/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 4 The vapor pressure of ethylene g... [FREE SOLUTION] | 91Ó°ÊÓ

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The vapor pressure of ethylene glycol at several temperatures is given below:$$\begin{array}{|l|r|r|r|r|r|r|}\hline T\left(^{\circ} \mathrm{C}\right) & 79.7 & 105.8 & 120.0 & 141.8 & 178.5 & 197.3 \\\\\hline p^{*}(\mathrm{mm} \mathrm{Hg}) & 5.0 & 20.0 & 40.0 & 100.0 & 400.0 & 760.0 \\\\\hline\end{array}$$ a semilog plot e vapor-pressure data and determine a linear expression for \(\ln p^{*}\) function of \(1 / T(\mathrm{K}) .\) Use the results to estimate the heat of vaporization \((\mathrm{kJ} / \mathrm{mol})\) of ethylene glycol, and then use that value in the Clausius-Clapeyron equation to estimate the vapor pressures at each of the temperatures given in the table.(b) Repeat Part (a) using the Slope and Intercept functions of APEx to obtain the expression for \(\ln p^{*}\) vs. \(1 / T(\mathrm{K})\).(c) Use the results from Part (b) to estimate vapor pressures of ethylene glycol at \(50^{\circ} \mathrm{C}, 80^{\circ} \mathrm{C},\) and \(110^{\circ} \mathrm{C} .\) Also estimate the boiling point of this substance at system pressures of \(760 \mathrm{mm} \mathrm{Hg}\) and 2000 mm Hg. Compare all five results with those obtained directly using APEx functions. In which of the estimates at the given temperatures and pressures would you have the least confidence? Explain your reasoning.

Short Answer

Expert verified
Solution will depend on the exact plot and calculations, which will derive the heat of vaporization and hence the vapor pressures at different temperatures and boiling points at varying system pressures.

Step by step solution

01

Create a semilog plot

Plot the given data in the form of a semilog graph with \( \ln p^{*} \) as the vertical axis and \( 1/T(K) \) as the horizontal axis. Use temperature data in Kelvin.
02

Determine the linear expression

Using the least squares method, obtain the equation of the line which best fits the data points. This equation will be of the form \( \ln p^{*} = -\Delta H_{vap}/R * 1/T + C \) where R is the gas constant (R=8.314 J/(mol*K)), \( \Delta H_{vap} \) is the heat of vaporization and C is constant.
03

Estimate the heat of vaporization

From the slope of the linear equation obtained in step 2, estimate the heat of vaporization \(\Delta H_{vap} \) using the formula \( \Delta H_{vap} = -Slope * R \).
04

Estimate the vapor pressure

Substitute the heat of vaporization into the Clausius-Clapeyron equation to estimate the vapor pressures at each of the given temperatures.
05

Repeat steps 1 to 4 with APEX functions

Use the APEX functions to obtain the linear expression and estimate the vapor pressures. Compare these results with the calculated results.
06

Calculate the vapor pressures and boiling point

Use the obtained linear equation to estimate the vapor pressures of ethylene glycol at temperatures 50°C, 80°C, and 110°C. Also, estimate the boiling point of the substance at system pressures of 760 mm Hg and 2000 mm Hg.
07

