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Chapter 3: Q3.104P (page 89)

How many milliliters of 0.383 M HCl are needed to react with 16.2 g of CaCO3?

2HCl(aq)+CaCO3(s)→CaCl2(aq)+CO2(g)+H2O(l)

Short Answer

Expert verified

The amount of solution needed to react with 16.2 g ofCaCO3is an 846 mL HCl solution.

Step by step solution

01

Calculating the number of moles of HCl

Calculate the number of moles of HCl needed to react with 16.2 g of Calcium chloride.

MolesofCaCO3=16.2 g CaCO3×1 mol CaCO3100.09 g CaCO3×2 mol HCl1 mol CaCO3                                        =0.324  mol  HCl.

02

Calculating the volume of solution

Calculate the volume of the solution needed as shown below:

Volume of solution=0.324 mol HCl0.383 mol HClL soln                                             =0.846  L solution or 846 mL solution.

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