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(a) Give the conjugate base of the following Br酶nstedLowry acids: (i) \(\mathrm{H}_{2} \mathrm{SO}_{3},\) (ii) \(\mathrm{HSO}_{3}^{-}(\mathbf{b})\) Give the conjugate acid of the following Br酶nsted-Lowry bases: (i) \(\mathrm{CH}_{3} \mathrm{NH}_{2}\), (ii) \(\mathrm{CH}_{3} \mathrm{COO}^{-}\).

Short Answer

Expert verified
Conjugate bases: (i) HSO鈧冣伝, (ii) SO鈧兟测伝; Conjugate acids: (i) CH鈧僋H鈧冣伜, (ii) CH鈧僀OOH.

Step by step solution

01

Understand Conjugate Bases

A conjugate base is what remains of a Br酶nsted-Lowry acid after it donates a proton (H鈦). This means that to find the conjugate base of an acid, we simply need to remove one hydrogen atom from the acid's formula and adjust the charge accordingly.
02

Determine the Conjugate Base of H鈧係O鈧

For the acid H鈧係O鈧, remove one hydrogen ion (H鈦). This gives us \[ \mathrm{H}_2\mathrm{SO}_3 \rightarrow \mathrm{HSO}_3^- + \mathrm{H}^+ \]Therefore, the conjugate base of H鈧係O鈧 is \(\mathrm{HSO}_3^-\).
03

Determine the Conjugate Base of HSO鈧冣伝

For the acid HSO鈧冣伝, remove one hydrogen ion (H鈦). This gives us \[ \mathrm{HSO}_3^- \rightarrow \mathrm{SO}_3^{2-} + \mathrm{H}^+ \] Therefore, the conjugate base of HSO鈧冣伝 is \(\mathrm{SO}_3^{2-}\).
04

Understand Conjugate Acids

A conjugate acid is formed when a Br酶nsted-Lowry base accepts a proton (H鈦). To find the conjugate acid of a base, add one hydrogen ion to the base's formula, and adjust the charge accordingly.
05

Determine the Conjugate Acid of CH鈧僋H鈧

For the base CH鈧僋H鈧, add a hydrogen ion (H鈦). This gives us \[ \mathrm{CH}_3\mathrm{NH}_2 + \mathrm{H}^+ \rightarrow \mathrm{CH}_3\mathrm{NH}_3^+ \]Therefore, the conjugate acid of CH鈧僋H鈧 is \(\mathrm{CH}_3\mathrm{NH}_3^+\).
06

Determine the Conjugate Acid of CH鈧僀OO鈦

For the base CH鈧僀OO鈦, add a hydrogen ion (H鈦). This gives us\[ \mathrm{CH}_3\mathrm{COO}^- + \mathrm{H}^+ \rightarrow \mathrm{CH}_3\mathrm{COOH} \]The conjugate acid of CH鈧僀OO鈦 is \(\mathrm{CH}_3\mathrm{COOH}\), which is acetic acid.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Br酶nsted-Lowry Acid
A Br酶nsted-Lowry Acid is a substance that can donate a proton (H鈦) to another substance. In this definition, the proton donor plays a central role and is what distinguishes an acid in this context.
When an acid donates a proton, it transforms into its conjugate base. This process highlights a clear link between acids and their corresponding bases. For instance, let's look at sulfurous acid \(\mathrm{H}_2\mathrm{SO}_3\).
  • When it donates a proton, it becomes \(\mathrm{HSO}_3^{-}\), which is its conjugate base.
  • Similarly, if \(\mathrm{HSO}_3^{-}\) donates another proton, it turns into \(\mathrm{SO}_3^{2-}\).
This indicates that \(\mathrm{H}_2\mathrm{SO}_3\) has donated its protons in a stepwise manner. Each step shows the acid turning into its conjugate base. This interplay illustrates how acids and bases form pairs through the transfer of protons, a hallmark of Br酶nsted-Lowry Acid behavior.
Br酶nsted-Lowry Base
Under the Br酶nsted-Lowry theory, a base is defined as a substance that can accept a proton. The acceptance of a proton by a base results in the formation of its conjugate acid.
An example of a Br酶nsted-Lowry base is methylamine, \(\mathrm{CH}_3\mathrm{NH}_2\). When\(\mathrm{CH}_3\mathrm{NH}_2\) accepts a proton, the process can be represented as: \[\mathrm{CH}_3\mathrm{NH}_2 + \mathrm{H}^+ \rightarrow \mathrm{CH}_3\mathrm{NH}_3^+\] Here, the base \(\mathrm{CH}_3\mathrm{NH}_2\) has transformed into its conjugate acid, \(\mathrm{CH}_3\mathrm{NH}_3^+\). This proton acceptance demonstrates the essential role of bases in chemical reactions as agents that can convert into acids via proton gain.
  • The acetate ion, \(\mathrm{CH}_3\mathrm{COO}^-\), is another clear example. It accepts a proton to form acetic acid, \(\mathrm{CH}_3\mathrm{COOH}\).
  • This transformation emphasizes the capacity of a base to "receive" and stabilize an extra proton, thus altering its identity to become its conjugate acid.
Chemical Reactions
Chemical reactions involving Br酶nsted-Lowry acids and bases center around the exchange of protons. During these reactions:
  • An acid \(\text{donates}\) a proton to a base.
  • In response, the base \(\text{accepts}\) this proton.
This back-and-forth transfer is the driving force behind many important chemical processes.
This type of reaction can be visually encapsulated in a straightforward chemical equation. For example, when acetic acid \(\mathrm{CH}_3\mathrm{COOH}\) reacts with water \(\mathrm{H}_2\mathrm{O}\), \[\mathrm{CH}_3\mathrm{COOH} + \mathrm{H}_2\mathrm{O} \rightleftharpoons \mathrm{CH}_3\mathrm{COO}^- + \mathrm{H}_3\mathrm{O}^+\]This equation demonstrates acetic acid donating a proton to water.
The products are acetate and the hydronium ion \(\mathrm{H}_3\mathrm{O}^+\), both illustrating the conjugate relationship formed during the reaction.
On a broader scale, this fundamental mechanism powers various biochemical reactions in nature, showcasing its pivotal role in transforming and transferring components at the molecular level.

