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The Goodparts Company produces a component that is subsequently used in the aerospace industry. The component consists of three parts (A, B, and C) that are purchased from outside and cost 40, 35, and 15 cents per piece, respectively. Parts A and B are assembled first on assembly line 1, which produces 140 components per hour. Part C undergoes a drilling operation before being finally assembled with the output from assembly line 1. There are in total six drilling machines, but at present only three of them are operational. Each drilling machine drills part C at a rate of 50 parts per hour. In the final assembly, the output from assembly line 1 is assembled with the drilled part C. The final assembly line produces at a rate of 160 components per hour. At present, components are produced eight hours a day and five days a week. Management believes that if need arises, it can add a second shift of eight hours for the assembly lines. The cost of assembly labor is 30 cents per part for each assembly line; the cost of drilling labor is 15 cents per part. For drilling, the cost of electricity is one cent per part. The total overhead cost has been calculated as \(1,200 per week. The depreciation cost for equipment has been calculated as \)30 per week.

a. Draw a process flow diagram and determine the process capacity (number of components produced per week) of the entire process.

b. Suppose a second shift of eight hours is run for assembly line 1 and the same is done for the final assembly line. In addition, four of the six drilling machines are made operational. The drilling machines, however, operate for just eight hours a day. What is the new process capacity (number of components produced per week)? Which of the three operations limits the capacity?

c. Management decides to run a second shift of eight hours for assembly line 1 plus a second shift of only four hours for the final assembly line. Five of the six drilling machines operate for eight hours a day. What is the new capacity? Which of the three operations limits the capacity?

d. Determine the cost per unit output for questions (b) and (c).

e. The product is sold at \(4.00 per unit. Assume that the cost of a drilling machine (fixed cost) is \)30,000 and the company produces 8,000 units per week. Assume that four drilling machines are used for production. If the company had an option to buy the same part at $3.00 per unit, what would be the break-even number of units?

Short Answer

Expert verified

a. 6400 units per week

b. 8000 units per week, drill machine

c. 9600 units per week, last assembly line

d. 1.81, 1.64

e. 100840 units

Step by step solution

01

Understanding the process capacity

Process capacity is the capacity of humans or machines for production.

02

Obtaining formula for process capacity

²Ñ²¹³¦³ó¾±²Ô±ð c²¹±è²¹³¦¾±³Ù²â =´Ç±è±ð°ù²¹³Ù¾±²Ô²µâ€‰h´Ç³Ü°ù²õ ״DZè±ð°ù²¹³Ù¾±²Ô²µâ€‰r²¹³Ù±ðײԳܳ¾²ú±ð°ù o´Ú″¾²¹³¦³ó¾±²Ô±ð²õ

03

Making a flow diagram for the entire process

04

 Step 4: Calculating the process capacity for the entire proces

°ä²¹±è²¹³¦¾±³Ù²â o´Ú‼î²õ²õ±ð³¾²ú±ô²â l¾±²Ô±ð 1=140 units/hr×8 hr/day×5 days/week=5,600 units/week

°ä²¹±è²¹³¦¾±³Ù o´Ú d°ù¾±±ô±ô″¾²¹³¦³ó¾±²Ô±ð²õ=3 drill machine×50 parts/hr×8hr/day×5 days/week=6,000 units/week

°ä²¹±è²¹³¦¾±³Ù²â o´Ú f¾±²Ô²¹±ô a²õ²õ±ð³¾²ú±ô²â l¾±²Ô±ð=160 units/hr×8 hr/day×5 days/week=6,400 units/week

05

Finding the capacity of the entire process and limiting capacity

The capacity of the process is always the bottleneck process and the limiting capacity. In the above case, the assemblyline is the bottleneck process and the limiting capacity.

Step 5: Calculating new process capacity

b.

°ä²¹±è²¹³¦¾±³Ù²â o´Ú a²õ²õ±ð³¾²ú±ô²â l¾±²Ô±ð 1=140 units/hr×16 hr/day×5 days/week=11,200 units/week

°ä²¹±è²¹³¦¾±³Ù²â o´Ú d°ù¾±±ô±ô″¾²¹³¦³ó¾±²Ô±ð²õ=4drill machines×50 parts/hr×8 hr/day×5 days/week=8,000 units/week

Capacity of final assembly=160 units/hr×16 hr/day×5 days/week=12,800 units/week

06

Analyzing which operation is limiting the capacity

The bottleneck is the capacity of the process and also the limiting capacity. In the case above,the capacity of the drill machine is the bottleneck.

07

Calculating new capacity for the changes made

c.°ä²¹±è²¹³¦¾±³Ù²â o´Ú a²õ²õ±ð³¾²ú±ô²â l¾±²Ô±ð 1=140 units/hr×16 hr/day×5 days/week=11,200 units/week

°ä²¹±è²¹³¦¾±³Ù²â o´Ú d°ù¾±±ô±ô″¾²¹³¦³ó¾±²Ô±ð=5 drill machines×50 parts/hr×8 hr/day×5 days/week=10,000 units/week

°ä²¹±è²¹³¦¾±³Ù²â o´Ú f¾±²Ô²¹±ô a²õ²õ±ð³¾²ú±ô²â=160 units/hr×12 hr/day×5 days/week=9,600 units/week

08

Analyzing the changed operation which is limiting the capacity

9,600 units per week is the capacity of the entire process, and the limiting capacity is the final assembly line.

