaled air per min can be calculated by the difference in molar volume multiplied by inhaled volume per min and Avogadro's number. This gives the amount of water vapor in mL that must be consumed to replace water lost from breathing: \(volume H_{2}O = N_{A} * (X_{ex} - X_{in}) * V_{in}\)
05

Repeat for other conditions

The same process can be used to find the difference in water vapor amounts for the conditions on an airplane where the temperature, pressure and relative humidity are \(25^{\circ} \mathrm{C}, 1\) atm and 10% respectively. Simply replace the saturation pressure and relative humidity in step 3 with those corresponding to the conditions on an airplane.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mole Fraction
The mole fraction concept is crucial when it comes to understanding the composition of gaseous mixtures, such as the air we breathe. In simple terms, the mole fraction is a way of expressing the concentration of a component in a mixture. It is defined as the ratio of the number of moles of a particular substance to the total number of moles of all substances present.

When we say that the exhaled air has a mole fraction of nitrogen of 0.75, it means that nitrogen accounts for 75% of the total moles of gas in the exhaled breath. Mole fractions are dimensionless numbers and are particularly useful because they remain unchanged with temperature and pressure variations, which is not the case for other concentration measures like molarity or mass fraction.

Importantly, when calculating respiratory water loss, mole fraction helps us understand how much of the humidity in the exhaled air is due to water vapor in comparison to other gases like nitrogen or oxygen.
Water Vapor Saturation
Water vapor saturation is a term that refers to the maximum amount of water vapor that the air can hold at a specific temperature and pressure. It's directly tied to the concept of relative humidity, which is the ratio of the current amount of water vapor in the air to the total amount it could hold at saturation at the same temperature and pressure.

At body temperature, which is typically around 37 degrees Celsius, the lungs saturate the exhaled air with water vapor. Knowing the saturation pressure of water at this temperature allows us to calculate the mole fraction of water in exhaled air. The more water vapor the air contains at saturation, the higher the loss of water through exhalation - a key factor in calculating respiratory water loss.

Understanding water vapor saturation is crucial, as it ensures accurate measurement of the water vapor content in the air we breathe in and out, ultimately helping in estimating hydration needs.
Avogadro's Number
Avogadro's number, which is approximately 6.022 x 10^23, represents the number of atoms or molecules in one mole of a substance. Its significance cannot be overstated in chemical calculations, including those necessary for understanding respiratory physiology.

For our calculations involving respiratory water loss, we use Avogadro's number to convert mole fractions into actual quantities of water molecules, thus allowing us to quantify the volume of liquid water represented by the moist air exhaled with each breath. Knowing the number of molecules in a given volume of air at specific humidity conditions is essential to accurately determine the water loss occurring due to breathing.
Humidity and Breathing
Humidity plays a fundamental role in the calculation of water loss through respiration. When we inhale, air is humidified to 100% relative humidity at body temperature within the lungs. Upon exhalation, this moist air carries away water from the respiratory system.

The ambient humidity greatly influences the amount of water that needs to be replaced. Higher humidity in the inhaled air means less water is needed to replace respiratory losses because the air coming in is already closer in moisture content to the air being exhaled. Conversely, in dry environments, like inside an airplane cabin, the relative humidity is much lower, and thus, the body loses more water through exhalation, increasing the need for fluid intake.
Gas Exchange in Lungs
The lungs are the primary site for the exchange of gases between the body and the environment. Oxygen is taken into the body, and carbon dioxide is expelled. During this process, nitrogen remains relatively unchanged as it is poorly soluble in blood and not used for metabolic processes.

This exchange of gases occurs via the alveoli in the lungs, tiny sacs where blood and air are separated by just a thin membrane. While the focus here is on water vapor, understanding the entire breath cycle is necessary, as it puts into context the mechanism through which water vapor is added to and removed from the bloodstream.

In the context of calculating respiratory water loss, this exchange process illustrates how humid exhaled air can be saturated with water that was once part of the body's hydration. Thus, ensuring proper hydration is essential to maintain overall respiratory and metabolic function.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A vapor mixture of \(n\) -butane (B) and \(n\) -hexane (H) contains 50.0 mole\% butane at \(120^{\circ} \mathrm{C}\) and 1.0 atm. A stream of this mixture flowing at a rate of \(150.0 \mathrm{L} / \mathrm{s}\) is cooled and compressed, causing some but not all of the vapor to condense. (Treat this process as a single-unit operation.) Liquid and vapor product streams emerge from the process in equilibrium at \(T\left(^{\circ} \mathrm{C}\right)\) and \(1100 \mathrm{mm} \mathrm{Hg}\). The vapor product contains 60.0 mole\% butane.(a) Draw and label a flowchart. Perform a degree-of-freedom analysis to show that you have enough information to determine the required final temperature ( \(T\) ), the composition of the liquid product (component mole fractions), and the molar flow rates of the liquid and vapor products from the given information and Antoine expressions for the vapor pressures \(p_{\mathrm{B}}^{*}(T)\) and \(p_{\mathrm{H}}^{*}(T) .\) Just identify the equations - for example, mole balance on butane or Raoult's law for hexane-but don't write them yet.(b) Write in order the equations you would use to determine the quantities listed in Part (a) and also the fractional condensation of hexane (mol \(\mathrm{H}\) condensed/mol \(\mathrm{H}\) fed). In each equation, circle the variable for which you would solve. Do no algebra or calculations.(c) Complete the calculations either manually or with an equation-solving program.(d) State three assumptions you made that could lead to errors in the calculated quantities.