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Most popular questions from this chapter

Calculate \(\left[\mathrm{OH}^{-}\right]\) and \(\mathrm{pH}\) for each of the following strong base solutions: (a) \(0.182 \mathrm{M} \mathrm{KOH},(\mathbf{b}) 3.165 \mathrm{~g}\) of \(\mathrm{KOH}\) in 500.0 \(\mathrm{mL}\) of solution, (c) \(10.0 \mathrm{~mL}\) of \(0.0105 \mathrm{M} \mathrm{Ca}(\mathrm{OH})_{2}\) diluted to \(500.0 \mathrm{~mL},\) (d) a solution formed by mixing \(20.0 \mathrm{~mL}\) of 0.015 \(M \mathrm{Ba}(\mathrm{OH})_{2}\) with \(40.0 \mathrm{~mL}\) of \(8.2 \times 10^{-3} \mathrm{M} \mathrm{NaOH}\).

Ephedrine, a central nervous system stimulant, is used in nasal sprays as a decongestant. This compound is a weak organic base: $$ \mathrm{C}_{10} \mathrm{H}_{15} \mathrm{ON}(a q)+\mathrm{H}_{2} \mathrm{O}(l) \rightleftharpoons \mathrm{C}_{10} \mathrm{H}_{15} \mathrm{ONH}^{+}(a q)+\mathrm{OH}^{-}(a q) $$ A \(0.035 \mathrm{M}\) solution of ephedrine has a \(\mathrm{pH}\) of 11.33 . (a) What are the equilibrium concentrations of \(\mathrm{C}_{10} \mathrm{H}_{15} \mathrm{ON}, \mathrm{C}_{10} \mathrm{H}_{15} \mathrm{ONH}^{+},\) and \(\mathrm{OH}^{-} ?\) (b) Calculate \(K_{b}\) for ephedrine.

Indicate whether each of the following statements is correct or incorrect. (a) Every Br酶nsted-Lowry acid is also a Lewis acid. (b) Every Lewis acid is also a Br酶nsted-Lowry acid. (c) Conjugate acids of weak bases produce more acidic solutions than conjugate acids of strong bases. (d) \(\mathrm{K}^{+}\) ion is acidic in water because it causes hydrating water molecules to become more acidic. (e) The percent ionization of a weak acid in water increases as the concentration of acid decreases.

Carbon dioxide in the atmosphere dissolves in raindrops to produce carbonic acid \(\left(\mathrm{H}_{2} \mathrm{CO}_{3}\right),\) causing the \(\mathrm{pH}\) of clean, unpolluted rain to range from about 5.2 to \(5.6 .\) What are the ranges of \(\left[\mathrm{H}^{+}\right]\) and \(\left[\mathrm{OH}^{-}\right]\) in the raindrops?

At the boiling point of water \(\left(100^{\circ} \mathrm{C}\right), K_{w}=5.6 \times 10^{-13} .\) Calculate \(\left[\mathrm{H}^{+}\right]\) and \(\left[\mathrm{OH}^{-}\right]\) for a neutral solution at this temperature.

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