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Question: I-mart is a discount optical shop that can fill most prescription orders in around 1 hour. The management is analyzing the processes at the store. There currently is one person assigned to each task below. The optometrist assigned to task B takes an hour off for lunch and the other employees work the entire day.

Task	Time
Greet/register the patient	2 minutes
An optometrist conducts an eye exam	25 minutes
Frame/lenses selection	20 minutes
Glasses made (the process can run 6 pairs of glasses at the same time).	60 minutes
Final fitting	5 minutes

For a typical 10-hour retail day (10 a.m.鈥�8 p.m.), the manager would like to calculate the following:

a. What is the current maximum output of the process per day (assuming every patient requires glasses)?

b. If another person were added, where would be the logical place?

c. What effect would a mail-order lab (where the glasses are made off-site and returned in 5鈥�7 days) have on the process?

Step by step solution

01

(a) The current maximum output of the process per day.

Maximum output is not given

Overall hours of work from10 a.m. - 8 p.m. is 10 a.m.

Hours of work for optometrists are 9 hours (10 hours + 1-hourlunch break).

In given work time we can maximize output for all work time and is necessary to finish the work in the given time.

The maximum output for I-mart every day is the task with the least output.

The formula of output per day = (1 hour (minutes) / Time taken) x Number of working hours.

Note: 6 glasses can be made parallel.

Though the maximum outputis 21.6 glasses per day

02

(b) If another person were added, the logical place

If asecond employee might be included, then it must go for Task B i.e., optometrist conduct eye check, since this is the roadblock to increased output. While Task B's output will increase to 43 glasses and the store I-mart's output will be 30 glasses each day.

Task C has the next lowest output.

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