09

Calculating the cost per unit output of b

d. Calculating the total cost per week when output is 8000

°ä´Ç²õ³Ù o´Ú p²¹°ù³Ù‼î=0.40×8000=$3,200

°ä´Ç²õ³Ù o´Ú p²¹°ù³Ù B=0.35×8000=$2,800

°ä´Ç²õ³Ù o´Ú p²¹°ù³Ù C=0.15×8,000=$1,200

Electricity=0.01×8,000=$80

³¢²¹²ú´Ç°ù c´Ç²õ³Ù o´Ú a²õ²õ±ð³¾²ú±ô²â 1=0.30×8,000=$2,400

³¢²¹²ú´Ç°ù c´Ç²õ³Ù o´Ú f¾±²Ô²¹±ô a²õ²õ±ð³¾²ú±ô²â=0.30×8,000=$2,400

°ä´Ç²õ³Ù o´Ú d°ù¾±±ô±ô¾±²Ô²µâ€‰l²¹²ú´Ç°ù=.15×8000=$1200

°¿±¹±ð°ù³ó±ð²¹»å c´Ç²õ³Ù=$1200 per week

Depreciation=$30 per week

Total=$14,510

°ä´Ç²õ³Ù p±ð°ù u²Ô¾±³Ù=°Õ´Ç³Ù²¹±ô c´Ç²õ³Ù p±ð°ù w±ð±ð°ì±·³Ü³¾²ú±ð°ù o´Ú u²Ô¾±³Ù²õ p°ù´Ç»å³Ü±ð»å p±ð°ù w±ð±ð°ì=$14,5108,000=$1.81

10

Calculating the cost per unit output of c

Calculating total cost per week when output is 9600 units

°ä´Ç²õ³Ù o´Ú p²¹°ù³Ù‼î=0.40×9,600=$3,840

°ä´Ç²õ³Ù o´Ú p²¹°ù³Ù B=0.35×9,600=$3,360

°ä´Ç²õ³Ù o´Ú p²¹°ù³Ù C=0.15×9,600=$1,440

·¡±ô±ð³¦³Ù°ù¾±³¦¾±³Ù²â c´Ç²õ³Ù=0.01×9,600=$96

³¢²¹²ú´Ç°ù c´Ç²õ³Ù o´Ú a²õ²õ±ð³¾²ú±ô²â 1=0.30×9,600=$2,880

°ä´Ç²õ³Ù o´Ú d°ù¾±±ô±ô¾±²Ô²µâ€‰l²¹²ú´Ç°ù=0.30×9,600=$2,880

°¿±¹±ð°ù³ó±ð²¹»å c´Ç²õ³Ù=$1200per week

Depriciation=$30 per week

Total=$15,726

°ä´Ç²õ³Ù p±ð°ù u²Ô¾±³Ù=°Õ´Ç³Ù²¹±ô c´Ç²õ³Ù p±ð°ù w±ð±ð°ì±·³Ü³¾²ú±ð°ù o´Ú u²Ô¾±³Ù²õ p°ù´Ç»å³Ü³¦±ð»å p±ð°ù w±ð±ð°ì=$15,7269,600=$1.64

11

Calculating the break-even number of units

e. Let the number of units to be produced by each option bex

The cost of buying the units is $3 per unit =3x

When they manufacture, they incur a fixed cost of $120,000 and a cost per unit of1.81x

Forming them into the equation

3x=120,000+1.81x3x−1.81x=120,0001.19x=120,000x=120,0001.19x=100,840 units

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Most popular questions from this chapter

The desired daily output for an assembly line is 360 units. This assembly line will operate for 450 minutes per day. The following table contains information on this product’s task times and precedence relationships:

TASK

Task Time (Seconds)

Immediate Predecessor

A

30

-

B

35

A

C

30

A

D

35

B

E

15

C

F

65

C

G

40

E, F

h

25

D, G

a. Draw the precedence diagram.

b. What is the workstation cycle time required to produce 360 units per day?

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d. What is the efficiency of your line balance, assuming it is running at the cycle time from part (b)?

An initial solution has been given to the following work center layout problem. Given the flows described and a cost of $2.00 per unit per foot, compute the total cost for the layout. Each location is 100 feet long and 50 feet wide as shown in the following figure. Use the centers of departments for distances and measure distance using metropolitan rectilinear distance.

A toll tunnel has decided to experiment with the use of a debit card for the collection of tolls. Initially, only one lane will be used. Cars are estimated to arrive at this experimental lane at the rate of 750 per hour. It will take exactly four seconds to verify the debit card.

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Question: Calculate the average customer arrival rate and service rate per hour.

You are planning the new layout for the local branch of the Sixth Ninth Bank. You are considering separate cashier windows for the three different classes of service. Each class of service would be separate with its cashiers and customers. Oddly enough, each class of service, while different, has the same demand and service times. People for one class of service arrive every four minutes, and arrival times are exponentially distributed (The standard deviation is equal to the mean). It takes seven minutes to service each customer, and the standard deviation of the service times is three minutes. You assign two cashiers to each type of service.

  1. On average, how long will each line be at each of the cashier windows?
  2. On average, how long will a customer spend in the bank (assume they enter, go directly to one line, and leave as soon as service is complete)? You decide to consolidate all the cashiers so they can handle all types of customers without increasing the service times.
  3. What will happen to the amount of time each cashier spends idle? (Increase, decrease, stay the same, depend on ________)
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