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Chapter 4: Q4.54P (page 180)

Sodium hydroxide is used extensively in acid-base titrations because it is a strong, inexpensive base. A sodium hydroxide solution was standardized by titrating 25.00 mL of 0.1528 M standard hydrochloric acid. The initial buret reading of the sodium hydroxide was 2.24 mL, and the final reading was 39.21 mL. What was the molarity of the base solution?

Short Answer

Expert verified

The molarity of the base solution is 0.103 M NaOH.

Step by step solution

01

first write down the balanced molecular equation:

NaOH(aq)+2HCl(aq)鈫�NaCl(aq)+H2O(l)

02

To find out the molarity of the base solution, first, we have to calculate the moles of sodium hydroxide:

Given values are:

volumeofstandard0.1528MHClsolution=25mlinitialburetereading=2.24mlfinalburetereading=39.21ml

Moles ofSodium hydroxide:

molesofNaOH=(25mlH2SO4)(1lit1000ml)(0.1528molHCl1litHClsolution)(1molNaOH1molHCl)

=3.82x10-3molNaOH

The molarity of the base solution is:

molarityofNaOH=molesofNaOHvolumeofNaOH

=3.82x10-3molNaOH(39.21ml-2.24ml)(1lit1000ml)

=0.103MNaOH

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