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Chapter 3: Q41P (page 132)

A sample of 0.600 mol of a metal M reacts completely withexcess fluorine to form 46.8 g ofMF2.
(a) How many moles of F are in the sample of that forms?
(b) How many grams of M are in this sample ofMF2
(c) What element is represented by the symbol M?

Short Answer

Expert verified
  1. The moles of F is1.2 mol.
  2. The grams of M is24 g.
  3. The element is represented asCalcium (Ca).

Step by step solution

01

Calculation of the moles of F

The moles of sample is 0.600 mol. Since the chemical formula of compound isMF2

M+F2鈫�MF2

This states that 2 mol of F is equal to 0.600 mol ofMF2

From the given data,

role="math" localid="1657088953138" n(F)=2脳n(MF2)n(F)=2脳0.6moln(F)=1.2mol

02

Determine the mass of M

The mass of M is calculated as:

m(M)=m(MF2)-m(F)m(M)=46.8g-1.2脳19gm(M)=46.8g-22.8gm(M)=24g

03

Determine the representation of element having symbol M

The molar mass of M is calculated as:

MolarmassofM=massofMmolesofM=24g0.600mol=40g/mol

Thus, the element is Calcium.

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Most popular questions from this chapter

In 1961, scientists agreed that the atomic mass unit (amu) would be defined as 1/12 the mass of an atom of 12C. Before then, it was defined as 1/16 the average mass of an atom of naturally occurring oxygen (a mixture of 16O, 17O, and 18O). The current atomic mass of oxygen is 15.9994 amu. (a) Did Avogadro鈥檚 number change after the definition of an amu changed and, if so, in what direction? (b) Did the definition of the mole change? (c) Did the mass of a mole of a substance change? (d) Before 1961, was Avogadro鈥檚 number 6.02脳1023 (when considered to three significant figures), as it is today?

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