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The solubility of sodium bicarbonate in water is \(11.1 \mathrm{g} \mathrm{NaHCO}_{3} / 100 \mathrm{g} \mathrm{H}_{2} \mathrm{O}\) at \(30^{\circ} \mathrm{C}\) and \(16.4 \mathrm{g}\) \(\mathrm{NaHCO}_{3} / 100 \mathrm{g} \mathrm{H}_{2} \mathrm{O}\) at \(60^{\circ} \mathrm{C} .\) If a saturated solution of \(\mathrm{NaHCO}_{3}\) at \(60^{\circ} \mathrm{C}\) is cooled and comes to equilibrium at \(30^{\circ} \mathrm{C},\) what percentage of the dissolved salt crystallizes?

Short Answer

Expert verified
Approximately 32.32% of the dissolved salt crystallizes.

Step by step solution

01

Determine the initial amount of dissolved sodium bicarbonate

At 60°C, the solubility of sodium bicarbonate is given as 16.4 g per 100 g of water. Given the solution described is saturated, this means that there are 16.4 g of sodium bicarbonate for every 100 g of water.
02

Determine the final amount of dissolved sodium bicarbonate

At 30°C, the solubility of sodium bicarbonate is given as 11.1 g per 100g of water. This means that when cooled to 30°C, only this amount of sodium bicarbonate can remain dissolved in 100g of water. The rest will crystallize.
03

Determine the amount of sodium bicarbonate that crystallizes

Subtract the final amount of dissolved sodium bicarbonate from the initial amount to determine how much sodium bicarbonate crystallizes. \[Crystallized = Initial - Final = 16.4g - 11.1g = 5.3g \]
04

Determine the percentage of sodium bicarbonate that crystallizes

The percentage of sodium bicarbonate that crystallizes can be determined by dividing the amount that crystallizes by the initial amount and multiplying by 100. \[Percentage = \frac{crystallized}{initial} * 100 = \frac{5.3g}{16.4g} * 100 ≈ 32.32% \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sodium Bicarbonate Crystallization
Sodium bicarbonate, commonly known as baking soda, is a compound that can dissolve in water to a certain extent. This solubility is not fixed and varies with changes in temperature. When a saturated solution of sodium bicarbonate is cooled, the amount of compound that water can hold in solution decreases.

This change leads to a process called crystallization, where the dissolved substance forms solid crystals. In the exercise, the crystallization occurs when the saturated solution at 60°C is cooled to 30°C. Since solubility decreases, the sodium bicarbonate that can no longer be kept in solution forms solid crystals.

Through crystallization, the solid sodium bicarbonate gets deposited, often adhering to a surface or forming at the bottom of the container. It's interesting to note that the purity of the crystallized substance is often high because typically, only the pure compound crystallizes out of the solution.
Temperature Effect on Solubility
Temperature is one of the key factors that affect the solubility of substances. The rule of thumb is that solubility of solids in liquids, such as sodium bicarbonate in water, generally increases with an increase in temperature.

Therefore, when the temperature of the solution is raised from 30°C to 60°C, as presented in the exercise, more sodium bicarbonate can dissolve. Conversely, when the solution is cooled, the solubility decreases which is why we observe crystallization of the excess sodium bicarbonate.

This relationship between temperature and solubility is crucial in many practical applications, such as in cooking, chemical synthesis, and preservation processes. Understanding this concept helps to manipulate conditions to either dissolve more of a substance or to crystallize it out from a solution.
Chemical Equilibrium
Chemical equilibrium refers to the state where the rate of the forward chemical reaction equals the rate of the reverse reaction, resulting in no net change in the amounts of reactants and products. It's a dynamic state where reactions are still occurring, but there's no observable change over time.

In the context of solubility, equilibrium is reached when the process of the substance dissolving is balanced with the process of the substance crystallizing. When the saturated solution of sodium bicarbonate is at equilibrium, the rate at which sodium bicarbonate dissolves in water equals the rate at which it crystallizes from the solution.

