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Chapter 3: Q.3.105P (page 89)

How many grams of NaH2PO4 are needed to react with 43.74 mL of 0.285 M NaOH?

NaH2PO4(s)+2NaOH(aq)→Na3PO4(aq)+2H2O(l)

Short Answer

Expert verified

The mass of NaH2PO4needed to reactwith 43.74 mL of 0.285 M NaOHis 0.747 g of NaH2PO4.

Step by step solution

01

Calculating the number of moles of HCl

Calculate the number of moles of HCl needed to react with 43.74 mL of sodium hydroxide.

Moles of NaH2PO4=43.74×10-3L soln×0.285 mol HCl1 Lsoln×1 mol NaH2PO42 mol NaH2PO4                                           =6.23×10-3mol NaH2PO4.

02

Calculating the number of moles

Calculate the mass of NaH2PO4as shown below:

Mass of NaH2PO4=6.23×10-3 mol NaH2PO4×119.98 g NaH2PO41 mol NaH2PO4                                          =0.747 g NaH2PO4.

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