/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q5 E Use valence bond theory to expla... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Use valence bond theory to explain the bonding in\({{\rm{O}}_{\rm{2}}}\). Sketch the overlap of the atomic orbitals involved in the bonds in \({{\rm{O}}_{\rm{2}}}\).

Short Answer

Expert verified

The molecules of oxygen contains a double bond consisting of sigma and pi bond.

Step by step solution

01

Definition of Concept

The sigma bond is formed when two half-filled atomic orbitals involved in the formation of a molecular orbital overlap along the internuclear axis.

The bond formed is a pi-bond when half-filled p-orbitals involved in bond formation overlap sideways.

02

Sketch the overlap of the atomic orbitals involved in the bonds

The bonding in\({{\rm{O}}_{\rm{2}}}\)can be explained in following ways:

A sigma bond and a pi-bond make up the double bond in the oxygen molecule. Two half-filled p-orbitals from each atom overlap along their internuclear axis when two oxygen atoms approach each other, forming a sigma bond. As shown in the diagram, a pi-bond is formed when one atom's second half-filled p-orbital overlaps a similar p-orbital of the other atom sideways.

Therefore, the sigma and pi bonds in oxygen molecules form a double bond.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.