Whenever the conditions like temperature change, the solubility equilibrium is disturbed, initiating the process to re-establish a new equilibrium at the new temperature. This can result in either more of the solid dissolving or crystallizing out, as observed with the temperature-induced crystallization of sodium bicarbonate.

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Most popular questions from this chapter

In an attempt to conserve water and to be awarded LEED (Leadership in Energy and Environmental Design) certification, a 20,000-liter cistem has been installed during construction of a new building. The cistem collects water from an HVAC (heating, ventilation, and air-conditioning) system designed to provide 2830 cubic meters of air per minute at \(22^{\circ} \mathrm{C}\) and \(50 \%\) relative humidity after converting it from ambient conditions \(\left(31^{\circ} \mathrm{C}, 70 \% \text { relative humidity }\right) .\) The collected condensate serves as the source of water for lawn maintenance. Estimate (a) the rate of intake of air at ambient conditions in cubic feet per minute and (b) the hours of operation required to fill the cistern.

Benzene and hexane are being considered as solvents to extract acetic acid from aqueous mixtures. At \(30^{\circ} \mathrm{C},\) distribution coefficients for the two solvents are \(\mathrm{K}_{\mathrm{B}}=0.098\) mass fraction acetic acid in benzene/mass fraction acetic acid in water and \(\mathrm{K}_{\mathrm{H}}=0.017\) mass fraction acetic acid in hexane/mass fraction acetic acid in water.(a) Based on the distribution coefficients only, which of the two solvents would you use and why? Demonstrate the logic of your decision by comparing the quantities of the two solvents required to reduce the acetic acid content in \(100 \mathrm{kg}\) of an aqueous solution from \(30 \mathrm{wt} \%\) to \(10 \mathrm{wt} \%\).(b) What other factors may be important in choosing between benzene and cyclohexane?

The pressure in a vessel containing methane and water at \(70^{\circ} \mathrm{C}\) is 10 atm. At the given temperature, the Henry's law constant for methane is \(6.66 \times 10^{4}\) atm/mole fraction. Estimate the mole fraction of methane in the liquid.

Recovery and processing of various oils are important elements of the agricultural and food industries. For example, soybean hulls are removed from the beans, which are then flaked and contacted with hexane. The hexane extracts soybean oil and leaves very little oil in the residual solids. The solids are dried at an elevated temperature, and the dried solids are used to feed livestock or further processed to extract soy protein. The gas stream leaving the dryer is at \(80^{\circ} \mathrm{C}\) 1 atm absolute, and 50\% relative saturation.(a) To recover hexane, the gas leaving the dryer is fed to a condenser, which operates at 1 atm absolute. The gas leaving the condenser contains 5.00 mole \(\%\) hexane, and the hexane condensate is recovered at a rate of \(1.50 \mathrm{kmol} / \mathrm{min}\). (b) In an altemative arrangement, the gas leaving the dryer is compressed to 10.0 atm and the temperature simultancously is increased so that the relative saturation remains at \(50 \% .\) The gas then is cooled at constant pressure to produce a stream containing 5.00 mole \(\%\) hexane. Calculate the final gas temperature and the ratio of volumetric flow rates of the gas streams leaving and entering the condenser. State any assumptions you make.(c) What would you need to know to determine which of processes (a) and (b) is more cost- effective?

A dry gas containing \(10.0 \% \mathrm{NH}_{3}\) by volume is contacted with water at \(10^{\circ} \mathrm{C}\) and 1 atm in a singlestage bubble contactor. The effluent liquid and gas streams may be considered to be in equilibrium with each other. A small slip stream taken from the effluent liquid is fed to a continuous densitometer, which indicates that the liquid density is \(0.9534 \mathrm{g} / \mathrm{mL}\) (a) Using tabulated data from Perry's Chemical Engineers' Handbook,12 estimate the percentage of the ammonia in the feed that is removed in the contactor. (b) Why is it important to maintain the slip stream and densitometer chamber at a known temperature at or below the temperature of the contactor?

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