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What enables RNA polymerase to start transcribing a gene at the right place on the DNA in a bacterial cell? In a eukaryotic cell?

Short Answer

Expert verified

In the prokaryotic cell, RNA polymerase binds to the promoter segment directly and initiates the process of transcription.

In a eukaryotic cell, transcription factors bind to the promoter region, followed by the binding of the RNA polymerase to the promoter region to initiate the transcription process.

Step by step solution

01

Description of RNA polymerase

RNA polymerase is the enzyme that synthesizes DNA from the RNA strand. It mediates the critical process in gene expression, such as transcription.

02

RNA polymerase binding in the bacterial cell

Bacteria are single-celled prokaryotic organisms. The transcription process occurs more simply in bacteria compared to eukaryotes.

The RNA polymerase enzyme recognizes the promoter region directly and binds to it to begin the transcription process. There is no requirement for transcription factors in the prokaryotic cells.

03

RNA polymerase binding in the eukaryotic cell

Eukaryotic cells have complex organization compared to prokaryotic cells.The transcription factors are the assisting elements that facilitate the binding of the RNA polymerase with the promoter sequence. In this process, there is no direct binding involved.

The transcription factors have eligibility to control the rate of the transcription process.

Hence, the RNA polymerase itself searches for the promoters and binds to them in the case of the bacterial cell. In the eukaryotic cell, the transcription factors enable the binding of the promoter with the RNA polymerase.

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Most popular questions from this chapter

Which of the following is not true of a codon?

  1. It may code for the same amino acid as another codon.

  2. It never codes for more than one amino acid.

  3. It extends from one end of a tRNA molecule

  4. It is the basic unit of the genetic code.

Using Figure 17.6, identify a 5’– 3’ sequence of nucleotides in the DNA template strand for an mRNA coding for the polypeptide sequence Phe-Pro-Lys.

(A) 5’-UUUCCCAAA-3’

(B) 5’-GAACCCCTT-3’

(C) 5’-CTTCGGGAA-3’

(D) 5’-AAACCCUUU-3’

In eukaryotic cells, transcription cannot begin until

  1. the two DNA strands have completely separated and exposed the promoter.

  2. several transcription factors have bound to the promoter.

  3. the 5’caps are removed from the mRNA

  4. the DNA introns are removed from the mRNA.

Which of the following mutations would be most likely to have a harmful effect on an organism?

  1. a deletion of three nucleotides near the middle of a gene

  2. a single nucleotide deletion in the middle of an intron

  3. a single nucleotide deletion near the end of the coding sequence

  4. a single nucleotide insertion downstream of, and close to, the start of the coding sequence.

In the sequence logo (bottom, left), the horizontal axis shows the primary sequence of the DNA by nucleotide position. Letters for each base are stacked on top of each other according to their relative frequency at that position among the aligned sequences, with the most common base as largest letter at the top of the stack. The height of each letter represents the relative frequency of that base at that position. (a) In the sequence alignment, count the number of each base at position-9 and order them from the most to least frequent. Compare this to the size and placement of each base -9 in the logo. (b) Do the same for position 0 and 1.

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