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What is the half-life for the first-order decay of carbon-14?

\({{\bf{\;}}_{\bf{6}}}^{{\bf{14}}}{\bf{C}}\)鉄禱({_{\bf{7}}^{{\bf{14}}}}{\bf{N + }}{{\bf{e}}^{\bf{ - }}}\)

The rate constant for the decay is\({\bf{1}}{\bf{.21 \times 1}}{{\bf{0}}^{{\bf{ - 4}}}}{\bf{yea}}{{\bf{r}}^{{\bf{ - 1}}}}\).

Short Answer

Expert verified

Half-life periods may be defined as the time period at which half the concentration of reactant converts into the product. The half-life period of the first-order decay of carbon-14 is 5700 years which has a rate constant \({\bf{1}}{\bf{.21 \times 1}}{{\bf{0}}^{{\bf{ - 4}}}}{\bf{yea}}{{\bf{r}}^{{\bf{ - 1}}}}\).

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Step by step solution

01

Reaction Rate

The reaction involved the effective collision of two reactants to produce the desired products. Reactions can be natural, which occur in the surrounding environment, whereas it can be artificially done in the laboratory to form a desired required product.

The reaction rate can be defined as the reaction speed to produce the products. The reaction rate can be slow, fast or moderate. The reaction can take a lesser than millisecond to produce products, or it can take years to produce the desired product.

The half-life period can be defined as the time period at which half the concentration of the reactants gets converted into a product.

02

Explanation

The half-life period of the first-order decay of carbon-14 is:

\(Half - life{\bf{ }}period{\bf{ }} = {\bf{ }}\frac{{\ln {\bf{ }}\left( 2 \right)}}{k}\)

The rate constant for the decay of Carbon-14= \({\bf{1}}{\bf{.21 \times 1}}{{\bf{0}}^{{\bf{ - 4}}}}{\bf{yea}}{{\bf{r}}^{{\bf{ - 1}}}}\)

\(Half - life{\bf{ }}period{\bf{ }} = {\bf{ }}\frac{{0.693}}{{1.21{\bf{ }} \times {\bf{ }}{{10}^{ - 4}}yea{r^{ - 1}}}}\)

Half-life period = 5727 years or 5730 years.

Hence, the half-life period of the first-order decay of carbon-14 is 5700 years which has rate constant \({\bf{1}}{\bf{.21 \times 1}}{{\bf{0}}^{{\bf{ - 4}}}}{\bf{yea}}{{\bf{r}}^{{\bf{ - 1}}}}\).

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Most popular questions from this chapter

Ozone decomposes to oxygen according to the equation\({\bf{2}}{{\bf{O}}_{\bf{3}}}{\bf{(g)}} \to {\bf{3}}{{\bf{O}}_{\bf{2}}}{\bf{(g)}}\). Write the equation that relates the rate expressions for this reaction in terms of the disappearance of\({{\bf{O}}_{\bf{3}}}\)and the formation of oxygen.

Thefollowingdatahave been determined for the reaction: \({{\bf{I}}^{\bf{ - }}}{\bf{ + OC}}{{\bf{l}}^{\bf{ - }}} \to {\bf{I}}{{\bf{O}}^{\bf{ - }}} + {\bf{C}}{{\bf{l}}^{\bf{ - }}}\)

1

2

3

\({{\bf{(}}{{\bf{I}}^{\bf{ - }}}{\bf{)}}_{{\bf{initial}}}}\)(M)

0.10

0.20

0.30

\({{\bf{(OC}}{{\bf{l}}^{\bf{ - }}}{\bf{)}}_{{\bf{initial}}}}\)(M)

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Rate(mol/l/s)

\({\bf{3}}{\bf{.5*1}}{{\bf{0}}^{{\bf{ - 4}}}}\)

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Determine the rate equation and the rate constant for this reaction.

Tripling the concentration of a reactant increases the rate of a reaction nine-fold. With this knowledge, answer the following questions:

  1. What is the order of the reaction with respect to that reactant?
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What is the rate equation for the elementary termolecular reaction A + 2B鉄秔roducts? For 3A鉄秔roducts?

Go to the PhET Reactions & Rates interactive. Use the Single Collision tab to represent how the collision between monatomic oxygen (O) and carbon monoxide (CO) results in the breaking of one bond and the formation of another. Pull back on the red plunger to release the atom and observe the results. Then, click on 鈥淩eload Launcher鈥 and change to 鈥淎ngled shot鈥 to see the difference.

  1. What happens when the angle of the collision is changed?
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