/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q35E Draw the geometric, linkage, and... [FREE SOLUTION] | 91影视

91影视

Draw the geometric, linkage, and ionization isomers for \(\left( {CoC{l_5}CN} \right)(CN)\)

Short Answer

Expert verified

Isomers are the chemical species which have the same molecular formula but different arrangement of atoms or ligands in space.

Step by step solution

01

of 3: Explanation

  • Geometric isomers are isomers in which the orientation of atoms in the space is relative to each other which lead to different physical and chemical properties.
  • Linkage isomers are isomers in which the bonding to the central metal atom is observed for two different atoms belonging to the same ligand
  • Ionisation isomers are the isomers in which the anionic ligands are replaced by the counter ion in the inner coordination space.
02

of 3: Diagrammatic representation

There are 8 isomers for \(\left( {{\rm{CoC}}{{\rm{l}}_5}{\rm{CN}}} \right)({\rm{CN}})\)

03

of 3: Variations of isomers

  • There are different variation of these isomers:
  • a) Only geometric isomer:\(1)\).
  • b) Only linkage isomer:\(2)\).
  • c) Geometric and linkage isomer: \(3),{\rm{ }}4)\)and\(5)\).
  • d) Geometric and ionization isomer: \(7)\)and \(8).\)
  • e) Linkage and ionization isomer: \(2)\)and\(5)\).
  • f) Geometrical, linkage and ionization isomer: \(2),{\rm{ }}3),{\rm{ }}5),{\rm{ }}6).\)

Result

There are \(8\) isomers of this molecule which have different variations.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Predict the products of each of the following reactions. (Note: In addition to using the information in this chapter, also use the knowledge you have accumulated at this stage of your study, including information on the prediction of reaction products.)

\(\begin{aligned}(a)Fe(s) + {H_2}S{O_4}(aq) \to \\(b)FeC{l_3}(aq) + NaOH(aq) \to \\(c)Mn{(OH)_2}(s) + HBr(aq) \to \\(d)Cr(s) + {O_2}(g) \to \\(e)M{n_2}{O_3}(s) + HCl(aq) \to \\(f)Ti(s) + xs{F_2}(g) \to \end{aligned}\)

Specify whether the following complexes have isomers.

\(\begin{aligned}{}(a)tetrahedral\left( {Ni{{(CO)}_2}{{(Cl)}_2}} \right)\\(b)trigonalbipyramidal\left( {Mn{{(CO)}_4}NO} \right)\\(c)\left( {Pt{{(en)}_2}C{l_2}} \right)C{l_2}\end{aligned}\)

Give the coordination numbers and write the formulas for each of the following, including all isomers where appropriate:

(a) tetrahydroxozincate(II) ion (tetrahedral)

(b) hexacyanopalladate(IV) ion

(c) dichloroaurate(I) ion (note that aurum is Latin for 鈥済old鈥)

(d) diamminedichloroplatinum(II)

(e) potassium diamminetetrachlorochromate(III)

(f) hexaamminecobalt(III) hexacyanochromate(III)

(g) dibromobis(ethylenediamine) cobalt(III) nitrate

How many unpaired electrons are present in each of the following?

\(\begin{aligned}{}(a){\left( {Co{F_6}} \right)^{3 - }}(highspin)\\(b){\left( {Mn{{(CN)}_6}} \right)^{3 - }}(lowspin)\\(c){\left( {Mn{{(CN)}_6}} \right)^{4 - }}(lowspin)\\(d){\left( {MnC{l_6}} \right)^{4 - }}(highspin)\\(e){\left( {RhC{l_6}} \right)^{3 - }}(lowspin)\end{aligned}\)

The solid anhydrous solid \(CoC{l_2}\)is blue in color. Because it readily absorbs water from the air, it is used as a humidity indicator to monitor if equipment (such as a cell phone) has been exposed to excessive levels of moisture. Predict what product is formed by this reaction, and how many unpaired electrons this complex will have.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.