91Ó°ÊÓ

(a)

• For\(\left( {{\rm{Ni}}{{({\rm{CO}})}_2}{\rm{C}}{{\rm{l}}_2}} \right)\),We can see that central metal atom \({\rm{Ni}}\)is attached to \(2\) molecules of \({\rm{CO}}\)and \(2{\rm{C}}{{\rm{l}}^ - }\)ions in tetrahedral arrangement.
• All tetrahedral positions are equivalent and molecule contains a plane of symmetry, which specifies that this molecule will not show geometrical or optical isomerism.

(b)

• For\(\left( {{\rm{Mn}}{{({\rm{CO}})}_4}{\rm{NO}}} \right)\),We can see that central metal atom \({\rm{Mn}}\)is attached to \(4\) molecules of \({\rm{CO}}\)and \(1{\rm{NO}}\)in trigonal bipyramidal arrangement. NO group can be present at equatorial or axial position.
• As this molecule cannot have mirror images, it means this molecule will not show geometrical or optical isomerism.

(c)

• For\(\left( {{\rm{Pt}}{{({\rm{en}})}_2}{\rm{C}}{{\rm{l}}_2}} \right){\rm{Cl}}{l_2}\), We can see that central metal atom \(Pt\)is attached to \(2\) molecules of ethylene diamine, which is a bidentate ligand, and \(2{\rm{C}}{{\rm{l}}^ - }\)ions.
• This means this molecule will have cis and trans isomers. Also, cis isomers will show optical isomerism, but, trans will not as it contains a plane of symmetry.

a) It does not have isomers.

b) It does not have isomers.

c) It has cis and trans isomers, in which cis isomers are optical isomers.