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Chapter 4: Q91E (page 225)

A sample of solid calcium hydroxide, Ca(OH)2is allowed to stand in water until a saturated solution is formed. A titration of 75.00 mL of this solution with 5.00脳10-2M HCl requires 36.6 mL of the acid to reach the end point.

\({\rm{Ca(OH}}{{\rm{)}}_{2({\rm{aq}})}}{\rm{ + 2HC}}{{\rm{l}}_{({\rm{aq}})}}{\rm{ }} \to {\rm{ CaC}}{{\rm{l}}_{2({\rm{aq}})}}{\rm{ + 2}}{{\rm{H}}_2}{{\rm{O}}_{({\rm{l}})}}\)

What is the molarity?

Short Answer

Expert verified

The molarity of solid sample of calcium hydroxide is 0.0122 M.

Step by step solution

01

Given data 

According to the question, it is given that

The concentration of hydrochloric acid is \({\rm{5}}{\rm{.00 }} \times {\rm{ 1}}{{\rm{0}}^{ - 2}}{\rm{ M}}\)and the volume is 36.6 ml.

The volume of calcium hydroxide is 75 ml and the concentration is unknown.

Moreover, 1 mole of calcium hydroxide reacts with 2 moles of hydrochloric acid.

02

Molarity of the calcium hydroxide 

Thus, to calculate the concentration or molarity of calcium hydroxide, we can use:

\({{\rm{n}}_{\rm{H}}}{{\rm{M}}_{\rm{H}}}{{\rm{V}}_{\rm{H}}}\,{\rm{ = }}{{\rm{n}}_{\rm{c}}}{{\rm{M}}_{\rm{c}}}{{\rm{V}}_{\rm{c}}}\)

Here, \({{\rm{n}}_{\rm{H}}}{\rm{, }}{{\rm{M}}_{\rm{H}}}{\rm{, }}{{\rm{V}}_{\rm{H}}}\,\)is moles, molarity and volume of HCl whereas \({{\rm{n}}_{\rm{c}}}{\rm{, }}{{\rm{M}}_{\rm{c}}}{\rm{, }}{{\rm{V}}_{\rm{c}}}\) is moles, molarity and volume of calcium hydroxide.

\({\rm{1 }} \times {\rm{ 5 }} \times {\rm{ }}{10^{ - 2}}{\rm{ }} \times {\rm{ 36}}{\rm{.6 }}\,{\rm{ = 2 }} \times {\rm{ }}{{\rm{M}}_{\rm{c}}}{\rm{ }} \times {\rm{ }}75\)

\({{\rm{M}}_{\rm{c}}}{\rm{ = 0}}{\rm{.0122 M}}\)

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Most popular questions from this chapter

Classify the following as acid-base reaction or oxidation-reduction reactions.

(a)\(N{a_2}S\left( {aq} \right) + 2HCl\left( {aq} \right) \to 2NaCl\left( {aq} \right) + {H_2}S\left( g \right)\)

(b)\(2Na\left( s \right) + 2HCl\left( {aq} \right) \to 2NaCl\left( {aq} \right) + {H_2}\left( g \right)\)

(c)\(Mg\left( s \right) + C{l_2}\left( g \right) \to MgC{l_2}\left( s \right)\)

(d)\(MgO\left( s \right) + 2HCl\left( {aq} \right) \to MgC{l_2}\left( {aq} \right) + {H_2}O\left( l \right)\)

(e)\({K_3}P\left( s \right) + 2{O_2}\left( g \right) \to {K_3}P{O_4}\left( s \right)\)

(f)\(3KOH\left( {aq} \right) + {H_3}P{O_4}\left( {aq} \right) \to {K_3}P{O_4}\left( {aq} \right) + 3{H_2}O\left( l \right)\)

Determine the oxidation states of the elements in the compounds listed. None of the oxygen-containing compounds are peroxides or superoxides.

(a) \({H_2}S{O_4}\)

(b) \(Ca{\left( {OH} \right)_2}\)

(c) \(BrOH\)

(d) \(ClN{O_2}\)

(e) \(TiC{l_4}\)

(f) \(NaH\)

Balance the following equations:

\(\begin{array}{l}\;(a)\;PC{l_5}\left( s \right) + {H_2}O\left( l \right) \to POC{l_3}\left( l \right) + HCl\left( {aq} \right)\\\left( b \right)\,Cu\left( s \right) + HN{O_3}\left( {aq} \right) \to Cu{\left( {N{O_3}} \right)_2}\left( {aq} \right) + {H_2}O\left( l \right) + NO\left( g \right)\\\left( c \right){H_2}\left( g \right) + {I_2}\left( g \right) \to HI\left( s \right)\\\left( d \right)\,Fe\left( s \right) + {O_2}\left( g \right) \to F{e_2}{O_3}\left( s \right)\\\left( e \right)\,Na\left( s \right) + {H_2}O\left( l \right) \to NaOH\left( {aq} \right) + {H_2}\left( g \right)\\\left( f \right)\,{\left( {N{H_4}} \right)_2}C{r_2}{O_7}\left( s \right) \to C{r_2}{O_3}\left( s \right) + {N_2}\left( g \right) + {H_2}O\left( g \right)\\\left( g \right){P_4}\left( s \right) + C{l_2}\left( g \right) \to PC{l_3}\left( l \right)\\\left( h \right)PtC{l_4}\left( s \right) \to Pt\left( s \right) + C{l_2}\left( g \right)\end{array}\)

What volume of 0.0105-M HBr solution is required to titrate 125 mL of a 0.0100-MCa(OH)2 solution?

Ca(OH)2(aq) + 2HBr(aq)鉄禖补叠谤2(aq) + 2H2 O(l)

Write a balanced equation for the decomposition of ammonium nitrate to form molecular nitrogen, molecular oxygen and water. (Hint Balance oxygen last, since it is present in more than one molecule on the right side of the equation)
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