Q7 E A friend tells you \({{\rm{N}}_{... [FREE SOLUTION]

Chapter 8: Q7 E (page 446)

A friend tells you \({{\rm{N}}_{\rm{2}}}\)has three \({\rm{\pi }}\)bonds due to overlap of the three p-orbitals on each N atom. Do you agree?

Short Answer

Expert verified

In the given structure; \({N_2},N \equiv N\), there is one sigma and two pi bonds because one sigma bond is formed by the axial overlapping of two p-orbital of each nitrogen atom. After the formation of one sigma bond; remaining p-orbital overlaps by sidewise and will from two pi bond also.

Step by step solution

Definition of Concept

The sigma bond is formed when atomic orbitals involved in the formation of a molecular orbital overlap along the internuclear axis.

The bond formed is known as a pi-bond when p-orbitals involved in bond formation overlap sideways.

Explain \({{\rm{N}}_{\rm{2}}}\) has three \({\rm{\pi }}\) bonds due to overlap of the three p-orbitals on each N atom

Considering the given information:

\({N_2},N \equiv N\)

Only a single bond is always a sigma bond, whereas a double bond has one sigma bond and one pi bond, and a triple bond has one sigma bond and two pi bonds.

Therefore, one sigma bond is formed by the axial overlapping of two p-orbitals of each nitrogen atom, the structure \({N_2},N \equiv N\) has one sigma and two pi bonds. Following the formation of one sigma bond, the remaining p-orbital overlaps sideways, resulting in the formation of two pi bonds.