Analyze the results

Compare all the results obtained and identify which estimates at the given temperatures and pressures provide the least confidence. Provide reasoning based on the data analysed.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Clausius-Clapeyron Equation
The Clausius-Clapeyron equation is a fundamental principle in physical chemistry that relates the change in pressure with the change in temperature of a substance as it moves between two phases, such as liquid and gas. This relationship is particularly useful for estimating the vapor pressure of a liquid at various temperatures. The equation is expressed as:
\[\ln(p^{*}) = -\frac{\Delta H_{vap}}{R} \cdot \frac{1}{T} + C\] where \( p^{*} \) is the vapor pressure, \( T \) is the temperature in Kelvin, \( R \) is the universal gas constant, \( \Delta H_{vap} \) is the heat of vaporization, and \( C \) is a constant that can be determined through experimental data.
To apply this equation in practice, one must obtain a linear expression of \( \ln p^{*} \) versus \( 1/T \), which is done by plotting experimental vapor pressure data against the inverse of temperature. The slope of this line provides the heat of vaporization, and the intercept gives the constant \( C \). This allows for the calculation of vapor pressures at other temperatures by substituting these values back into the Clausius-Clapeyron equation.
Heat of Vaporization
The heat of vaporization, \( \Delta H_{vap} \), is a critical component in understanding phase transitions, specific to the process of a substance transitioning from liquid to gas. It represents the amount of energy required to vaporize one mole of a liquid at its boiling point under standard atmospheric pressure. This value is essential for the Clausius-Clapeyron equation, as it directly influences the curve of the vapor pressure versus temperature plot.

Estimating the heat of vaporization typically involves analyzing a graph of vapor pressure against temperature. Once the linear representation of \( \ln p^{*} \) versus \( 1/T \) is determined, the negative of the slope multiplied by the gas constant \( R \) yields the heat of vaporization:
\[ \Delta H_{vap} = -(\text{Slope}) \times R \] In the context of an educational exercise, students are often tasked with finding this slope through linear regression analysis on their semilog plot. This calculation allows them to understand the thermodynamic principles governing phase changes while providing a practical approach to real-world chemical problems.
Semilog Plot
A semilog plot is a type of graph used to visualize data where one axis (usually the y-axis) is on a logarithmic scale and the other axis (x-axis) is on a linear scale. This kind of plot is particularly useful when the data covers a large range of values, as it can show the smaller and larger values on the same graph without losing detail.

For estimating vapor pressures, a semilog plot helps to linearize the exponential relationship expressed by the Clausius-Clapeyron equation. In the plot, the natural logarithm of the vapor pressure (\( \ln p^{*} \)) is graphed against the reciprocal of the temperature in Kelvin (\( 1/T \)). The result is a straight line when the assumptions of the Clausius-Clapeyron equation hold true, which greatly simplifies the process of determining the heat of vaporization and subsequent calculations of vapor pressures at various temperatures.
Linear Regression Analysis
Linear regression analysis is a statistical method used to model the relationship between a dependent variable and one or more independent variables. In the context of vapor pressure estimation, linear regression is applied to determine the best-fit line through a set of data points on the semilog plot of natural log vapor pressure versus reciprocal temperature.

The equation of this best-fit line is of the form:
\[ y = mx + b \] where \( y \) corresponds to \( \ln p^{*} \), \( x \) is \( 1/T \), \( m \) is the slope of the line, and \( b \) is the y-intercept. In the Clausius-Clapeyron equation, the slope (\( m \)) is related to the negative heat of vaporization (\( -\Delta H_{vap} \)) and the intercept (\( b \)) corresponds to the constant \( C \).

Using linear regression, one can find the values of \( m \) and \( b \) that minimize the sum of the squared differences between the observed data points and the values predicted by the model. This ensures that the derived heat of vaporization is as accurate as possible with respect to the given data, resulting in reliable vapor pressure estimations.

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Most popular questions from this chapter

When fermentation units are operated with high aeration rates, significant amounts of water can be evaporated into the air passing through the fermentation broth. since fermentation can be adversely affected if water loss is significant, the air is humidified before being fed to the fermenter. Sterilized ambient air is combined with steam to form a saturated air-water mixture at 1 atm and \(90^{\circ} \mathrm{C}\). The mixture is cooled to the temperature of the fermenter \(\left(35^{\circ} \mathrm{C}\right),\) condensing some of the water, and the saturated air is fed to the bottom of the fermenter. For an air flow rate to the fermenter of \(10 \mathrm{L} / \mathrm{min}\) at \(35^{\circ} \mathrm{C}\) and \(1 \mathrm{atm},\) estimate the rate at which steam must be added to the sterilized air and the rate (kg/min) at which condensate is collected upon cooling the air-steam mixture.

