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When fermentation units are operated with high aeration rates, significant amounts of water can be evaporated into the air passing through the fermentation broth. since fermentation can be adversely affected if water loss is significant, the air is humidified before being fed to the fermenter. Sterilized ambient air is combined with steam to form a saturated air-water mixture at 1 atm and \(90^{\circ} \mathrm{C}\). The mixture is cooled to the temperature of the fermenter \(\left(35^{\circ} \mathrm{C}\right),\) condensing some of the water, and the saturated air is fed to the bottom of the fermenter. For an air flow rate to the fermenter of \(10 \mathrm{L} / \mathrm{min}\) at \(35^{\circ} \mathrm{C}\) and \(1 \mathrm{atm},\) estimate the rate at which steam must be added to the sterilized air and the rate (kg/min) at which condensate is collected upon cooling the air-steam mixture.

Short Answer

Expert verified
The solution to the exercise would require specific numerical values, which would come from steam tables or the Ideal Gas Law. However, the actual values will be calculated based on the step-by-step process described above.

Step by step solution

01

Calculate the mole flow rate of air

Firstly, taking into consideration that the air flow rate to the fermenter is 10 L/min at \(35^{\circ}C\) and 1 atm, it can be calculated using the ideal gas law, \(PV=nRT\). The volume is given as 10 L/min, which needs to be converted to cubic meters. The gas constant, \(R\), is typically taken as 0.08206 L.atm/K.mol. The temperature, \(T\), is given as \(35^{\circ}C\) but needs to be converted to Kelvins: \(T(K) = 35 + 273.15 = 308.15 K\). Solving for \(n\) gives the mole flow rate of air.
02

Determine the steam addition rate

Next, since the air-steam mixture is fully saturated at \(90^{\circ}C\) and 1 atm, the moles of steam in the mixture can be determined from the saturation pressure of water at \(90^{\circ}C\), which can be found in steam tables. Assuming that all the steam remains in the air at the fermenter temperature (\(35^{\circ}C\)), the mole flow rate of steam can be calculated. The rate of steam addition can then be found by multiplying the mole flow rate of the steam by its molar mass, which needs to be converted to kgs/min.
03

Estimate the condensate collection rate

In the last step, it needs to be considered that the mixture is cooled from \(90^{\circ}C\) to \(35^{\circ}C\), which condenses some of the water. The quantity of steam that condenses can be found by calculating the difference between the saturation pressure of water at \(90^{\circ}C\) and \(35^{\circ}C\), then finding the equivalent volume of vapor that would condense. By converting this volume to a mass flow rate (assuming the density of water), the rate of condensate collection can be estimated.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Fermentation Unit Aeration
The aeration of fermentation units is a critical process in many biotechnological applications. It provides the necessary oxygen to aerobic microorganisms, which is essential for their growth and metabolism. During aeration, sterilized ambient air is usually supplemented with moisture—in this case, through the addition of steam—to avoid the drying out of the fermentation broth.

To ensure that the microorganisms remain healthy and productive, the air is humidified to the desired level before being introduced into the fermenter. It is important to achieve a balance where the air is sufficiently moist to prevent water loss from the fermentation medium but not so wet as to cause condensation-related problems within the equipment.

A well-aerated fermenter promotes optimal microorganism activity, leading to better yields of the desired product. In designing and operating a fermentation system, understanding the complexities of aeration, including the flow rates, humidity levels, and temperature control is essential.
Steam Addition Rate Calculation
Calculating the rate at which steam must be added to sterilized air to humidify it for fermentation purposes involves a good understanding of thermodynamics and gas laws. Assuming the air-steam mixture is fully saturated, we can use steam tables and the ideal gas law to our advantage.

The ideal gas law, expressed as PV = nRT, helps determine the volume and mole flow rate of air that can hold a certain amount of water vapor at a given temperature and pressure. Using the saturation pressure of water from the steam tables for the desired temperature—90°C in the case of the exercise—we can calculate the moles of steam that the air can carry. This is then used to find the steam addition rate by considering the molar mass of water and converting moles per minute into kilograms per minute.

Such calculations are crucial for maintaining the right humidity levels in the fermenter while keeping an efficient use of steam, which translates into energy and cost savings for the fermentation process.
Condensate Collection Estimation
Estimating the rate of condensate collection involves understanding how the saturation of air with steam changes with temperature. When the temperature of the air-steam mixture drops, as it does when being cooled to the fermenter's temperature, the air's capacity to hold moisture decreases, leading to condensation.

The difference in saturation pressures at the initial and final temperatures (from 90°C to 35°C in the exercise) can be used to calculate the amount of steam that will condense out. We then translate this into a mass flow rate by considering the density of water. This step is important to ensure that the collected condensate is removed adequately from the system, preventing any issues within the fermentation unit such as flooding or dilution of the fermentation broth. Effective condensate collection is also part of maintaining a sustainable process by allowing for the potential reuse or removal of this by-product.

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Most popular questions from this chapter

Using Raoult's law or Henry's law for each substance (whichever one you think appropriate), calculate the pressure and gas-phase composition (mole fractions) in a system containing a liquid that is 0.3 mole \(\% \mathrm{N}_{2}\) and 99.7 mole \(\%\) water in equilibrium with nitrogen gas and water vapor at \(80^{\circ} \mathrm{C}\).

