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Chapter 4: Q78E (page 224)

What volume of 0.0105-M HBr solution is required to titrate 125 mL of a 0.0100-MCa(OH)2 solution?

Ca(OH)2(aq) + 2HBr(aq)鉄禖补叠谤2(aq) + 2H2 O(l)

Short Answer

Expert verified

238 mL of 0.0105-M HBr solution is required to titrate 125 mL of a 0.0100-M Ca(OH)2 solution

Step by step solution

01

Given data 

This titration is between acid and base. For this formula we use

\({M_a}{V_a} = {M_b}{V_b}\)

where a = acid (HBr) and b = base (Ca(OH)2)

Molarity of HBr = 0.0105 M and Volume of HBr =??

Molarity of Ca(OH)2 = 0.0100 M Volume of Ca(OH)2 = 125 mL

02

Determine volume of HBr

Ca(OH)2(aq) + 2HBr(aq)鉄禖补叠谤2(aq) + 2H2 O(l)

\({M_a}{V_a} = {M_b}{V_b}\)

By putting the values in the above equation,

\(\begin{aligned}{}1 \times 0.0105M \times X = 0.0100\,M \times 2 \times 125\,mL\\X = \frac{{0.0100\,M \times 2 \times 125\,mL}}{{0.0105M}}\\X = 238.09\,mL\end{aligned}\)

238 mL of HBr

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