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Which solution could be used to precipitate barium ion Ba2+, in a water sample, Sodium chloride, sodium hydroxide, or sodium sulfate. What is the formula for the expected precipitate?

Short Answer

Expert verified

Sodium Sulfate is used to precipitate a barium ion.

The formula for the expected precipitate is BaSO4.

Step by step solution

01

Depending on the solubility

Sodium sulfates can be used to precipitate barium ions because, when a barium ion is dissolved in a sodium sulfate, it forms a barium sulfate, which is insoluble in water while the other is soluble in water and cannot form a precipitate with a barium ion.

02

The equation for precipitation of barium ion

\(B{a^{2 + }}\left( {aq} \right) + N{a_2}S{O_4} \to 2N{a^ + } + BaS{O_4}\left( {ppt} \right).\)

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Most popular questions from this chapter

The balanced molecular equations, write the complete ionic and net ionic equations for the following

(a)\({K_2}{C_2}{O_4}\left( {aq} \right) + Ba{\left( {OH} \right)_2}\left( {aq} \right) \to 2KOH\left( {aq} \right) + B{a_2}{C_2}{O_4}\)

(b)\(Pb{\left( {N{O_3}} \right)_2}\left( {aq} \right) + {H_2}S{O_4}\left( {aq} \right) \to PbS{O_4} + 2HN{O_3}\)

(c)\(CaC{O_3}\left( s \right) + {H_2}S{O_4}\left( {aq} \right) \to CaS{O_4} + C{O_2} + {H_2}O\)

What mass of Ca(OH)2 will react with 25.0 g of propionic acid to form the preservative calcium propionate according to the equation?

Balance the following equations:

\(\begin{array}{l}\;(a)\;PC{l_5}\left( s \right) + {H_2}O\left( l \right) \to POC{l_3}\left( l \right) + HCl\left( {aq} \right)\\\left( b \right)\,Cu\left( s \right) + HN{O_3}\left( {aq} \right) \to Cu{\left( {N{O_3}} \right)_2}\left( {aq} \right) + {H_2}O\left( l \right) + NO\left( g \right)\\\left( c \right){H_2}\left( g \right) + {I_2}\left( g \right) \to HI\left( s \right)\\\left( d \right)\,Fe\left( s \right) + {O_2}\left( g \right) \to F{e_2}{O_3}\left( s \right)\\\left( e \right)\,Na\left( s \right) + {H_2}O\left( l \right) \to NaOH\left( {aq} \right) + {H_2}\left( g \right)\\\left( f \right)\,{\left( {N{H_4}} \right)_2}C{r_2}{O_7}\left( s \right) \to C{r_2}{O_3}\left( s \right) + {N_2}\left( g \right) + {H_2}O\left( g \right)\\\left( g \right){P_4}\left( s \right) + C{l_2}\left( g \right) \to PC{l_3}\left( l \right)\\\left( h \right)PtC{l_4}\left( s \right) \to Pt\left( s \right) + C{l_2}\left( g \right)\end{array}\)

Uranium can be isolated from its ores by dissolving it as UO2(NO3)2, then separating it as solid UO2(C2O4). Addition of 0.4031 g of sodium oxalate, NaC2O4, to a solution containing 1.481 g of uranyl nitrate, UO2(NO3)2, yields 1.073 g of solid

\(Na{C_2}{O_4} + U{O_2}{\left( {N{O_3}} \right)_2} + 3{H_2}O \to U{O_2}\left( {{C_2}{O_4}} \right) \cdot 3{H_2}O + 2NaN{O_3}\)

A sample of solid calcium hydroxide, Ca(OH)2is allowed to stand in water until a saturated solution is formed. A titration of 75.00 mL of this solution with 5.00×10-2M HCl requires 36.6 mL of the acid to reach the end point.

\({\rm{Ca(OH}}{{\rm{)}}_{2({\rm{aq}})}}{\rm{ + 2HC}}{{\rm{l}}_{({\rm{aq}})}}{\rm{ }} \to {\rm{ CaC}}{{\rm{l}}_{2({\rm{aq}})}}{\rm{ + 2}}{{\rm{H}}_2}{{\rm{O}}_{({\rm{l}})}}\)

What is the molarity?

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