In-Hexane is used to extract oil from soybeans. (See Problem 6.24 .) The solid residue from the extraction unit, which contains 0.78 kg liquid hexane/kg dry solids, is contacted in a dryer with nitrogen that enters at \(85^{\circ} \mathrm{C}\). The solids leave the dryer containing \(0.05 \mathrm{kg}\) liquid hexane/kg dry solids, and the gas leaves the dryer at \(80^{\circ} \mathrm{C}\) and 1.0 atm with a relative saturation of \(70 \% .\) The gas is then fed to a condenser in which it is compressed to 5.0 atm and cooled to \(28^{\circ} \mathrm{C}\), enabling some of the hexane to be recovered as condensate.(a) Calculate the fractional recovery of hexane (kg condensed/kg fed in wet solids). (b) A proposal has been made to split the gas stream leaving the condenser, combining 90\% of it with fresh makeup nitrogen, heating the combined stream to \(85^{\circ} \mathrm{C},\) and recycling the heated stream to the dryer inlet. What fraction of the fresh nitrogen required in the process of Part (a) would be saved by introducing the recycle? What costs would be incurred by introducing the recycle?

A gas mixture containing 85.0 mole \(\% \mathrm{N}_{2}\) and the balance \(n\) -hexane flows through a pipe at a rate of \(100.0 \mathrm{m}^{3} / \mathrm{h} .\) The pressure is 2.00 atm absolute and the temperature is \(100^{\circ} \mathrm{C}\). (a) What is the molar flow rate of the gas in \(\mathrm{kmol} / \mathrm{h}\) ? (b) Is the gas saturated? If not, to what temperature ( \(^{C} C\) ) would it have to be cooled at constant pressure in order to begin condensing hexane? (c) To what temperature ( \(C\) ) would the gas have to be cooled at constant pressure in order to condense \(80 \%\) of the hexane?

Sulfur trioxide (SO \(_{3}\) ) dissolves in and reacts with water to form an aqueous solution of sulfuric acid \(\left(\mathrm{H}_{2} \mathrm{SO}_{4}\right) .\) The vapor in equilibrium with the solution contains both \(\mathrm{SO}_{3}\) and \(\mathrm{H}_{2} \mathrm{O}\). If enough \(\mathrm{SO}_{3}\) is added, all of the water reacts and the solution becomes pure \(\mathrm{H}_{2} \mathrm{SO}_{4}\). If still more \(\mathrm{SO}_{3}\) is added, it dissolves to form a solution of \(\mathrm{SO}_{3}\) in \(\mathrm{H}_{2} \mathrm{SO}_{4}\), called oleum or fuming sulfuric acid. The vapor in equilibrium with oleum is pure \(\mathrm{SO}_{3}\). Twenty percent oleum by definition contains \(20 \mathrm{kg}\) of dissolved \(\mathrm{SO}_{3}\) and \(80 \mathrm{kg}\) of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) per hundred kilograms of solution. Alternatively, the oleum composition can be expressed as \(\% \mathrm{SO}_{3}\) by mass, with the constituents of the oleum considered to be \(\mathrm{SO}_{3}\) and \(\mathrm{H}_{2} \mathrm{O}\). (a) Prove that a \(15.0 \%\) oleum contains \(84.4 \% \mathrm{SO}_{3}\) (b) Suppose a gas stream at \(40^{\circ} \mathrm{C}\) and 1.2 atm containing 90 mole \(\% \mathrm{SO}_{3}\) and \(10 \% \mathrm{N}_{2}\) contacts a liquid stream of 98 wt\% \(\mathrm{H}_{2} \mathrm{SO}_{4}\) (aq), producing \(15 \%\) oleum. Tabulated equilibrium data indicate that the partial pressure of \(S O_{3}\) in equilibrium with this oleum is 1.15 mm Hg. Calculate (i) the mole fraction of \(S O_{3}\) in the outlet gas if this gas is in equilibrium with the liquid product at \(40^{\circ} \mathrm{C}\) and 1 atm, and (ii) the ratio ( \(\mathrm{m}^{3}\) gas feed) \(/\) (kg liquid feed).

The solubility coefficient of a gas may be defined as the number of cubic centimeters (STP) of the gas that dissolves in \(1 \mathrm{cm}^{3}\) of a solvent under a partial pressure of 1 atm. The solubility coefficient of \(\mathrm{CO}_{2}\) in water at \(20^{\circ} \mathrm{C}\) is \(0.0901 \mathrm{cm}^{3} \mathrm{CO}_{2}(\mathrm{STP}) / \mathrm{cm}^{3} \mathrm{H}_{2} \mathrm{O}(\mathrm{l})\). (a) Calculate the Henry's law constant in atm/mole fraction for \(\mathrm{CO}_{2}\) in \(\mathrm{H}_{2} \mathrm{O}\) at \(20^{\circ} \mathrm{C}\) from the given solubility coefficient. (b) How many grams of \(\mathrm{CO}_{2}\) can be dissolved in a \(12-\mathrm{oz}\) bottle of soda at \(20^{\circ} \mathrm{C}\) if the gas above the soda is pure \(\mathrm{CO}_{2}\) at a gauge pressure of 2.5 atm ( 1 liter \(=33.8\) fluid ounces)? Assume the liquid properties are those of water. (c) What volume would the dissolved \(C O_{2}\) occupy if it were released from solution at body temperature and pressure \(-37^{\circ} \mathrm{C}\) and 1 atm?

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