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Chapter 3: Q67 E (page 172)

What volume of a 0.20-M K2SO4 solution contains 57 g of K2SO4?

Short Answer

Expert verified

1.6 L of 0.20 M K2SO4solutioncontains 57 g of K2SO4.

Step by step solution

01

Given data

Molarity = number of moles / liter of solution

Given

Molarity =0.20M

MassK2SO4=57g

1 mol S=32.065g

1 mol K =39.098g

1 mol O =15.999g

02

Determine the volume

Calculation

Molar Mass

\(\begin{align}{K_2}S{O_4} &= 2\left( {39.098} \right) + 32.065 + 4\left( {15.999} \right)\\ &= 174.257gmo{l^{ - 1}}\end{align}\)

Molarity = number of moles / liter of solution

Solution volume = number of moles / molarity

Substitute the values in the formula above.

\(\frac{{57g\left( {\frac{{1\,mol}}{{174.257g}}} \right)}}{{0.20\frac{{mol}}{L}}} = 1.6L\)

Therefore, the volume needs to be required is 1.6L

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