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(a) At any instant, how many water molecules are ionized in 1 L of pure water at pH 7.0? (b) Express this number as a percentage of the total water molecules.

Short Answer

Expert verified

(a) The number of water molecules ionized is 6.0221016molecules.

(b) The percentage of water molecules ionized is 1.8107%.

Step by step solution

01

(a) Calculation of the number of water molecules ionized in 1L.

One out of every 107 water molecules is ionized by breaking up into hydrogen and hydroxide ions.

At a pH value of 7, the number of moles of water molecules that are ionized is 10-7.

Calculation of the number of molecules that are ionized:

Numberofmolecules=NumberofmolesAvogadro'sNumber

Substitute 10-7 for the number of moles and 6.022x1023 for Avogadro鈥檚 number.

Numberofmolecules=107moles6.0221023=6.0221016molecules.

Hence, the number of ionized molecules of water is6.0221016molecules.

02

(b) Calculation of the percentage of water molecules ionized to total molecules.

The mass of 1 L of water is equal to 1000 g. The molecular mass of water is 18 g.

Calculation of the number of moles of water:

Numberofmoles=MassofwaterMolecularmassofwater

Substitute 1000 g for the mass of water and 18 g for the molecular mass of water.

Numberofmoles=1000g18g=55.55mol

Calculation of the total number of molecules in 1L:

Numberofmolecules=NumberofmolesAvogadro'sNumber107

Substitute 55.55 mol for the number of moles and 6.022x1023.

Numberofmolecules=55.55moles6.0221023=3.341025molecules.

Calculation of the percentage of molecules ionized to total molecules:

Percentageofmoleculeionized=NumberofmoleculesionizedTotalnumberofmoleculesPercentageofmoleculeionised=6.0210163.341025100=1.8107

Hence, the percentage of water molecules ionized is 1.8107%.

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