Pure chlorobenzene is contained in a flask attached to an open-end mercury manometer. When the flask contents are at \(58.3^{\circ} \mathrm{C}\), the height of the mercury in the arm of the manometer connected to the flask is \(747 \mathrm{mm}\) and that in the arm open to the atmosphere is \(52 \mathrm{mm} . \mathrm{At} 110^{\circ} \mathrm{C},\) the mercury level is \(577 \mathrm{mm}\) in the arm connected to the flask and \(222 \mathrm{mm}\) in the other arm. Atmospheric pressure is \(755 \mathrm{mm} \mathrm{Hg}\). (a) Extrapolate the data using the Clausius-Clapeyron equation to estimate the vapor pressure of chlorobenzene at \(130^{\circ} \mathrm{C}\). (b) Air saturated with chlorobenzene at \(130^{\circ} \mathrm{C}\) and \(101.3 \mathrm{kPa}\) is cooled to \(58.3^{\circ} \mathrm{C}\) at constant pressure. Estimate the percentage of the chlorobenzene originally in the vapor that condenses. (See Example 6.3-2.)(c) Summarize the assumptions you made in doing the calculation of Part (b).

An aqueous waste stream leaving a process contains 10.0 wt\% sulfuric acid and 1 kg nitric acid per \(\mathrm{kg}\) sulfuric acid. The flow rate of sulfuric acid in the waste stream is \(1000 \mathrm{kg} / \mathrm{h}\). The acids are neutralized before being sent to a wastewater treatment facility by combining the waste stream with an aqueous slurry of solid calcium carbonate that contains 2 kg of recycled liquid per \(\mathrm{kg}\) solid calcium carbonate. (The source of the recycled liquid will be given later in the process description.) The following neutralization reactions occur in the reactor:$$\begin{array}{l} \mathrm{CaCO}_{3}+\mathrm{H}_{2} \mathrm{SO}_{4} \rightarrow \mathrm{CaSO}_{4}+\mathrm{H}_{2} \mathrm{O}+\mathrm{CO}_{2} \\ \mathrm{CaCO}_{3}+2 \mathrm{HNO}_{3} \rightarrow \mathrm{Ca}\left(\mathrm{NO}_{3}\right)_{2}+\mathrm{H}_{2} \mathrm{O}+\mathrm{CO}_{2} \end{array}$$,The sulfuric and nitric acids and calcium carbonate fed to the reactor are completely consumed. The carbon dioxide leaving the reactor is compressed to 30 atm absolute and \(40^{\circ} \mathrm{C}\) and sent elsewhere in the plant. The remaining reactor effluents are sent to a crystallizer operating at \(30^{\circ} \mathrm{C},\) at which temperature the solubility of calcium sulfate is \(2.0 \mathrm{g} \mathrm{CaSO}_{4} / 1000 \mathrm{g} \mathrm{H}_{2} \mathrm{O} .\) Calcium sulfate crystals form in the crystallizer and all other species remain in solution.The slurry leaving the crystallizer is filtered to produce (i) a filter cake containing \(96 \%\) calcium sulfate crystals and the remainder entrained saturated calcium sulfate solution, and (ii) a filtrate solution saturated with \(\mathrm{CaSO}_{4}\) at \(30^{\circ} \mathrm{C}\) that also contains dissolved calcium nitrate. The filtrate is split, with a portion being recycled to mix with the solid calcium carbonate to form the slurry fed to the reactor, and the remainder being sent to the wastewater treatment facility.(a) Draw and completely label a flowchart for this process. (b) Speculate on why the acids must be neutralized before being sent to the wastewater treatment facility.(c) Calculate the mass flow rates ( \(\mathrm{kg} / \mathrm{h}\) ) of the calcium carbonate fed to the process and of the filter cake; also determine the mass flow rates and compositions of the solution sent to the wastewater facility and of the recycle stream. (Caution: If you write a water balance around the reactor or the overall system, remember that water is a reaction product and not just an inert solvent.)(d) Calculate the volumetric flow rate ( \(L / h\) ) of the carbon dioxide leaving the process at 30 atm absolute and 40^0 C. Do not assume ideal-gas behavior. (e) The solubility of \(\mathrm{Ca}\left(\mathrm{NO}_{3}\right)_{2}\) at \(30^{\circ} \mathrm{C}\) is \(152.6 \mathrm{kg} \mathrm{Ca}\left(\mathrm{NO}_{3}\right)_{2}\) per \(100 \mathrm{kg} \mathrm{H}_{2} \mathrm{O}\). What is the maximum ratio of nitric acid to sulfuric acid in the feed that can be tolerated without encountering difficulties associated with contamination of the calcium sulfate by-product by \(\mathrm{Ca}\left(\mathrm{NO}_{3}\right)_{2} ?\)

