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Chapter 3: Q.3.105P (page 89)

How many grams of NaH2PO4 are needed to react with 43.74 mL of 0.285 M NaOH?

NaH2PO4(s)+2NaOH(aq)→Na3PO4(aq)+2H2O(l)

Short Answer

Expert verified

The mass of NaH2PO4needed to reactwith 43.74 mL of 0.285 M NaOHis 0.747 g of NaH2PO4.

Step by step solution

01

Calculating the number of moles of HCl

Calculate the number of moles of HCl needed to react with 43.74 mL of sodium hydroxide.

Moles of NaH2PO4=43.74×10-3L soln×0.285 mol HCl1 Lsoln×1 mol NaH2PO42 mol NaH2PO4                                           =6.23×10-3mol NaH2PO4.

02

Calculating the number of moles

Calculate the mass of NaH2PO4as shown below:

Mass of NaH2PO4=6.23×10-3 mol NaH2PO4×119.98 g NaH2PO41 mol NaH2PO4                                          =0.747 g NaH2PO4.

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Most popular questions from this chapter

Many metals react with oxygen gas to form the metal oxide. For example, calcium reacts as follows:

2Ca(s)+O2(g)→2CaO(s)

You wish to calculate the mass of calcium oxide that can be prepared from 4.20 g of and 2.80 g of O2

(a) How many moles of CaO can be produced from the given mass of Ca ?

(b) How many moles of CaO can be produced from the given mass ofO2

(c) Which is the limiting reactant?

(d) How many grams of CaO can be produced?

List three ways compositional data may be given in a problem that involves finding an empirical formula.

Write balanced equations for each of the following by inserting the correct coefficients in the blanks:

  1. _Cu(NO3)2(aq)+_KOH(aq)→_Cu(OH)2(s)+_KNO3(aq)
  2. _BCl3(g)+_H2O(l)→_H3BO3(s)+_HCl(g)
  3. _CaSiO3(s)+_HF(g)→_SiF4(g)+_CaF2(s)+_H2O(l)
  4. _(CN)2(g)+_H2O(l)→_H2C2O4(aq)+_NH3(g)

How does a balanced chemical equation apply the law of conservation of mass?

Each of the following balances weighs the indicated numbers of atoms of two elements:

Which element-left, right, or neither,
(a) Has the higher molar mass?
(b) Has more atoms per gram?
(c) Has fewer atoms per gram?
(d) Has more atoms per mole?
See all solutions

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