/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q102E Question: Describe the factors r... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 9: Q102E (page 515)

Question: Describe the factors responsible for the deviation of the behaviour of real gases from that of an ideal gas.

Short Answer

Expert verified

Actual gases deviate from their ideal condition due to changes in temperature, pressure, and van der Waals attractions. Furthermore, when the size of the gas molecules grows larger, the gas's ideal behaviour begins to vary.

Step by step solution

01

Step 1: Define Gas

One of the four fundamental states of matter, a gas is made up of particles with no definite volume or structure.

02

Describing the factor responsible for the behaviour of real gas

The departure of real gases from that of an ideal gas is caused by lowering the temperature, raising the pressure, and van der Waals attractions. In addition, when the size of the gas molecules grows larger, the gas begins to diverge from its optimum behaviour.

Therefore, lowering the temperature, rising the pressure, and van der Waals attractions cause actual gases to diverge from their ideal state. Furthermore, when the size of the gas molecules increases, the gas begins to deviate from its ideal behaviour.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Question: Explain why the numbers of molecules are not identical in the left- and right-hand bulbs shown in the centre illustration of Figure \({\rm{9}}{\rm{.27}}\).

Question: When two cotton plugs, one moistened with ammonia and the other with hydrochloric acid, are simultaneously inserted into opposite ends of a glass tube that is 87.0 cm long, a white ring of \({\rm{N}}{{\rm{H}}_{\rm{4}}}{\rm{Cl}}\) forms where gaseous \({\rm{N}}{{\rm{H}}_{\rm{3}}}\) and gaseous \({\rm{HCl}}\) first come into contact. (Hint: Calculate the rates of diffusion for both \({\rm{N}}{{\rm{H}}_{\rm{3}}}\) and \({\rm{HCl}}\), and find out how much faster \({\rm{N}}{{\rm{H}}_{\rm{3}}}\) diffuses than \({\rm{HCl}}\).) \({\rm{N}}{{\rm{H}}_{\rm{3}}}{\rm{(g) + HCl(g)}} \to {\rm{N}}{{\rm{H}}_{\rm{4}}}{\rm{Cl(s)}}\)

At approximately what distance from the ammonia moistened plug does this occur?

Question: Heavy water, \({{\rm{D}}_{\rm{2}}}{\rm{O}}\) (molar mass\({\rm{ = 20}}{\rm{.03 gmo}}{{\rm{l}}^{{\rm{ - 1}}}}\)), can be separated from ordinary water, \({{\rm{H}}_{\rm{2}}}{\rm{O}}\) (molar mass\({\rm{ = 18}}{\rm{.01}}\)), as a result of the difference in the relative rates of diffusion of the molecules in the gas phase. Calculate the relative rates of diffusion of \({{\rm{H}}_{\rm{2}}}{\rm{O}}\) and \({{\rm{D}}_{\rm{2}}}{\rm{O}}\).

An alternate way to state Avogadro鈥檚 law is 鈥淎ll other things being equal, the number of molecules in a gas is directly proportional to the volume of the gas.鈥� (a) What is the meaning of the term 鈥渄irectly proportional?鈥� (b) What are the 鈥渙ther things鈥� that must be equal?

In addition to the data found in Figure \({\rm{9}}{\rm{.13}}\), what other information do we need to find the mass of the sample of air used to determine the graph?
See all solutions

Recommended explanations on Chemistry Textbooks

Chemical Analysis

Read Explanation

Making Measurements

Read Explanation

Organic Chemistry

Read Explanation

Nuclear Chemistry

Read Explanation

Inorganic Chemistry

Read Explanation

Physical Chemistry

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.