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Question: The following tasks are to be performed on an assembly line:

Task

Seconds

Task That Must Precede

A

20

-

B

7

A

C

20

B

D

22

B

E

15

C

F

10

D

G

16

E, F

H

8

G

The workday is seven hours long. Demand for the completed product is 750 per day.

a. Find the cycle time required to produce 750 units per day.

b. What is the theoretical number of workstations?

c. Draw the precedence diagram.

d. Balance the line using sequential restrictions and the longest-operating-time rule.

e. What is the efficiency of the line balanced as in part (d), assuming it is running at the cycle time from part (a)?

f. Suppose that demand rose from 750 to 800 units per day. What would you do? Show any amounts or calculations.

g. Suppose that demand rose from 750 to 1,000 units per day. What would you do? Show any amounts or calculations.

Short Answer

Expert verified
  1. The cycle time is 33.6 seconds.
  2. The number of workstations should be 3.51.
  3. The efficiency of line balancing is 70.2%.

The following are the qualities of the assembly line:

Everyday demand=750UnitsProduction time  = 7 hours=7×60×60=25200 secondsTotaltask time = 118 seconds

Step by step solution

01

Step-by-Step SolutionStep 1: (a) Workstation cycle time

It could be calculated by dividing the production time per dayby desired output per day.

Workstation cycle time=Production per dayDesired output per day= 25200750= 33.60 seconds

02

(b)Theoretical number of workstations

Thetheoretical number of workstationsis the ideal number of workstations, which can be found as follows:

number of workstations = Sum of task timesworkstations cycle time= 20 + 7 + 20 + 22 + 15 + 10 + 16 + 833.6= 11833.6= 3.51

03

(c) The Precedence Diagram

The precedence diagramis given below:

04

(d) Line balance using the largest operation time rule  


Hence, the number of workstationsis 5.

05

(e) Efficiency of the line balance

Aline balance’s efficiencyaddresses how productively the capacity is utilized. Efficiency =Sum of task timesNumber of ·É´Ç°ù°ì²õ³Ù²¹³Ù¾±´Ç²Ô²õװ´ǰù°ì²õ³Ù²¹³Ù¾±´Ç²Ô cycle time=1185×33×60= 0.702= 70.2%

06

(f) Increase in demand

To adapt toincreased demand, a firm can either increase the functioning hours of each day or the number of workstations. With the increase in demand, workstations cycle time will be decreased as calculated below:

Workstation cycle time=Production time per dayDesired output per day=7×60×60800= 31.55 second= 32 seconds

Number of workstations=Sum of task timeCycle time=11832= 3.68 ≃ 4

Efficiency =Sum of task timesNumber of ·É´Ç°ù°ì²õ³Ù²¹³Ù¾±´Ç²Ô²õ× Workstation cycle time=1184×32= 0.921= 92.1%

By expanding this number to the closest higher whole number, we observe that the number of workstations ought to be 4. So no increment is expected in the number of workstations or working hours. The firm can produce expanded yield utilizing the unassigned time of present workstations. The cycle time will be diminished and the efficiency is expanded to 92.15 with 800 units each day.

07

(g) Reduction in Workstation cycle time

Workstation cycle timewill be reduced as

Workstation cycle time = Production time per dayDesired output per day=7×60×601000= 25.20 seconds

Number of workstations= Sum of task timeCycle time= 11825.20= 4.68 ≃ 5

Efficiency=Sum of task timesNumber of ·É´Ç°ù°ì²õ³Ù²¹³Ù¾±´Ç²Ô²õװ´ǰù°ì²õ³Ù²¹³Ù¾±´Ç²Ô cycle time=1185×25.2= 0.936= 93.6%

By expanding this number to the closest higher whole number, we observe that the number of workstations ought to be 5. On the off chance that this is beyond the realm of possibilities to expect to expand the number of workstations, working hours of the day ought to be expanded. New working hours ought to be8.7531.51×1000/60×60

So to adapt to the interest of 1000 units each day, either working hours ought to be expanded to 8.75 or another workstation ought to be added.

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