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Chapter 3: Q3.99P (page 89)

Calculate each of the following quantities: (a) Molarity of the solution resulting from dissolving 46.0 g of silver nitrate in enough water to give a final volume of 335 mL (b) Volume in liters of 0.385 M manganese (II) sulfate that contains 63.0 g of solute (c) Volume in milliliters of 6.44脳10-2 M adenosine triphosphate (ATP) that contains 1.68 mmol of ATP.

Short Answer

Expert verified
  1. The molarity of the solution resulting from dissolving 46.0g of silver nitrate in enough water to give a final volume of 335mLis a
  2. The volume in liters of 0.385 M manganese (II) sulfate that contains 63.0 g of solute is a
  3. The volume in milliliters of 6.44脳10-2 M adenosine triphosphate (ATP) that contains 1.68 m mol of ATP is 26.1 mL ATP solution

Step by step solution

01

Finding the molarity

a.Multiply the mass of AgNO3 by the molar mass reciprocal to find mole number.

Molesof鈥AgNO3=46鈥g鈥AgNO3脳mol鈥AgNO3169.87鈥g鈥NO3鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥=0.271鈥mol鈥AgNO3.

Now, divide the mole number calculated above by the given solution volume to find the molarity solution.

Molarity=0.271鈥mol鈥AgNO3335脳10-3鈥L鈥soln鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥=0.809鈥鈥M.

02

Finding Volume of solution

b. Multiply the given MnSO4 mass by the molar mass reciprocal to find the mole number present in the solution.

Moles鈥of鈥MnSO4=63鈥g鈥MnSO4脳mol鈥MnSO4151鈥g鈥MnSO4\hfill鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥=0.117鈥mol鈥鈥MnSO4.Volume鈥of鈥the鈥solution=0.417鈥mol鈥MnSO40.385鈥mol鈥MnSO4L鈥soln鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥=1.08鈥鈥L.

03

Finding the volume in milliliters

c.The given mole number of ATP can be divided by the given molarity of the solution to find the solution鈥檚 volume.

Volume鈥of鈥the鈥solution=1.68脳10-3鈥mol鈥ATP6.44脳10-2鈥mol鈥ATPL鈥soln鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥=0.0261鈥鈥L鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥鈥=26.1鈥鈥mL.

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