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Which solution could be used to precipitate barium ion Ba2+, in a water sample, Sodium chloride, sodium hydroxide, or sodium sulfate. What is the formula for the expected precipitate?

Short Answer

Expert verified

Sodium Sulfate is used to precipitate a barium ion.

The formula for the expected precipitate is BaSO4.

Step by step solution

01

Depending on the solubility

Sodium sulfates can be used to precipitate barium ions because, when a barium ion is dissolved in a sodium sulfate, it forms a barium sulfate, which is insoluble in water while the other is soluble in water and cannot form a precipitate with a barium ion.

02

The equation for precipitation of barium ion

\(B{a^{2 + }}\left( {aq} \right) + N{a_2}S{O_4} \to 2N{a^ + } + BaS{O_4}\left( {ppt} \right).\)

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\(Na{C_2}{O_4} + U{O_2}{\left( {N{O_3}} \right)_2} + 3{H_2}O \to U{O_2}\left( {{C_2}{O_4}} \right) \cdot 3{H_2}O + 2NaN{O_3}\)

Identify the atoms that are oxidized and reduced, the change in the oxidation state for each, and the oxidizing and reducing agents in each of the following equations:

(a)\(Mg\left( s \right) + NiC{l_2}\left( {aq} \right) \to MgC{l_2}\left( {aq} \right) + Ni\left( s \right)\)

(b)\(PC{l_3}\left( l \right) + C{l_2}\left( g \right) \to PC{l_5}\left( s \right)\)

(c)\({C_2}{H_4}\left( g \right) + 3{O_2}\left( g \right) \to 2C{O_2}\left( g \right) + 2{H_2}O\left( g \right)\)

(d)\(Zn\left( s \right) + {H_2}S{O_4}\left( {aq} \right) \to ZnS{O_4}\left( {aq} \right) + {H_2}\left( g \right)\)

(e) \(2{K_2}{S_2}{O_3}\left( s \right) + {I_2}\left( s \right) \to {K_2}{S_4}{O_6}\left( s \right) + 2KI\left( s \right)\)

(f) \(3Cu\left( s \right) + 8HN{O_3}\left( {aq} \right) \to 3Cu{\left( {N{O_3}} \right)_2}\left( {aq} \right) + 2NO\left( g \right) + 4{H_2}O\left( l \right)\)

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