91Ó°ÊÓ

In figure A, solid AgCl is formed and the remaining ions are Cu²⁺, Cl^-, and Mg²⁺.

In figure B, solid MgCl₂ is formed and the remaining ions are Cu²⁺ and Cl^-.

In figure C, solid CuCl₂ is formed and the remaining ions are Ag⁺, Cl^-, and Mg²⁺.

In figure D, solid CuCl₂ is formed and the remaining ions are Cl^-, and Mg²⁺.

According to the solubility rules, AgCl is insoluble and MgCl₂ and CuCl₂ are soluble. SO, in the mixture, AgCl should be insoluble and MgCl₂ and CuCl₂ should be present in the form of ions.

Thus, figure A represents the resulting mixture.

In figure A, there are 12 spheres. It means that each sphere consist of 5.0x10^-3mol of ions.

Total number of moles of ions are,

$\frac{\mathbf{5}\mathbf{.}\mathbf{0}\mathbf{×}{\mathbf{10}}^{\mathbf{-}\mathbf{3}}\mathbf{mol}}{\mathbf{1}\mathbf{sphere}}\mathbf{×}\mathbf{12}\mathbf{spheres}\mathbf{=}\mathbf{0}\mathbf{.}\mathbf{060}\mathbf{}\mathbf{moles}$

Now, the concentration of the ions is,

$$\begin{gathered} \mathbf{Concentration}\mathbf{=}\frac{\mathbf{number}\mathbf{}\mathbf{of}\mathbf{}\mathbf{moles}}{\mathbf{Volume}\mathbf{}\mathbf{inL}} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\frac{\mathbf{0}\mathbf{.}\mathbf{060}\mathbf{mol}}{\mathbf{0}\mathbf{.}\mathbf{05}\mathbf{L}} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{1}\mathbf{.}\mathbf{2}\mathbf{M} \end{gathered}$$

Thus, the concentration of the ions which are dissolved is 1.2 M.

In figure A, there are 4 spheres of Ag. The mass of solid AgCl is,

$\mathbf{4}\mathbf{}\mathbf{Ag}\mathbf{}\mathbf{spheres}\mathbf{×}\frac{\mathbf{5}\mathbf{.}\mathbf{0}\mathbf{×}{\mathbf{10}}^{\mathbf{-}\mathbf{3}}\mathbf{mol}\mathbf{}\mathbf{Ag}}{\mathbf{1}\mathbf{sphere}}\mathbf{×}\frac{\mathbf{1}\mathbf{mol}\mathbf{}\mathbf{AgCI}}{\mathbf{1}\mathbf{mol}\mathbf{}\mathbf{Ag}}\mathbf{×}\frac{\mathbf{143}\mathbf{.}\mathbf{4}\mathbf{g}\mathbf{}\mathbf{AgCI}}{\mathbf{1}\mathbf{mol}\mathbf{}\mathbf{AgCI}}\mathbf{=}\mathbf{2}\mathbf{.}\mathbf{9}\mathbf{g}\mathbf{}\mathbf{AgCI}$

Thus, the total mass of the solid is 2.9 g.