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Chapter 14: Q. 14.15 (page 481)

Draw the condensed structural formula for the ester formed when each of the following reacts with methyl alcohol:

a. acetic acid

b. pentanoic acid

Short Answer

Expert verified

(part a)

(part b)

Step by step solution

01

Introduction (part a)

Carboxylic acids are weak acids that reduce basic by releasing hydrogen ion salts. To generate a methyl group having carbonyl group, either carboxyl group of both a carboxyl group is linked to both an aromatic rings. An methyl or benzyl component may engage to the carboxyl member.

02

Given Information (part a) 

Formation seems to be a procedure wherein the carboxylic acid mixes with such an alcohol that make compounds in the presence of a catalyst.

03

Explanation (part a)

(part a) The ester synthesized when acetic acid reactions using methane alconol has had the given reduced equation:

04

Given Information (part b) 

Formation seems to be a procedure wherein the carboxylic acid mixes with such an alcohol that make compounds in the presence of a catalyst.

05

Explanation (part b)

(part b) The ester created when pentanoic acid combines using methyl alconol really does have the same reduced general formula:

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Draw the condensed structural formulas for aand band lineangle formulas for c and d:(14.1,14.3)

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b. 2-methylpentanamide

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d. N,N-dimethyl ethanamide
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