Sodium bicarbonate is synthesized by reacting sodium carbonate with carbon dioxide and water at \(70^{\circ} \mathrm{C}\) and \(2.0 \mathrm{atm}\) gauge pressure: $$\mathrm{Na}_{2} \mathrm{CO}_{3}+\mathrm{CO}_{2}+\mathrm{H}_{2} \mathrm{O} \rightarrow 2 \mathrm{NaHCO}_{3}$$ An aqueous solution containing 7.00 wt\% sodium carbonate and a gas stream containing 70.0 mole\% \(\mathrm{CO}_{2}\) and the balance air are fed to the reactor. All of the sodium carbonate and some of the carbon dioxide in the feed react. The gas leaving the reactor, which contains the air and unreacted \(\mathrm{CO}_{2},\) is saturated with water vapor at the reactor conditions. A liquid-solid slurry of sodium bicarbonate crystals in a saturated aqueous solution containing \(2.4 \mathrm{wt} \%\) dissolved sodium bicarbonate and a negligible amount of dissolved \(\mathrm{CO}_{2}\) leaves the reactor and is pumped to a filter. The wet filter cake contains 86 wt\% sodium bicarbonate crystals and the balance saturated solution, and the filtrate also is saturated solution. The production rate of solid crystals is \(500 \mathrm{kg} / \mathrm{h}\).Suggestion: Although the problems to be given can be solved in terms of the product flow rate of \(500 \mathrm{kg} \mathrm{NaHCO}_{3}(\mathrm{s}) / \mathrm{h},\) it might be easier to assume a different basis and then scale the process to the desired production rate of crystals.(a) Calculate the composition (component mole fractions) and volumetric flow rate \(\left(\mathrm{m}^{3} / \mathrm{min}\right)\) of the gas stream leaving the reactor. (b) Calculate the feed rate of gas to the process in standard cubic meters/min \(\left[\mathrm{m}^{3}(\mathrm{STP}) / \mathrm{min}\right]\) (c) Calculate the flow rate \((\mathrm{kg} / \mathrm{h})\) of the liquid feed to the process. What more would you need to know to calculate the volumetric flow rate of this stream? (d) The filtrate was assumed to leave the filter as a saturated solution at \(70^{\circ} \mathrm{C}\). What would be the effect on your calculations if the temperature of the filtrate actually dropped to \(50^{\circ} \mathrm{C}\) as it passed through the filter? (e) The reactor pressure of 2 atm gauge was arrived at in an optimization study. What benefit do you suppose would result from increasing the pressure? What penalty would be associated with this increase? The term "Henry's law" should appear in your explanation. (Hint: The reaction occurs in the liquid phase and the \(\mathrm{CO}_{2}\) enters the reactor as a gas. What step must precede the reaction?)

A gas containing nitrogen, benzene, and toluene is in equilibrium with a liquid consisting of 35 mole\% benzene and 65 mole \(\%\) toluene at \(85^{\circ} \mathrm{C}\) and 10 atm. Estimate the gas composition (mole fractions) using Raoult's law and assuming ideal-gas behavior.

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