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Chapter 12: QCYL (page 651)

(a) Multiply 2.334 cm and 0.320 cm.(b) Divide 55.8752 m by 56.53 s.

Short Answer

Expert verified

(a) The result is 0.747cm2 (rounded to three significant figures).

(b) The result is 0.9884 m/s (rounded to four significant figures).

Step by step solution

01

Significant figures

All the digits in measurement, including the uncertain last digit, are called significant figures or significant digits.

02

Determining the significant figures in multiplication and division

2.334cm 脳 0.320 cm

=0.74688cm2

The result is 0.747cm2 (rounded to three significant figures).

(b)\(\begin{array}{l}\frac{{55.8752\,{\rm{m}}}}{{56.53\,{\rm{s}}}}\\ = 0.9884167699\,{\rm{m/s}}\\ = 0.9884\,{\rm{m/s}}\end{array}\)

The result is 0.9884 m/s (rounded to four significant figures).

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How much and in what direction will each of the following effect the rate of the reaction:

CO(g) + \({\bf{NO}}{}_{\bf{2}}\) (g)鉄� \({\bf{CO}}{}_{\bf{2}}\) (g) + NO(g) if the rate law for the reaction is rate =\({\bf{k(NO}}{}_{\bf{2}}{{\bf{)}}^{\bf{2}}}{\bf{a}}\)?

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When heated to 499\({\bf{^\circ C}}\), cyclopropane rearranges (isomerizes) and forms propene with a rate constant of\({\bf{5}}{\bf{.95 \times 1}}{{\bf{0}}^{{\bf{ - 4}}}}{{\bf{s}}^{{\bf{ - 1}}}}\). What is the half-life of this reaction? What fraction of the cyclopropane remains after 0.75 h at 499.5\({\bf{^\circ C}}\)?
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