When fermentation units are operated with high aeration rates, significant amounts of water can be evaporated into the air passing through the fermentation broth. since fermentation can be adversely affected if water loss is significant, the air is humidified before being fed to the fermenter. Sterilized ambient air is combined with steam to form a saturated air-water mixture at 1 atm and \(90^{\circ} \mathrm{C}\). The mixture is cooled to the temperature of the fermenter \(\left(35^{\circ} \mathrm{C}\right),\) condensing some of the water, and the saturated air is fed to the bottom of the fermenter. For an air flow rate to the fermenter of \(10 \mathrm{L} / \mathrm{min}\) at \(35^{\circ} \mathrm{C}\) and \(1 \mathrm{atm},\) estimate the rate at which steam must be added to the sterilized air and the rate (kg/min) at which condensate is collected upon cooling the air-steam mixture.

A quantity of methyl acetate is placed in an open, transparent, three-liter flask and boiled long enough to purge all air from the vapor space. The flask is then sealed and allowed to equilibrate at \(30^{\circ} \mathrm{C},\) at which temperature methyl acetate has a vapor pressure of \(269 \mathrm{mm}\) Hg. Visual inspection shows \(10 \mathrm{mL}\) of liquid methyl acetate present.(a) What is the pressure in the flask at equilibrium? Explain your reasoning.(b) What is the total mass (grams) of methyl acetate in the flask? What fraction is in the vapor phase at equilibrium?(c) The above answers would be different if the species in the vessel were ethyl acetate because methyl acetate and ethyl acetate have different vapor pressures. Give a rationale for that difference.

The solubility coefficient of a gas may be defined as the number of cubic centimeters (STP) of the gas that dissolves in \(1 \mathrm{cm}^{3}\) of a solvent under a partial pressure of 1 atm. The solubility coefficient of \(\mathrm{CO}_{2}\) in water at \(20^{\circ} \mathrm{C}\) is \(0.0901 \mathrm{cm}^{3} \mathrm{CO}_{2}(\mathrm{STP}) / \mathrm{cm}^{3} \mathrm{H}_{2} \mathrm{O}(\mathrm{l})\). (a) Calculate the Henry's law constant in atm/mole fraction for \(\mathrm{CO}_{2}\) in \(\mathrm{H}_{2} \mathrm{O}\) at \(20^{\circ} \mathrm{C}\) from the given solubility coefficient. (b) How many grams of \(\mathrm{CO}_{2}\) can be dissolved in a \(12-\mathrm{oz}\) bottle of soda at \(20^{\circ} \mathrm{C}\) if the gas above the soda is pure \(\mathrm{CO}_{2}\) at a gauge pressure of 2.5 atm ( 1 liter \(=33.8\) fluid ounces)? Assume the liquid properties are those of water. (c) What volume would the dissolved \(C O_{2}\) occupy if it were released from solution at body temperature and pressure \(-37^{\circ} \mathrm{C}\) and 1 atm?

You were recently hired as a process engineer by a pulp and paper manufacturing firm. Your new boss calls you in and tells you about a pulp dryer designed to reduce the moisture content of \(1500 \mathrm{kg} / \mathrm{min}\) of wet pulp from \(0.9 \mathrm{kg} \mathrm{H}_{2} \mathrm{O} / \mathrm{kg}\) dry pulp to \(0.15 \mathrm{wt} \% \mathrm{H}_{2} \mathrm{O}\). The design called for drawing atmospheric air at \(90 \%\) relative humidity, \(25^{\circ} \mathrm{C}, 760 \mathrm{mm}\) Hg into a blower that forces the air through a heater and into the dryer. When the operation was put into service, weather conditions were exactly as assumed in the design, and measurements showed that the air leaving the dryer was at \(80^{\circ} \mathrm{C}\) and a gauge pressure of \(10 \mathrm{mm}\) Hg. However, there was no way to check the operation of the blower to see if it was delivering the specified volumetric flow rate of air. Your boss wants to check that value and asks you to devise a method for doing so. You go back to your office, sketch the process, and determine that you can estimate the air flow rate from the given information if you also know the moisture content of the air leaving the dryer.(a) Propose a method to estimate the moisture content of the exit air. (b) Suppose your measurement is carried out and you learn that the exit air at \(10 \mathrm{mm}\) Hg gauge has a dew point of \(40^{\circ} \mathrm{C}\). Use that information and the mass of water removed from the wet pulp to determine the volumetric flow rate ( \(\mathrm{m}^{3} / \mathrm{min}\) ) of air entering the system.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.