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Chapter 5: Q5.29P (page 228)

If 1.47脳10-3of argon occupies a 75.0-mL container at 26.掳C, what is the pressure (in torr)?

Short Answer

Expert verified

Answer

The pressure of the gas is 365 torr.

Step by step solution

01

Ideal gas law

The ideal gas law equation is,

PV=nRT

The ideal gas law for the given condition can be written as,

P=nRTV

Here,

V is the volume (75.0mL=0.075鈥�L).

T is the temperature (26掳C=299K).

n is the number of moles (1.47脳10-3mol).

02

Determination of the pressure.

The pressure of the gas is,

P=nRTVP=(1.47脳10-3mol)脳0.0821LatK-1mol-1脳299K0.075LP=0.48atm

Conversion of the unit of pressure from atm to torr,

1torr=0.00132atm

And,

0.481atm脳1torr0.00132

Thus, the pressure of the gas is 365 torr.

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